From: Pubkeybreaker on
On May 7, 7:20 am, "Achava Nakhash, the Loving Snake"
<ach...(a)hotmail.com> wrote:
> On May 6, 1:00 am, ThinkTank <ebigl...(a)gmail.com> wrote:
>
> > > yeah, that's the spirit.  the problem is,
> > > in developing a model of n-dimensional figurate
> > > numbers,

> It says nothing about one polygonal number being representable as a
> sum of 2 polyngonal numbers.  None of 3, 4, 5, 6, etc. are equal to 2,
> and the representation is of ALL INTEGERS and not of another figurate
> number.  Again, the connection with Fermat's Last Theorem eludes me is
> almost surely completely bogus.

Note also that the Fermat equation is an algebraic plane CURVE,
whereas
in talking about polygonal numbers, the OP is now talking about
varieties
on SURFACES --> A totally different problem.

And the OP is too ignorant to realize it.
From: ThinkTank on
> On May 4, 5:16 am, ThinkTank <ebigl...(a)gmail.com>
> wrote:
> > If Fermat's original proof of the Fermat Polygonal
> Number
> > Theorem has not yet been found, why are
> mathematicians so
> > quick to assume that Fermat did not have an
> extension to
> > that proof which may have led to the proof of
> Fermat's Last
> > Theorem? It seems to me the key to understanding
> FLT lies
> > in a simple inductive proof for Fermat's Polygonal
> Number
> > theorem.
>
> Why would this extend to Fermat's last theorem, when
> it is about lots
> of numbers of a certain type adding to any number,
> whereas Fermat's
> Last Theorem is about two numbers of ceratain types
> adding to another
> number of that same type? They are completely
> different issues, and I
> can't imagine how solving the one would shed any
> light on solving the
> other.

I'm not sure how you can say they are a completely
different issue. There are many similarities between the
two problems. Most notably, both are statements about
sums of n-symmetric shapes, where n>2. Stated
mathematically:

a^p + b^p = c^p

=> a + b == c (mod p)

is the p-symmetric reduction. Furthermore, notice that
Fermat's Last Theorem (FLT) is a statement about
inequality, whereas the Fermat Polygonal Number Theorem
(FPNT) is a statement about equality. So, it seems
reasonable that the inequality of FLT may be stated as
recurrence regarding the symmetry of hypercubes. Or,
perhaps, it may be used to set a lower bound on the
number of n-cubes needed to sum to an n-cube. However,
it seems to me that a simple proof to the Polygonal
Number Theorem must be quite spectacular, considering
that it has not been found yet.

> I mean, he worked on Pell's equation too, so
> why not an
> inductive extension of that? Or anything else? It
> makes no sense.
>
>
> Regards,
> Achava
From: Pubkeybreaker on
On May 7, 8:50 am, ThinkTank <ebigl...(a)gmail.com> wrote:
> > On May 4, 5:16 am, ThinkTank <ebigl...(a)gmail.com>
> > wrote:
> I'm not sure how you can say they are a completely
> different issue.  There are many similarities between the
> two problems.  Most notably, both are statements about
> sums of n-symmetric shapes,

If you don't know the difference between a curve and a surface, I give
up.
You are so totally clueless about mathematics that you
are not even aware of the DEPTH of your ignorance.

However, in this particular instance, I will tell you the difference.

Varieties over SURFACES have many more 'degrees of freedom' than
varieties over curves. A^4 = B^4 + C^4 + D^4 *HAS* solutions.
Infinitely many.

They are different problems.

From: ThinkTank on
> On May 7, 8:50 am, ThinkTank <ebigl...(a)gmail.com>
> wrote:
> > > On May 4, 5:16 am, ThinkTank <ebigl...(a)gmail.com>
> > > wrote:
> > I'm not sure how you can say they are a completely
> > different issue.  There are many similarities
> between the
> > two problems.  Most notably, both are statements
> about
> > sums of n-symmetric shapes,
>
> If you don't know the difference between a curve and
> a surface, I give
> up.
> You are so totally clueless about mathematics that
> you
> are not even aware of the DEPTH of your ignorance.
>

Do you NOT understand the concept of VOLUME and figurate
numbers??? You are so totally clueless about mathematics
that you are not even aware of the VOLUME of your
ignorance. I will tell you the same thing I told Gerry.
I go by the Golden Rule. If you want to throw around
meaningless Ad Hominems, and waste my time, I will be
MORE than happy to reciprocate. And, if you then
continue, I will ignore you. Both you and Gerry need to
GROW UP. I expect MUCH MORE from people who claim to be
educated. Were you guys denied your tenure or
something??? You've both got anger issues you need to
deal with.

> However, in this particular instance, I will tell you
> the difference.
>
> Varieties over SURFACES have many more 'degrees of
> freedom' than
> varieties over curves. A^4 = B^4 + C^4 + D^4
> *HAS* solutions.
> Infinitely many.
>
> They are different problems.
>
From: ThinkTank on
> On May 7, 6:26 am, ThinkTank <ebigl...(a)gmail.com>
> wrote:
> > > In article
> > >
> <677236230.80457.1273132878888.JavaMail.r...(a)gallium.m
> > > athforum.org>,
> > >  ThinkTank <ebigl...(a)gmail.com> wrote:
> >
> > > > ""...an isomorphism between the integers and
> the
> > > reals..."
> >
> > > Thanks for removing any trace of doubt
> > > about your mathematical knowledge.
> >
> > And you, Gerry, have proven that you do not READ
> the
> > posts. Besides that fact, I was speaking informally
> to
> > save time. Perhaps you have all the time in the
> world to
> > waste, but I do not.
>
> Gerry discerned the content of your posts quite
> clearly.

No, he did not, and apparently you don't READ either. He
did not quote me correctly.

> I stand with him. You are a crank, and you are
> mathematically
> clueless. Your claim of an

You have no evidence to support that claim. Your quote
is not even correct. You, Gerry and Tonio are grasping
at straws here. I have made absolutely NO mathematical
mistakes in ANY of my posts so far. NONE. Not ONE.
Until you, Gerry or Tonio can point out a contradiction
or mistake in my statements, you have no case.

>
> "> > > ""...an isomorphism between the integers and
> the
> > > reals...""
>
> make this a certainty.