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From: Roberto on 20 Jul 2010 09:19
I have two variables (let's say A and B).
A = [99;201;333;394;501] *(5x1 double)
B = {'333';'501';'629'}; *(3x1 cell)

I need to know if the values in A are also in B and use that in an if/then/else statement. Something like this:
if (%/a value in A is also in B\)
'do this'
else (%/which means that a value in A is not in B\)
'do that'
end

I've tried a lot with findstr, compare, num2cell, char, etc etc etc. But I didn't find the right way...
Could anyone fix it for me?

TNX a lot!


From: Andy on 20 Jul 2010 09:29
"Roberto " <ivogrunn(a)hotmail.com> wrote in message <i247o8$ecm$1(a)fred.mathworks.com>...
> I have two variables (let's say A and B).
> A = [99;201;333;394;501] *(5x1 double)
> B = {'333';'501';'629'}; *(3x1 cell)
>
> I need to know if the values in A are also in B and use that in an if/then/else statement. Something like this:
> if (%/a value in A is also in B\)
> 'do this'
> else (%/which means that a value in A is not in B\)
> 'do that'
> end
>
> I've tried a lot with findstr, compare, num2cell, char, etc etc etc. But I didn't find the right way...
> Could anyone fix it for me?
>
> TNX a lot!
>
>

This question is not well posed. Are you iterating over the elements of A? If not, do you want to return true if any element of A is also in B, or if all elements of A are also in B, or if a certain element in A is also in B? For the purposes of looking for an element in B, do you care that it might be a number in A and a string in B?
From: Roberto on 20 Jul 2010 09:57
"Andy " <myfakeemailaddress(a)gmail.com> wrote in message <i248bi$n9m$1(a)fred.mathworks.com>...
> "Roberto " <ivogrunn(a)hotmail.com> wrote in message <i247o8$ecm$1(a)fred.mathworks.com>...
> > I have two variables (let's say A and B).
> > A = [99;201;333;394;501] *(5x1 double)
> > B = {'333';'501';'629'}; *(3x1 cell)
> >
> > I need to know if the values in A are also in B and use that in an if/then/else statement. Something like this:
> > if (%/a value in A is also in B\)
> > 'do this'
> > else (%/which means that a value in A is not in B\)
> > 'do that'
> > end
> >
> > I've tried a lot with findstr, compare, num2cell, char, etc etc etc. But I didn't find the right way...
> > Could anyone fix it for me?
> >
> > TNX a lot!
> >
> >
>
> This question is not well posed. Are you iterating over the elements of A? If not, do you want to return true if any element of A is also in B, or if all elements of A are also in B, or if a certain element in A is also in B? For the purposes of looking for an element in B, do you care that it might be a number in A and a string in B?

Right, my matlab-skills aren't that good, so I hope my answer will be clear enough (otherwise: give me a call!).
For all elements in A that are also in B, I have to do the same calculation (I don't think it's necessary to explain that calculation right here). And for all elements in A that aren't in B, I have to do another calculation. When I've done that, my simulation continues and (because of a while loop), variables A and B are renewed and I have to do the check them again.
I think the best outcome should be two variables; one with the elements that are in A and B, and one variable with the elements that are in A only. For further calculations it would be preferable that the two variables are double.

Extra info: the variables A and B contain almost 500 elements each, so speed is an important factor ;)

Hopefully it's clear now...
From: Andy on 20 Jul 2010 10:09
But you still didn't answer an important question. You have given:

A = [99;201;333;394;501];
B = {'333';'501';'629'};

Should the elements 333 and 501 in A match the elements '333' and '501' in B? Note: these are doubles in A, but they are strings in B.
From: Roberto on 20 Jul 2010 10:19
"Andy " <myfakeemailaddress(a)gmail.com> wrote in message <i24am0$q1a$1(a)fred.mathworks.com>...
> But you still didn't answer an important question. You have given:
>
> A = [99;201;333;394;501];
> B = {'333';'501';'629'};
>
> Should the elements 333 and 501 in A match the elements '333' and '501' in B? Note: these are doubles in A, but they are strings in B.

Yes, indeed! The outcome of the 'check' would be:
matching elements: 333 and 501
non-matching elements: 99, 201 and 394
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