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From: Andy on 20 Jul 2010 10:30
"Roberto " <ivogrunn(a)hotmail.com> wrote in message <i24b8p$6v9$1(a)fred.mathworks.com>...
> "Andy " <myfakeemailaddress(a)gmail.com> wrote in message <i24am0$q1a$1(a)fred.mathworks.com>...
> > But you still didn't answer an important question. You have given:
> >
> > A = [99;201;333;394;501];
> > B = {'333';'501';'629'};
> >
> > Should the elements 333 and 501 in A match the elements '333' and '501' in B? Note: these are doubles in A, but they are strings in B.
>
> Yes, indeed! The outcome of the 'check' would be:
> matching elements: 333 and 501
> non-matching elements: 99, 201 and 394

Okay, try this:

A = [99;201;333;394;501];
B = {'333';'501';'629'};
B=cellfun(@(x) str2double(x),B);
[C,IA,IB] = intersect(A,B);
A(IA)=[];
B(IB)=[];

Notes: after running this, C holds the common values, A holds the values only in A, and B holds the values only in B. (If you don't want to alter A and B, make a copy of them and alter the copy.) Note that this converts B into a numeric array, and converts the strings to doubles. I don't know how slow this might be for that size input. Also, if the cell array B contains things other than strings that can be str2double'd, then cellfun might not be happy.
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