From: rbwinn on
On 24 June, 07:24, PD <thedraperfam...(a)gmail.com> wrote:
> On Jun 23, 7:43 pm, rbwinn <rbwi...(a)gmail.com> wrote:
>
>
>
>
>
> > On 23 June, 06:59, PD <thedraperfam...(a)gmail.com> wrote:
>
> > > On Jun 22, 7:38 pm, rbwinn <rbwi...(a)gmail.com> wrote:
>
> > > > On 22 June, 13:59, PD <thedraperfam...(a)gmail.com> wrote:
>
> > > > > On Jun 21, 7:24 pm, rbwinn <rbwi...(a)gmail.com> wrote:
>
> > > > > > On Jun 21, 2:20 pm, PD <thedraperfam...(a)gmail.com> wrote:
>
> > > > > > > On Jun 17, 5:47 pm, rbwinn <rbwi...(a)gmail.com> wrote:
>
> > > > > > > > On Jun 17, 1:06 pm, PD <thedraperfam...(a)gmail.com> wrote:
>
> > > > > > > > > On Jun 13, 8:31 am, rbwinn <rbwi...(a)gmail.com> wrote:
>
> > > > > > > > > >                                    x'=x-vt
> > > > > > > > > >                                    y'=y
> > > > > > > > > >                                    z'=z
> > > > > > > > > >                                    t'=t
>
> > > > > > > > > >       Experiment shows that a clock in moving frame of reference S' is
> > > > > > > > > > slower than a clock in S which shows t.  According to theGalilean
> > > > > > > > > > transformation equations, that slower clock does not show t'.  Time on
> > > > > > > > > > the slower clock has to be represented by some other variable if the
> > > > > > > > > >Galileantransformation equations are to be used.  We call time on the
> > > > > > > > > > slow clock in S' by the variable n'.
> > > > > > > > > > We can calculate time on the slow clock from theGalilean
> > > > > > > > > > transformation equations because we know that it shows light to be
> > > > > > > > > > traveling at 300,000 km per second in S'.  Therefore, if
> > > > > > > > > >  |x'|=300,000 km/sec(n') and |x| =300,000km/sec(t), then
>
> > > > > > > > > >                         cn'=ct-vt
> > > > > > > > > >                         n'=t(1-v/c)
>
> > > > > > > > > >          We can now calculate orbits of satellites and planets without
> > > > > > > > > > the problems imposed by the Lorentz equations and their length
> > > > > > > > > > contraction.  For instance, the speed of earth in its orbit around the
> > > > > > > > > > sun is 29.8 km/sec.  While a second of time takes place on earth, a
> > > > > > > > > > longer time is taking place on the sun.
>
> > > > > > > > > >                             n'(earth)=t(sun)(1-v/c)
> > > > > > > > > >                             1 sec.=t(sun)(1-29.8/300,000)
> > > > > > > > > >                              t(sun)=1.0001 sec.
>
> > > > > > > > > >        Since the orbit of Mercury was the proof used to verify that
> > > > > > > > > > Einstein's equations were better than Newton's for gravitation, we
> > > > > > > > > > calculate how time on earth compares with time on Mercury.
>
> > > > > > > > > >                               n'Mercury=t(sun)(1-v(Mercury)/c)
> > > > > > > > > >                               n'(mercury)=1.0001sec(1-47.87 km/sec/
> > > > > > > > > > 300,000km/sec)
> > > > > > > > > >                               n'(Mercury)=.99994 sec
>
> > > > > > > > > >           So a second on a clock on earth is ..99994 sec on a clock on
> > > > > > > > > > Mercury.  The question now is where would this put the perihelion of
> > > > > > > > > > Mercury using Newton's equations?
>
> > > > > > > > > Amazing to see you back, Robert. Even more amazing to find that you've
> > > > > > > > > done a reset and started with the very same nonsense you've put out
> > > > > > > > > for years and years. I would have thought that you would have learned
> > > > > > > > > something.
>
> > > > > > > > > So you are claiming that for clocks A and B, where B is moving
> > > > > > > > > relative to A and runs slower than A, then A is measuring time (as
> > > > > > > > > denoted by the quantity t), but B is not measuring time (as denoted by
> > > > > > > > > the quantity t').
>
> > > > > > > > > The problem of course is that A is moving relative to B and runs
> > > > > > > > > slower than B. Your conclusion consistently would be that B is
> > > > > > > > > measuring time but A is not.
>
> > > > > > > > > Therefore, according to you, A is measuring time and not measuring
> > > > > > > > > time, and B is measuring time and not measuring time.
>
> > > > > > > > > PD
>
> > > > > > > > You are confusing measurement of time with transformation of
> > > > > > > > coordinates.  Time can be measured about any way imaginable.
> > > > > > > > Coordinates can be transformed only with t' and t.- Hide quoted text -
>
> > > > > > > A time coordinate is what is *measured* in that frame, Robert.. It
> > > > > > > really does help to know what the terms mean.
>
> > > > > > So how did you "measure" time, PD?  With an hourglass, with the sun,
> > > > > > with the moon, with a waterclock?  You must have done it some way.- Hide quoted text -
>
> > > > > It depends on what kind of precision I'm looking for, Robert.
> > > > > A wristwatch is fine for some things.
> > > > > A TDC is better for some other things.
>
> > > > > If you have a decent clock and you measure processes *at rest*
> > > > > relative to the clock, you'll find that there is a consistent result
> > > > > in most cases. If there are uncontrolled factors, this may affect the
> > > > > quality of your results.
>
> > > > > What is known, though, is if you measure the processes with a clock
> > > > > that is *moving* relative to the process, you may notice a shift in
> > > > > the duration of the process. The "may" depends on the sensitivity of
> > > > > your clock.
>
> > > > Well, scientists studying relativity seem to have about a million ways
> > > > to adjust results to get whatever answer they are trying to get.  With
> > > > regard to time, I have to say they have been flim-flamming the public
> > > > since Einstein gave them a way to do it in 1905.
>
> > > Well, here's the thing, Robert. The measurements are very
> > > straightforward. You measure distances with sticks with marks on them
> > > or with surveying instruments. You measure time with clocks. If you
> > > make those measurements, you find that they do exactly what Einstein
> > > says you'll see.
>
> > > Now, some people will look at what they see with their own eyes, and
> > > they'll say, "OK, I guess that shows I was wrong." Other people will
> > > regard the results with suspicion and say, "You've tricked me somehow..
> > > I don't know how you did it, but this can't be right. I don't trust
> > > you or any of your kind, and I'm sick and tired of people like you
> > > trying to pull the wool over my eyes."
>
> > > I think it's pretty clear what kind of person you are, Robert.
>
> > > >     You probably claim there have been great advances in science.  I
> > > > don't really see it.  To start their present flim-flam, they got
> > > > millions of dollars from the U.S government to construct a bomb during
> > > > World War II, which they ran up to 2 billion dollars by the end of the
> > > > war.  For that kind of money, they were happy to take one kind of
> > > > radioactive substance, put it into a cannon and shoot it into another
> > > > kind of radioactive substance.  Scientists all over the world had
> > > > speculated that this could be done even before the war started.
> > > >     So by doing this, they created the greatest man made explosion
> > > > witnessed up to that time, and it was all done by believing in a
> > > > length contraction.  So that proves to scientists that there is a
> > > > length contraction, especially when they can get trillions of more
> > > > dollars from governments by saying there is a length contraction.
> > > >     Scientists of today cannot explain the length contraction,
>
> > > Of course they can, and they've explained it tens of thousands of
> > > people to their satisfaction. Perhaps you meant to say that you've not
> > > had length contraction explained to you to your satisfaction. This
> > > doesn't surprise me, Robert, as you are not satisfied with just about
> > > everything.
>
> > > > but
> > > > their faith in it is absolute because it is the source of all good
> > > > things, (money), in their lives.
> > > >     All I have to do to provoke an outcry is to post in sci.physics
> > > > relativity that there is no length contraction, and scientists will
> > > > start screaming, Blasphemy, blasphemy.
>
> > > I think you confuse, Robert, scientists screaming blasphemy with
> > > scientists quietly chuckling and remarking that you're an idiot. I
> > > think you've puffed yourself up a little too much, thinking that
> > > you've had any gadfly influence at all. Even a street clown will
> > > attract a crowd, Robert; this doesn't mean that the street clown is
> > > anything other than a clown.
>
> > > >     Now here is something interesting.  TheGalileantransformation
> > > > equations do not show a length contraction.
>
> > > Of course they don't, Robert. That's one reason they're wrong. They
> > > disagree with what's actually measured.
>
> > They agree when I use them.  I just use t'=t in two frames of
> > reference, not to explain the entire universe.- Hide quoted text -
>
> They agree within the precision of the measurements you make. That's
> because theGalileantransformation are an excellent *approximation*
> to the real thing, especially at the low speeds that welders like to
> work with. As I told you before, Robert, feel free to use theGalilean
> transforms if they work for you and your needs. Physicists, on the
> other hand, sometimes work in domains where theGalileantransforms
> don't work well at all, because they don't always agree with
> measurments. It's in those cases that they're more careful, where
> you're happy to be simple and sloppy.
>
> PD

