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From: quadratic on 15 May 2010 20:28
In rectangle ABCD, point R is on BC, point T is on AD, and RT is
parallel to AB and to CD. Point S is on AB, and quadrilateral SRDT
has an area of 24. How does one determine the area of rectangle
ABCD? Thanks.
From: andrews on 16 May 2010 04:39
if you take the area of RTD and the area of RST (base*height/2) than you
find that the area of the rectangle is double of the area of DCBA, thus 48
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