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From: Richard L. Peterson on 6 Nov 2009 09:20 I'm sure it's well known but still: Let p be prime and C(n,k) be the usual binomial coefficient. Then C(np,kp) is congruent to C(n,k) mod p.
From: Richard L. Peterson on 29 Nov 2009 14:50
> I'm sure it's well known but still: Let p be > prime and C(n,k) be the usual binomial coefficient. > Then C(np,kp) is congruent to C(n,k) mod p. This turns out to be a weakened statemant of Wolstenholme's theorem, with "mod p" where [mod p^3] could have been correctly placed. |