Well, I have noticed that with regard to people who subscribe to
disciplines. In any event, you may have noticed that I only apply the
Galilean transformation equations to two frames of reference at a
time. When I say t'=t, I am not talking about all clocks in the
universe, just to the two references to time that are measuring these
equations:

x'=x-vt
y'=y
z'=z
t'=t

Consequently, if I say that t' is time on a clock in S, the equations
are satisfied, regardless of what a clock running at a different rate
may say. As a scientist, you may not like this, but if so, prove it
wrong. Just complaining about an equation does not prove anything.
From: artful on
On Jun 25, 1:49 pm, rbwinn <rbwi...(a)gmail.com> wrote:
> On 23 June, 18:23, "Inertial" <relativ...(a)rest.com> wrote:
>
>
>
>
>
> > "rbwinn" <rbwi...(a)gmail.com> wrote in message
>
> >news:47bedc16-9823-469d-8c63-87bddcf10145(a)c10g2000yqi.googlegroups.com....
>
> > > On 23 June, 06:59, PD <thedraperfam...(a)gmail.com> wrote:
> > >> On Jun 22, 7:38 pm, rbwinn <rbwi...(a)gmail.com> wrote:
>
> > >> > On 22 June, 13:59, PD <thedraperfam...(a)gmail.com> wrote:
>
> > >> > > On Jun 21, 7:24 pm, rbwinn <rbwi...(a)gmail.com> wrote:
>
> > >> > > > On Jun 21, 2:20 pm, PD <thedraperfam...(a)gmail.com> wrote:
>
> > >> > > > > On Jun 17, 5:47 pm, rbwinn <rbwi...(a)gmail.com> wrote:
>
> > >> > > > > > On Jun 17, 1:06 pm, PD <thedraperfam...(a)gmail.com> wrote:
>
> > >> > > > > > > On Jun 13, 8:31 am, rbwinn <rbwi...(a)gmail.com> wrote:
>
> > >> > > > > > > >                                    x'=x-vt
> > >> > > > > > > >                                    y'=y
> > >> > > > > > > >                                    z'=z
> > >> > > > > > > >                                    t'=t
>
> > >> > > > > > > >       Experiment shows that a clock in moving frame of
> > >> > > > > > > > reference S' is
> > >> > > > > > > > slower than a clock in S which shows t.  According to
> > >> > > > > > > > theGalilean
> > >> > > > > > > > transformation equations, that slower clock does not show
> > >> > > > > > > > t'.  Time on
> > >> > > > > > > > the slower clock has to be represented by some other
> > >> > > > > > > > variable if the
> > >> > > > > > > >Galileantransformation equations are to be used.  We call
> > >> > > > > > > >time on the
> > >> > > > > > > > slow clock in S' by the variable n'.
> > >> > > > > > > > We can calculate time on the slow clock from theGalilean
> > >> > > > > > > > transformation equations because we know that it shows
> > >> > > > > > > > light to be
> > >> > > > > > > > traveling at 300,000 km per second in S'.  Therefore, if
> > >> > > > > > > >  |x'|=300,000 km/sec(n') and |x| =300,000km/sec(t), then
>
> > >> > > > > > > >                         cn'=ct-vt
> > >> > > > > > > >                         n'=t(1-v/c)
>
> > >> > > > > > > >          We can now calculate orbits of satellites and
> > >> > > > > > > > planets without
> > >> > > > > > > > the problems imposed by the Lorentz equations and their
> > >> > > > > > > > length
> > >> > > > > > > > contraction.  For instance, the speed of earth in its orbit
> > >> > > > > > > > around the
> > >> > > > > > > > sun is 29.8 km/sec.  While a second of time takes place on
> > >> > > > > > > > earth, a
> > >> > > > > > > > longer time is taking place on the sun.
>
> > >> > > > > > > >                             n'(earth)=t(sun)(1-v/c)
> > >> > > > > > > >                             1 sec.=t(sun)(1-29.8/300,000)
> > >> > > > > > > >                              t(sun)=1.0001 sec.
>
> > >> > > > > > > >        Since the orbit of Mercury was the proof used to
> > >> > > > > > > > verify that
> > >> > > > > > > > Einstein's equations were better than Newton's for
> > >> > > > > > > > gravitation, we
> > >> > > > > > > > calculate how time on earth compares with time on Mercury.
>
> > >> > > > > > > > n'Mercury=t(sun)(1-v(Mercury)/c)
> > >> > > > > > > >                               n'(mercury)=1.0001sec(1-47.87
> > >> > > > > > > > km/sec/
> > >> > > > > > > > 300,000km/sec)
> > >> > > > > > > >                               n'(Mercury)=.99994 sec
>
> > >> > > > > > > >           So a second on a clock on earth is .99994 sec on
> > >> > > > > > > > a clock on
> > >> > > > > > > > Mercury.  The question now is where would this put the
> > >> > > > > > > > perihelion of
> > >> > > > > > > > Mercury using Newton's equations?
>
> > >> > > > > > > Amazing to see you back, Robert. Even more amazing to find
> > >> > > > > > > that you've
> > >> > > > > > > done a reset and started with the very same nonsense you've
> > >> > > > > > > put out
> > >> > > > > > > for years and years. I would have thought that you would have
> > >> > > > > > > learned
> > >> > > > > > > something.
>
> > >> > > > > > > So you are claiming that for clocks A and B, where B is
> > >> > > > > > > moving
> > >> > > > > > > relative to A and runs slower than A, then A is measuring
> > >> > > > > > > time (as
> > >> > > > > > > denoted by the quantity t), but B is not measuring time (as
> > >> > > > > > > denoted by
> > >> > > > > > > the quantity t').
>
> > >> > > > > > > The problem of course is that A is moving relative to B and
> > >> > > > > > > runs
> > >> > > > > > > slower than B. Your conclusion consistently would be that B
> > >> > > > > > > is
> > >> > > > > > > measuring time but A is not.
>
