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From: Leon on 16 Mar 2010 17:11
integral (xe^(2x))/((2x+1)^2) BY PARTS
From: Bart Goddard on 16 Mar 2010 17:21
Leon <eduardoleonrodriguez(a)gmail.com> wrote in news:a6d89ea6-0081-4d28-
be3b-772915b634e5(a)l11g2000pro.googlegroups.com:

> integral (xe^(2x))/((2x+1)^2) BY PARTS
>

Correct.

B.

--
Cheerfully resisting change since 1959.
From: Arturo Magidin on 16 Mar 2010 17:19
On Mar 16, 4:11 pm, Leon <eduardoleonrodrig...(a)gmail.com> wrote:
> integral (xe^(2x))/((2x+1)^2)  BY PARTS

Homework BY YOURSELF
From: Gerry Myerson on 16 Mar 2010 17:53
In article
<a6d89ea6-0081-4d28-be3b-772915b634e5(a)l11g2000pro.googlegroups.com>,
Leon <eduardoleonrodriguez(a)gmail.com> wrote:

> integral (xe^(2x))/((2x+1)^2) BY PARTS

Actually, I think it was by Newton, who preceded Parts
by many years.

--
Gerry Myerson (gerry(a)maths.mq.edi.ai) (i -> u for email)
From: J. Clarke on 16 Mar 2010 18:41
On 3/16/2010 5:53 PM, Gerry Myerson wrote:
> In article
> <a6d89ea6-0081-4d28-be3b-772915b634e5(a)l11g2000pro.googlegroups.com>,
> Leon<eduardoleonrodriguez(a)gmail.com> wrote:
>
>> integral (xe^(2x))/((2x+1)^2) BY PARTS
>
> Actually, I think it was by Newton, who preceded Parts
> by many years.

Don't think so. Newton Senior's Parts preceded Newton by about 9 months.


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