From: Frederick Williams on
Charlie-Boo wrote:

> �Gentzen's consistency proof "reduces" the consistency of mathematics,
> not to something that could be proved.� � Wikipedia
> http://en.wikipedia.org/wiki/Gentzen%27s_consistency_proof
>
> Wiki doesn�t say anything about ZF in its write-up of Gentzen�s proof
> of the consistency of PA! What happened??

I cannot speak for the Wikipedists, but can you not see that the proof
could be formalized in ZFC?

I don't know what to make of

It "reduces" the consistency of a simplified part of mathematics,
not to something that could be proved (which would contradict the
basic results of Kurt G�del), but to clarified logical principles.

But then that's Wikipedia for you.

--
I can't go on, I'll go on.
From: Frederick Williams on
Charlie-Boo wrote:

> Hey Frederick, I bet you $449.94 that Gentzen's book doesn't contain a
> proof that PA is consistent, carried out in ZFC. You on?

No, but I do claim that it could be formalized in ZFC.

> Or do you say things that you don't believe?

Yes, but I don't think that's relevant here.

--
I can't go on, I'll go on.
From: Charlie-Boo on
On Jun 27, 1:21 pm, ah...(a)FreeNet.Carleton.CA (David Libert) wrote:
> Transfer Principle (lwal...(a)lausd.net) writes:
> > On Jun 26, 7:51=A0pm, Tim Little <t...(a)little-possums.net> wrote:
> >> On 2010-06-26, R. Srinivasan <sradh...(a)in.ibm.com> wrote:
> >> > The theory ZF-Inf+~Inf clearly proves ~Inf ("Infinite sets do not
> >> > exist").
> >> Actually ~Inf does not assert "Infinite sets do not exist". =A0It only
> >> asserts "there does not exist a successor-closed set containing the
> >> empty set".
>
> > This has come up time and time again. I myself have claimed that
> > the theory ZF-Infinity+~Infinity proves that every set is finite,
> > and someone (usually MoeBlee or Rupert) points out that this
> > theory only proves that there's no _successor-inductive_ set
> > containing 0, not that there is no infinite set.
>
> > And every time this comes up, I want to say _fine_ -- so if
> > ZF-Inf+~Inf _doesn't_ prove that every set is finite, then there
> > should exist a model M of ZF-Inf+~Inf in which "there is an
> > infinite set" is true, even though "there exists a set containing
> > 0 that is successor-inductive" is clearly false (assuming, of
> > course, that ZF is itself consistent), just as the fact that ZFC
> > doesn't prove CH implies that there is a model of ZFC in which
> > CH is false (once again, assuming that ZF is itself consistent).
>
> > Yet no one seems to accept the existence of this model M.
>
> > Either this model M exists, or ZF-Inf+~Inf really does prove that
> > every set is finite. There are no other possibilities.
>
> > So let's settle this once and for all. Assuming that ZF is
> > consistent, I ask:
>
> > 1. Is there a proof in ZF-Inf+~Inf that every set is finite?
> > 2. Does there exist a model M of ZF-Inf+~Inf in which "there
> > is an infinite set" is true?
>
> > Notice that exactly one of these questions has a "yes" answer
> > and exactly one has a "no" answer. (Actually, come to think
> > of it, since the base theory is ZF and not ZFC, it's possible
> > that the answer to 1. is "yes" if by "finite" we mean one
> > type of finite, say Dedekind finite, and "no" if we mean some
> > other type of finite. In this case, I'd like to know which
> > types of finite produce a "yes" answer.)
>
> > If 1. is "yes," then I hope that I will never again see a post
> > claiming that ZF-Inf+~Inf doesn't prove that every set is in
> > fact finite. In fact, I'll go as far as to suggest that if 1.
> > is "yes," then those who claim that ZF-Inf+~Inf doesn't prove
> > that every set is finite deserve to be called five-letter
> > insults -- if posters are going to call those who deny the
> > proof of Cantor's Theorem by five-letter insults, then those
> > who deny the proof of "every set is finite" in ZF-Inf+~Inf
> > also ought to be called the same.
>
> > If 2. is "yes," then what I'd like to know is how can I take
> > _advantage_ of this fact? Suppose I want to consider a theory,
> > based on ZF-Inf, which actually proves that an infinite set
> > exists, yet also proves that no successor-inductive set
> > containing 0 exists.
>
> > In the current Tony Orlow thread, there is a discussion about
> > whether TO is defining N+ to be a successor-inductive set. It
> > is possible that the theory that I mentioned above might be
> > useful to discussing TO's ideas.
>
> > But of course, we can't proceed until we know, once and for
> > all, whether ZF-Inf+~Inf proves every set to be finite or not.
>
>   I posted a couple of articles in an old thread related to the
> questions above, I will give references below.
>
>   One issue in all this is how to define  infinite  in the posing of
> the question.
>
>   In usual  ZF  or ZFC,  in the presence of the usual axiom of
> infinity,  we can prove there exists a smallest set having as
> member    emptyset  and closed under  the successor operation
> on von Neumann ordinals.
>
>   (The axiom of infinity does not directly assert the existence
> of such a set.  It asserts directly that there is a set having
> emptyset as memeber and closed under trhe von Neumann successor
> operation.  It does not directly assert there is a smallest such
> set.  But that axiom of infinity together with the separation
> axiom proves as a theorem there is a smallest such set.)
>
>   We then define this smallest such set to be the set omega.
>
>   The usual definition of finiteness in ordinary ZF or ZFC
> is having von Neumann cardinaity a member of omega.  Infinite
> is defined as not finite in that sense.
>
>   These definitions rest on the axiom of infinity itself, so
> it at least bears some discussion whether to try working with
> this definition or some alternatives.
>
>   One alternative pair of definitions would be  Dedekind finite
> and Dedekind infinite.  See my references below for more details.
>
>   In my references below I also give another definition of finite,
> not presupposing the usual axiom of infinity.
>
>   With these definitions, we can get various rephrasings of the
> question, that could be more suitable for this theory.
>
>   My articles especially concentrate on Dedekind finite.  But
> from the discussion there you can also extract information
> about the other cases.
>
>   The articles:
>
> [1]     David Libert     "Axiom of Infinity (AxF) in ZF"
>         sci.logic        Aug 26, 2003
>        http://groups.google.com/group/sci.logic/msg/8b55a452fdf641d9
>
> [2]     David Libert     "Axiom of Infinity (AxF) in ZF"
>         sci.logic        Aug 29, 2003
>        http://groups.google.com/group/sci.logic/msg/9417324657c5b242