> > >> > > > > > > Therefore, according to you, A is measuring time and not
> > >> > > > > > > measuring
> > >> > > > > > > time, and B is measuring time and not measuring time.
>
> > >> > > > > > > PD
>
> > >> > > > > > You are confusing measurement of time with transformation of
> > >> > > > > > coordinates.  Time can be measured about any way imaginable.
> > >> > > > > > Coordinates can be transformed only with t' and t.- Hide quoted
> > >> > > > > > text -
>
> > >> > > > > A time coordinate is what is *measured* in that frame, Robert. It
> > >> > > > > really does help to know what the terms mean.
>
> > >> > > > So how did you "measure" time, PD?  With an hourglass, with the
> > >> > > > sun,
> > >> > > > with the moon, with a waterclock?  You must have done it some way.-
> > >> > > > Hide quoted text -
>
> > >> > > It depends on what kind of precision I'm looking for, Robert.
> > >> > > A wristwatch is fine for some things.
> > >> > > A TDC is better for some other things.
>
> > >> > > If you have a decent clock and you measure processes *at rest*
> > >> > > relative to the clock, you'll find that there is a consistent result
> > >> > > in most cases. If there are uncontrolled factors, this may affect the
> > >> > > quality of your results.
>
> > >> > > What is known, though, is if you measure the processes with a clock
> > >> > > that is *moving* relative to the process, you may notice a shift in
> > >> > > the duration of the process. The "may" depends on the sensitivity of
> > >> > > your clock.
>
> > >> > Well, scientists studying relativity seem to have about a million ways
> > >> > to adjust results to get whatever answer they are trying to get.  With
> > >> > regard to time, I have to say they have been flim-flamming the public
> > >> > since Einstein gave them a way to do it in 1905.
>
> > >> Well, here's the thing, Robert. The measurements are very
> > >> straightforward. You measure distances with sticks with marks on them
> > >> or with surveying instruments. You measure time with clocks. If you
> > >> make those measurements, you find that they do exactly what Einstein
> > >> says you'll see.
>
> > >> Now, some people will look at what they see with their own eyes, and
> > >> they'll say, "OK, I guess that shows I was wrong." Other people will
> > >> regard the results with suspicion and say, "You've tricked me somehow.
> > >> I don't know how you did it, but this can't be right. I don't trust
> > >> you or any of your kind, and I'm sick and tired of people like you
> > >> trying to pull the wool over my eyes."
>
> > >> I think it's pretty clear what kind of person you are, Robert.
>
> > >> >     You probably claim there have been great advances in science.  I
> > >> > don't really see it.  To start their present flim-flam, they got
> > >> > millions of dollars from the U.S government to construct a bomb during
> > >> > World War II, which they ran up to 2 billion dollars by the end of the
> > >> > war.  For that kind of money, they were happy to take one kind of
> > >> > radioactive substance, put it into a cannon and shoot it into another
> > >> > kind of radioactive substance.  Scientists all over the world had
> > >> > speculated that this could be done even before the war started.
> > >> >     So by doing this, they created the greatest man made explosion
> > >> > witnessed up to that time, and it was all done by believing in a
> > >> > length contraction.  So that proves to scientists that there is a
> > >> > length contraction, especially when they can get trillions of more
> > >> > dollars from governments by saying there is a length contraction.
> > >> >     Scientists of today cannot explain the length contraction,
>
> > >> Of course they can, and they've explained it tens of thousands of
> > >> people to their satisfaction. Perhaps you meant to say that you've not
> > >> had length contraction explained to you to your satisfaction. This
> > >> doesn't surprise me, Robert, as you are not satisfied with just about
> > >> everything.
>
> > >> > but
> > >> > their faith in it is absolute because it is the source of all good
> > >> > things, (money), in their lives.
> > >> >     All I have to do to provoke an outcry is to post in sci.physics
> > >> > relativity that there is no length contraction, and scientists will
> > >> > start screaming, Blasphemy, blasphemy.
>
> > >> I think you confuse, Robert, scientists screaming blasphemy with
> > >> scientists quietly chuckling and remarking that you're an idiot. I
> > >> think you've puffed yourself up a little too much, thinking that
> > >> you've had any gadfly influence at all. Even a street clown will
> > >> attract a crowd, Robert; this doesn't mean that the street clown is
> > >> anything other than a clown.
>
> > >> >     Now here is something interesting.  TheGalileantransformation
> > >> > equations do not show a length contraction.
>
> > >> Of course they don't, Robert. That's one reason they're wrong. They
> > >> disagree with what's actually measured.
>
> > > They agree when I use them.
>
> > You don't use them .. you use a different transform.  You LIE when you say
> > you useGalileantransforms.  Basically you are nothing but a liar and a
> > fraud
>
> > >  I just use t'=t in two frames of
> > > reference, not to explain the entire universe.
>
> > So which frames does it NOT explain?
>
> Any frames that are not S and S'.

Then label those frames S and S' and it does. My god but you're
stupid
From: artful on
On Jun 25, 1:38 pm, rbwinn <rbwi...(a)gmail.com> wrote:
> On 23 June, 19:37, "Inertial" <relativ...(a)rest.com> wrote:
>
>
>
>
>
> > "rbwinn" <rbwi...(a)gmail.com> wrote in message
>
> >news:2b2812e0-ce59-41c7-bd7b-c9faaecd4eab(a)i28g2000yqa.googlegroups.com....
>
> > > On 23 June, 17:33, "Inertial" <relativ...(a)rest.com> wrote:
> > >> "rbwinn" <rbwi...(a)gmail.com> wrote in message
>
> > >>news:819687c3-593e-45a4-a705-0005da870e4e(a)z10g2000yqb.googlegroups.com...
>
> > >> > On 21 June, 18:11, "Inertial" <relativ...(a)rest.com> wrote:
> > >> >> "rbwinn" <rbwi...(a)gmail.com> wrote in message
>
> > >> >>news:88390667-78fc-43b3-a480-43b63b45f6b2(a)s6g2000prg.googlegroups.com...
>
> > >> >> > On Jun 21, 5:41 pm, "Inertial" <relativ...(a)rest.com> wrote:
> > >> >> >> "rbwinn" <rbwi...(a)gmail.com> wrote in message
>
> > >> >> >>news:c05160c7-0799-4d35-b874-08e17bd5c74e(a)40g2000pry.googlegroups.com...
>
> > >> >> >> > On Jun 21, 2:20 pm, PD <thedraperfam...(a)gmail.com> wrote:
> > >> >> >> >> On Jun 17, 5:47 pm, rbwinn <rbwi...(a)gmail.com> wrote:
>
> > >> >> >> >> > On Jun 17, 1:06 pm, PD <thedraperfam...(a)gmail.com> wrote:
>
> > >> >> >> >> > > On Jun 13, 8:31 am, rbwinn <rbwi...(a)gmail.com> wrote:
>
> > >> >> >> >> > > >                                    x'=x-vt
> > >> >> >> >> > > >                                    y'=y
> > >> >> >> >> > > >                                    z'=z
> > >> >> >> >> > > >                                    t'=t
>
> > >> >> >> >> > > >       Experiment shows that a clock in moving frame of
> > >> >> >> >> > > > reference
> > >> >> >> >> > > > S'
> > >> >> >> >> > > > is
> > >> >> >> >> > > > slower than a clock in S which shows t.  According to
> > >> >> >> >> > > > theGalilean
> > >> >> >> >> > > > transformation equations, that slower clock does not show
> > >> >> >> >> > > > t'.
> > >> >> >> >> > > > Time
> > >> >> >> >> > > > on
> > >> >> >> >> > > > the slower clock has to be represented by some other
> > >> >> >> >> > > > variable
> > >> >> >> >> > > > if
> > >> >> >> >> > > > the
> > >> >> >> >> > > >Galileantransformation equations are to be used.  We call
> > >> >> >> >> > > >time
> > >> >> >> >> > > >on
> > >> >> >> >> > > >the
> > >> >> >> >> > > > slow clock in S' by the variable n'.
> > >> >> >> >> > > > We can calculate time on the slow clock from theGalilean
> > >> >> >> >> > > > transformation equations because we know that it shows
> > >> >> >> >> > > > light
> > >> >> >> >> > > > to
> > >> >> >> >> > > > be
> > >> >> >> >> > > > traveling at 300,000 km per second in S'.  Therefore, if
> > >> >> >> >> > > >  |x'|=300,000 km/sec(n') and |x| =300,000km/sec(t), then
>
> > >> >> >> >> > > >                         cn'=ct-vt
> > >> >> >> >> > > >                         n'=t(1-v/c)
>
> > >> >> >> >> > > >          We can now calculate orbits of satellites and
> > >> >> >> >> > > > planets
> > >> >> >> >> > > > without
> > >> >> >> >> > > > the problems imposed by the Lorentz equations and their
> > >> >> >> >> > > > length
> > >> >> >> >> > > > contraction.  For instance, the speed of earth in its
> > >> >> >> >> > > > orbit
> > >> >> >> >> > > > around
> > >> >> >> >> > > > the
> > >> >> >> >> > > > sun is 29.8 km/sec.  While a second of time takes place on
> > >> >> >> >> > > > earth, a
> > >> >> >> >> > > > longer time is taking place on the sun.
>
> > >> >> >> >> > > >                             n'(earth)=t(sun)(1-v/c)
> > >> >> >> >> > > >                             1 sec.=t(sun)(1-29.8/300,000)
> > >> >> >> >> > > >                              t(sun)=1.0001 sec.
>
> > >> >> >> >> > > >        Since the orbit of Mercury was the proof used to
> > >> >> >> >> > > > verify
> > >> >> >> >> > > > that
> > >> >> >> >> > > > Einstein's equations were better than Newton's for
> > >> >> >> >> > > > gravitation,
> > >> >> >> >> > > > we
> > >> >> >> >> > > > calculate how time on earth compares with time on Mercury.
>
> > >> >> >> >> > > > n'Mercury=t(sun)(1-v(Mercury)/c)
>
> > >> >> >> >> > > > n'(mercury)=1.0001sec(1-47.87
> > >> >> >> >> > > > km/sec/
> > >> >> >> >> > > > 300,000km/sec)
> > >> >> >> >> > > >                               n'(Mercury)=.99994 sec
>
> > >> >> >> >> > > >           So a second on a clock on earth is .99994 sec on
> > >> >> >> >> > > > a
> > >> >> >> >> > > > clock
> > >> >> >> >> > > > on
> > >> >> >> >> > > > Mercury.  The question now is where would this put the
> > >> >> >> >> > > > perihelion
> > >> >> >> >> > > > of