Where is ZFC used to prove that if a system has a model then it is
consistent?

C-B

> --
> David Libert          ah...(a)FreeNet.Carleton.CA- Hide quoted text -
>
> - Show quoted text -

From: George Greene on
On Jun 27, 1:54 am, Transfer Principle <lwal...(a)lausd.net> wrote:
> Hughes will undoubtedly disagree with me, but I find the
> arrival of all these opponents of ZFC at the same time
> simply hilarious...

You're an idiot.
These opponents ARE NOT all arriving at the same time.
Srinivasan was talking about NAFL here 4 years ago.
Herc has been around longer than that, and so has Nam.


From: Charlie-Boo on
On Jun 27, 1:22 pm, William Hale <h...(a)tulane.edu> wrote:
> In article
> <dbebec73-757b-4de5-ae60-d5f6a6ab8...(a)t10g2000yqg.googlegroups.com>,
>
>
>
>
>
>  Charlie-Boo <shymath...(a)gmail.com> wrote:
> > On Jun 27, 5:18 am, William Hale <h...(a)tulane.edu> wrote:
> > > In article
> > > <ff54cc7d-b23f-4a45-9040-0459145ff...(a)j8g2000yqd.googlegroups.com>, Charlie-
> > > Boo <shymath...(a)gmail.com> wrote:
>
> > > [cut]
>
> > > > If ZFC can't calculate what PA can, how can anyone say that ZFC is a
> > > > good basis for doing mathematics - PA is used by lots of
> > > > mathematicians.
>
> >  > PA is not used by any mathematicians to do algebra, number theory,
> > real
> > > analysis, complex analysis, topology, or differential geometry. These
> >  > mathematicians represent most mathematicians. They use ZFC as their
> > > axiomatic system.
>
> > PA is not used but ZFC is?  But ZFC invokes the Peano Axioms carte
> > blanche to represent N - so PA is used by ZFC and thus by all of these
> > Mathematicians.
>

> ZFC does not invoke the Peano Axioms to represent N. Textbooks may

ZFC declares that there is a set that satisfies Peano’s Axioms and
defines N to be that set. Whether it uses the phrase “Peano’s Axioms”
or not, those are the axioms that are being listed and used.

C-B

> mention the Peano Axioms when they show how ZFC incorporates what it
> deems to be the natural numbers, but this mention of PA is only for
> putting things in a historical perspective or to give some motivation
> for what is going on in ZFC, but it is not necessary for ZFC to have any
> mention of PA in order to develop natural numbers.
>
> A textbook could mention how Euclid developed natural numbers (for
> historical purposes or to show similarities etc), but this does not mean
> that ZFC invokes the five Euclidean postulates of geometry.
>
>
>
> > Good point!
>
> > C-B- Hide quoted text -
>
> - Show quoted text -- Hide quoted text -
>
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