> > >> >> >> >> > > > Mercury using Newton's equations?
>
> > >> >> >> >> > > Amazing to see you back, Robert. Even more amazing to find
> > >> >> >> >> > > that
> > >> >> >> >> > > you've
> > >> >> >> >> > > done a reset and started with the very same nonsense you've
> > >> >> >> >> > > put
> > >> >> >> >> > > out
> > >> >> >> >> > > for years and years. I would have thought that you would
> > >> >> >> >> > > have
> > >> >> >> >> > > learned
> > >> >> >> >> > > something.
>
> > >> >> >> >> > > So you are claiming that for clocks A and B, where B is
> > >> >> >> >> > > moving
> > >> >> >> >> > > relative to A and runs slower than A, then A is measuring
> > >> >> >> >> > > time
> > >> >> >> >> > > (as
> > >> >> >> >> > > denoted by the quantity t), but B is not measuring time (as
> > >> >> >> >> > > denoted
> > >> >> >> >> > > by
> > >> >> >> >> > > the quantity t').
>
> > >> >> >> >> > > The problem of course is that A is moving relative to B and
> > >> >> >> >> > > runs
> > >> >> >> >> > > slower than B. Your conclusion consistently would be that B
> > >> >> >> >> > > is
> > >> >> >> >> > > measuring time but A is not.
>
> > >> >> >> >> > > Therefore, according to you, A is measuring time and not
> > >> >> >> >> > > measuring
> > >> >> >> >> > > time, and B is measuring time and not measuring time.
>
> > >> >> >> >> > > PD
>
> > >> >> >> >> > You are confusing measurement of time with transformation of
> > >> >> >> >> > coordinates.  Time can be measured about any way imaginable.
> > >> >> >> >> > Coordinates can be transformed only with t' and t.- Hide
> > >> >> >> >> > quoted
> > >> >> >> >> > text -
>
> > >> >> >> >> A time coordinate is what is *measured* in that frame, Robert.
> > >> >> >> >> It
> > >> >> >> >> really does help to know what the terms mean.
>
> > >> >> >> > So how did you "measure" time, PD?  With an hourglass, with the
> > >> >> >> > sun,
> > >> >> >> > with the moon, with a waterclock?  You must have done it some
> > >> >> >> > way.
>
> > >> >> >> We call the thing you measure time with a 'clock'.  It is implied
> > >> >> >> (in
> > >> >> >> physics) when we talk about a general 'clock' that it is a
> > >> >> >> correctly
> > >> >> >> working
> > >> >> >> 'clock' .. ie that it correctly measures (or marks) the time at its
> > >> >> >> own
> > >> >> >> location in its own rest frame.  so if a duration dt of time at a
> > >> >> >> location
> > >> >> >> has elapsed, then a clock at that location will show a duration of
> > >> >> >> exactly
> > >> >> >> dt as well.
>
> > >> >> >> This is very very simple and basic stuff.
>
> > >> >> > Uh huh.  So what about the marks on S and S'?  They are not a clock
> > >> >> > any more?  That did not last long.
>
> > >> >> I said nothing about those marks.  You havea great deal of trouble
> > >> >> reading
> > >> >> and understanding .. that explains a lot.
>
> > >> >> However .. on the subject of such marks .. marks alone are not a clock
> > >> >> (they
> > >> >> are a ruler) .. you would also need something moving past those marks
> > >> >> at
> > >> >> a
> > >> >> known rate, from that you can calculate the time.  If you have
> > >> >> correctly
> > >> >> measured distances between the marks (ie measured from a
> > >> >> mutually-at-rest
> > >> >> observer .. ie the marks are not moving wrt the observer) and have
> > >> >> correctly
> > >> >> measured the speed of the moving object, then clock will work and be
> > >> >> correct.
>
> > >> >> This does NOT change the fact thegalileantransforms are proven
> > >> >> incorrect
> > >> >> by experiments that show correctly working clocks do NOT show the same
> > >> >> time
> > >> >> when those clocks are in relative motion.
>
> > >> > Well, theGalileantransformation equations I use are not proven
> > >> > incorrect.
>
> > >> Yes .. they are.
>
> > >> >  They account for the difference in rate of time between a
> > >> > clock in S and A clock in S'.
>
> > >> No .. they don't.  If they DO then they are NOTGalileantransforms.  How
> > >> about a bit of honesty from you here .. and admit you are using a
> > >> different
> > >> transform togalilean.
>
> > > Well, show the difference between these equations and theGalilean
> > > transformation equations.
>
> > >                  x'=x-vt
> > >                  y'=y
> > >                  z'=z
> > >                  t'=t
>
> > They are not the ones you use.  You post them .. but you don't use them.
> > You use your own equaition instead and then try to cheat by using a
> > different letter for time (n instead of t).
>
> It is called algebra.

I know what algebra is

[snip bullshit from rbwinn]

Nothing left
From: artful on
On Jun 25, 1:46 pm, rbwinn <rbwi...(a)gmail.com> wrote:
> On 23 June, 19:40, "Inertial" <relativ...(a)rest.com> wrote:
>
> > "rbwinn" <rbwi...(a)gmail.com> wrote in message
>
> >news:3de79bbe-3e03-4adf-a4f9-e425dfa8754e(a)b35g2000yqi.googlegroups.com....
>
> > > On 23 June, 18:21, "Inertial" <relativ...(a)rest.com> wrote:
> > >> "rbwinn" <rbwi...(a)gmail.com> wrote in message
>
> > >>news:bdf2fac8-9ead-4341-b213-bcaba14a5541(a)r27g2000yqb.googlegroups.com...
>
> > >> > On 22 June, 21:36, "whoever" <whoe...(a)whereever.com> wrote:
> > >> >> "rbwinn" <rbwi...(a)gmail.com> wrote in message
>
> > >> >>news:af6283d7-12a6-418b-9863-4e68e773fcd0(a)i31g2000yqm.googlegroups..com...
>
> > >> >> > On Jun 22, 6:18 pm, "Inertial" <relativ...(a)rest.com> wrote:
> > >> >> >> "rbwinn" <rbwi...(a)gmail.com> wrote in message
>
> > >> >> >>news:e430c702-c02c-4b28-ba75-14d58df5ee75(a)k39g2000yqd.googlegroups.com...
>
> > >> >> >> > On 22 June, 13:59, PD <thedraperfam...(a)gmail.com> wrote:
> > >> >> >> >> On Jun 21, 7:24 pm, rbwinn <rbwi...(a)gmail.com> wrote:
>
> > >> >> >> >> > On Jun 21, 2:20 pm, PD <thedraperfam...(a)gmail.com> wrote:
>
> > >> >> >> >> > > On Jun 17, 5:47 pm, rbwinn <rbwi...(a)gmail.com> wrote:
>
> > >> >> >> >> > > > On Jun 17, 1:06 pm, PD <thedraperfam...(a)gmail.com> wrote:
>
> > >> >> >> >> > > > > On Jun 13, 8:31 am, rbwinn <rbwi...(a)gmail.com> wrote:
>
> > >> >> >> >> > > > > >                                    x'=x-vt
> > >> >> >> >> > > > > >                                    y'=y
> > >> >> >> >> > > > > >                                    z'=z
> > >> >> >> >> > > > > >                                    t'=t
>
> > >> >> >> >> > > > > >       Experiment shows that a clock in moving frame of
> > >> >> >> >> > > > > > reference S' is
> > >> >> >> >> > > > > > slower than a clock in S which shows t.  According to
> > >> >> >> >> > > > > > theGalilean
> > >> >> >> >> > > > > > transformation equations, that slower clock does not
> > >> >> >> >> > > > > > show
> > >> >> >> >> > > > > > t'.
> > >> >> >> >> > > > > > Time on
> > >> >> >> >> > > > > > the slower clock has to be represented by some other
> > >> >> >> >> > > > > > variable
> > >> >> >> >> > > > > > if the
> > >> >> >> >> > > > > >Galileantransformation equations are to be used.  We
> > >> >> >> >> > > > > >call
> > >> >> >> >> > > > > >time
> > >> >> >> >> > > > > >on the
> > >> >> >> >> > > > > > slow clock in S' by the variable n'.
> > >> >> >> >> > > > > > We can calculate time on the slow clock from
> > >> >> >> >> > > > > > theGalilean
> > >> >> >> >> > > > > > transformation equations because we know that it shows
> > >> >> >> >> > > > > > light
> > >> >> >> >> > > > > > to
> > >> >> >> >> > > > > > be
> > >> >> >> >> > > > > > traveling at 300,000 km per second in S'.  Therefore,
> > >> >> >> >> > > > > > if
> > >> >> >> >> > > > > >  |x'|=300,000 km/sec(n') and |x| =300,000km/sec(t),
> > >> >> >> >> > > > > > then
>
> > >> >> >> >> > > > > >                         cn'=ct-vt
> > >> >> >> >> > > > > >                         n'=t(1-v/c)
>
> > >> >> >> >> > > > > >          We can now calculate orbits of satellites and
> > >> >> >> >> > > > > > planets
> > >> >> >> >> > > > > > without
> > >> >> >> >> > > > > > the problems imposed by the Lorentz equations and
> > >> >> >> >> > > > > > their
> > >> >> >> >> > > > > > length
> > >> >> >> >> > > > > > contraction.  For instance, the speed of earth in its
> > >> >> >> >> > > > > > orbit
> > >> >> >> >> > > > > > around the
> > >> >> >> >> > > > > > sun is 29.8 km/sec.  While a second of time takes
> > >> >> >> >> > > > > > place
> > >> >> >> >> > > > > > on
> > >> >> >> >> > > > > > earth, a
> > >> >> >> >> > > > > > longer time is taking place on the sun.
>
> > >> >> >> >> > > > > >                             n'(earth)=t(sun)(1-v/c)
> > >> >> >> >> > > > > >                             1
> > >> >> >> >> > > > > > sec.=t(sun)(1-29.8/300,000)
> > >> >> >> >> > > > > >                              t(sun)=1.0001 sec.
>
> > >> >> >> >> > > > > >        Since the orbit of Mercury was the proof used
> > >> >> >> >> > > > > > to
> > >> >> >> >> > > > > > verify
> > >> >> >> >> > > > > > that
> > >> >> >> >> > > > > > Einstein's equations were better than Newton's for
> > >> >> >> >> > > > > > gravitation,
> > >> >> >> >> > > > > > we
> > >> >> >> >> > > > > > calculate how time on earth compares with time on
> > >> >> >> >> > > > > > Mercury.
>
> > >> >> >> >> > > > > > n'Mercury=t(sun)(1-v(Mercury)/c)
>
> > >> >> >> >> > > > > > n'(mercury)=1.0001sec(1-47.87
> > >> >> >> >> > > > > > km/sec/
> > >> >> >> >> > > > > > 300,000km/sec)
> > >> >> >> >> > > > > >                               n'(Mercury)=.99994 sec
>
> > >> >> >> >> > > > > >           So a second on a clock on earth is .99994
> > >> >> >> >> > > > > > sec
> > >> >> >> >> > > > > > on a
> > >> >> >> >> > > > > > clock on
> > >> >> >> >> > > > > > Mercury.  The question now is where would this put the
> > >> >> >> >> > > > > > perihelion of
> > >> >> >> >> > > > > > Mercury using Newton's equations?
>
> > >> >> >> >> > > > > Amazing to see you back, Robert. Even more amazing to
> > >> >> >> >> > > > > find
> > >> >> >> >> > > > > that
> > >> >> >> >> > > > > you've
> > >> >> >> >> > > > > done a reset and started with the very same nonsense
> > >> >> >> >> > > > > you've
> > >> >> >> >> > > > > put
> > >> >> >> >> > > > > out
> > >> >> >> >> > > > > for years and years. I would have thought that you would
> > >> >> >> >> > > > > have
> > >> >> >> >> > > > > learned
> > >> >> >> >> > > > > something.
>
> > >> >> >> >> > > > > So you are claiming that for clocks A and B, where B is
> > >> >> >> >> > > > > moving
> > >> >> >> >> > > > > relative to A and runs slower than A, then A is
> > >> >> >> >> > > > > measuring
> > >> >> >> >> > > > > time
> > >> >> >> >> > > > > (as
> > >> >> >> >> > > > > denoted by the quantity t), but B is not measuring time
> > >> >> >> >> > > > > (as
> > >> >> >> >> > > > > denoted by
> > >> >> >> >> > > > > the quantity t').
>
> > >> >> >> >> > > > > The problem of course is that A is moving relative to B
> > >> >> >> >> > > > > and
> > >> >> >> >> > > > > runs
> > >> >> >> >> > > > > slower than B. Your conclusion consistently would be
> > >> >> >> >> > > > > that B
> > >> >> >> >> > > > > is
> > >> >> >> >> > > > > measuring time but A is not.
>
> > >> >> >> >> > > > > Therefore, according to you, A is measuring time and not
> > >> >> >> >> > > > > measuring
> > >> >> >> >> > > > > time, and B is measuring time and not measuring time.
>
> > >> >> >> >> > > > > PD
>
> > >> >> >> >> > > > You are confusing measurement of time with transformation
> > >> >> >> >> > > > of
> > >> >> >> >> > > > coordinates.  Time can be measured about any way
> > >> >> >> >> > > > imaginable.
> > >> >> >> >> > > > Coordinates can be transformed only with t' and t.- Hide
> > >> >> >> >> > > > quoted
> > >> >> >> >> > > > text -
>
> > >> >> >> >> > > A time coordinate is what is *measured* in that frame,
> > >> >> >> >> > > Robert.
> > >> >> >> >> > > It
> > >> >> >> >> > > really does help to know what the terms mean.
>
> > >> >> >> >> > So how did you "measure" time, PD?  With an hourglass, with
> > >> >> >> >> > the
> > >> >> >> >> > sun,
> > >> >> >> >> > with the moon, with a waterclock?  You must have done it some
> > >> >> >> >> > way.-
> > >> >> >> >> > Hide quoted text -
>
> > >> >> >> >> It depends on what kind of precision I'm looking for, Robert.
> > >> >> >> >> A wristwatch is fine for some things.
> > >> >> >> >> A TDC is better for some other things.
>
> > >> >> >> >> If you have a decent clock and you measure processes *at rest*
> > >> >> >> >> relative to the clock, you'll find that there is a consistent
> > >> >> >> >> result
> > >> >> >> >> in most cases. If there are uncontrolled factors, this may
> > >> >> >> >> affect
> > >> >> >> >> the
> > >> >> >> >> quality of your results.
>
> > >> >> >> >> What is known, though, is if you measure the processes with a
> > >> >> >> >> clock
> > >> >> >> >> that is *moving* relative to the process, you may notice a shift
> > >> >> >> >> in
> > >> >> >> >> the duration of the process. The "may" depends on the
> > >> >> >> >> sensitivity
> > >> >> >> >> of
> > >> >> >> >> your clock.
>
> > >> >> >> > Well, scientists studying relativity seem to have about a million
> > >> >> >> > ways
> > >> >> >> > to adjust results to get whatever answer they are trying to get.
>
> > >> >> >> Wrong
>
> > >> >> >> >  With
> > >> >> >> > regard to time, I have to say they have been flim-flamming the
> > >> >> >> > public
> > >> >> >> > since Einstein gave them a way to do it in 1905.
>
> > >> >> >> Wrong
>
> > >> >> >> >    You probably claim there have been great advances in science.
> > >> >> >> > I
> > >> >> >> > don't really see it.
>
> > >> >> >> That you don't see something is not a surprise
>
> > >> >> >> [snip irrelevant nonsense]
>
> > >> >> >> >    Scientists of today cannot explain the length contraction,
>
> > >> >> >> Wrong
>
> > >> >> >> > but
> > >> >> >> > their faith in it is absolute because it is the source of all
> > >> >> >> > good
> > >> >> >> > things, (money), in their lives.
>
> > >> >> >> Wrong
>
> > >> >> >> >    All I have to do to provoke an outcry is to post in
> > >> >> >> > sci.physics
> > >> >> >> > relativity that there is no length contraction, and scientists
> > >> >> >> > will
> > >> >> >> > start screaming, Blasphemy, blasphemy.
>
> > >> >> >> No .. they'll just tell you that your logic is wrong.  What you
> > >> >> >> claim
> > >> >> >> to
> > >> >> >> be
> > >> >> >> the case is refuted by experimental evidence.  It is simply wrong
>
> > >> >> >> >    Now here is something interesting.  TheGalileantransformation
> > >> >> >> > equations do not show a length contraction.
>
> > >> >> >> More to the point, they do NOT show time dilation .. and we observe
> > >> >> >> that
> > >> >> >> happening.  So they are wrong.
>
> > >> >> >> You are flogging a dead horse. . and have been for years
>
> > >> >> > Well, I do not flog horses.  I don't need to.  Generally, I walk
> > >> >> > wherever I go.  One thing is obvious to me, scientists are
> > >> >> > perpetrating a flim-flam.
>
> > >> >> Then you are deluded.
>
> > >> >> >  So I give them an example, easy to
> > >> >> > understand, marks every ten meters on S and marks every ten meters
> > >> >> > on
> > >> >> > S', and they pretend they do not understand how that could be.
>
> > >> >> Nothing wrong with that .. its called a pair of rulers
>
> > >> >> >  Well,
> > >> >> > OK, show the mathematics that you do not understand.
>
> > >> >> I do understand it.  You don't
>
> > >> >> > t'=t.
>
> > >> >> But it doesn't .. because experiment shows that time for a moving
> > >> >> object
> > >> >> is
> > >> >> measured as slower
>
> > >> >> > You have failed to show any proof whatsoever that this equation
> > >> >> > applies to anything other than the marks on S and S'.
>
> > >> >> It doesn't apply to marks.  It applies to time.  And it is proven
> > >> >> wrong.
>
> > >> >> >  It means that
> > >> >> > the marks on S are the same distance apart as the marks on S'.
>
> > >> >> The marks in S are 10m apart in S and the marks in S' are 10m apart in
> > >> >> S'.
>
> > >> >> That does not mean that an S observer would measure the moving marks
> > >> >> in
> > >> >> S'
> > >> >> as being 10m apart, or vice versa.
>
> > >> >> Galileantransforms say they would, Lorentz transforms say they do not.
>
> > >> >> Galileantransforms also say that differently moving clocks will by
> > >> >> measured
> > >> >> as ticking at the same rate, Lorentz transforms say they do not.
> > >> >> Experiment
> > >> >> confirms the Lorentz prediction.  Galillean transforms are refuted.
>
> > >> >> >  When
> > >> >> > S' moves relative to S, the marks line up with each other the entire
> > >> >> > lengths of S and S' every time the moving frame of reference moves
> > >> >> > 10
> > >> >> > m.
>
> > >> >> Nope.  That is whatGalileantransforms say, and very close to what
> > >> >> Lorentz
> > >> >> transforms predict at low speeds.
>
> > >> >> >  This is true when S' is moving at 1 m. /yr. and it is true when S'
> > >> >> > is moving at .99999c.
>
> > >> >> Nope.  Its not true in either.  The difference though is whether you
> > >> >> can
> > >> >> measure the difference accurately enough to tell.
>
> > >> >> >  You have no mathematics that shows otherwise
>
> > >> >> Wrong.  Lorentz transforms predict what we see experimentally
> > >> >> perfectly.
> > >> >> They give constant speed of light and they give time dilation as we
> > >> >> observe.Galileantransforms do not.
>
> > >> >> > because you have a time dilation that shows too much time on a clock
> > >> >> > in S', and consequently you have to compensate by saying there is a
> > >> >> > length contraction.
>
> > >> >> There is a length contraction and a time dilation.
>
> > >> >> >  Sorry, t'=t means there is no length
> > >> >> > contraction.
>
> > >> >> Wrong.  It means that the time (and so rates of clocks) is the same ..
> > >> >> it
> > >> >> doesn't say anything about lengths.
>
> > >> >> >  All you have is a slow clock in S'.
>
> > >> >> No .. the clocks in S' is just as correct as the one in S
>
> > >> >> Your score is getting worse .. a big fat ZERO score on that one.  Try
> > >> >> posting some more lies and nonsense .. I'm sure you will.
>
> > >> >> --- news://freenews.netfront.net/ - complaints: n...(a)netfront.net ---
>
> > >> > Well, anyone who is as committed to believing a fairy tale as you are
> > >> > should be allowed to believe it.
>
> > >> Liar
>
> > >> >  Here is the way I work the
> > >> > problem.
>
> > >> >                       x'=x-vt
> > >> >                       y'=y
> > >> >                       z'=Z
> > >> >                       t'=t
>
> > >> >    The last equation shows how time coordinates are transformed in
> > >> > theGalileantransformation equations.
>
> > >> There is no change in time due to motion or position .. so all correctly
> > >> working clocks will alwyas show the same tiem
>
> > >> This is REFUTED by experiment
>
> > >> >   The marks on S' align with the
> > >> > marks on S the entire lengths of S and S'.  That means that when one
> > >> > mark in S aligns with a mark in S', they all do.  This happens
> > >> > whenever the marks pass one another, whatever the velocity of S'
> > >> > relative to S.   If a clock in S shows t, it also shows t' because
> > >> > t'=t in theGalileantransformation equations.
>
> > >> Yeup .. and we know that correctly working clocks are affected by
> > >> relative
> > >> motion .. So the above is REFUTED
>
> > >> >     Scientists tell us that a clock in S' is slower than a clock in
> > >> > S.  Time on that clock cannot be t' because t' is already defined to
> > >> > be t, the time on a clock in S.  So we call time on the slower clock
> > >> > in S' by n'.
>
> > >> WRONG it is CORRECT clocks that work differently.  Not malfunctioning
> > >> ones
>
> > >> [snip nonsense from rbwinn lies]
>
> > > If time on correct clocks is slower than t, then it is slower than t'
> > > because t'=t.
>
> > Wrong.  A correct clock at rest in S shows time t .. by DEFINTION  A correct
> > clock at rest in S' shows time t' .. by DEFINITION.
>
> > So a correct clock at rest in in S cannot by slower then t and a correct
> > clock at rest  in S' cannot by slower than t'.
>
> > HOWEVER, what we find is that a correct clock at rest in S, that shows t',
> > runs slower than t.  So we lets use T' as the clock time shown on a correct
> > clock in S'
>
> > T' = t ... which says the clock shows the correct time in S'.. s it is a
> > correct clock
> > T' <> t .. which is what we observer, the clock runs slow
> > so t' <> t .. thereforeGalileantransforms wrong
>
> By definition, you say.

Yes.

>  Well, I just use the terms as they appear in
> the equations.

They don't

>  The equations only require that t'=t,

And so correct clocks will always agree. But they don't

> and the
> conditions of that are met if t'= time on a clock at rest in S.

And so correct clocks will always agree. But they don't.

> Scientists may have placed other constraints on the equations,

Nope

[snip bullshit from rbwinn]
From: eric gisse on
artful wrote:
[...]

>
> Then label those frames S and S' and it does. My god but you're
> stupid

Bobby is exploring the true depths of stupidity.

No rush - he's been doing it for more than a decade. He'll be here tomorrow.