Hubble Redshift is the expansion of time
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From: Michael Helland on 10 Jul 2010 02:37 On Jul 9, 11:03 pm, Sam Wormley <sworml...(a)gmail.com> wrote: > On 7/10/10 12:20 AM, Michael Helland wrote: > > > On Jul 9, 5:07 pm, Sam Wormley<sworml...(a)gmail.com> wrote: > >> On 7/9/10 5:00 PM, Michael Helland wrote: > > >>> Except in a model where light slows down as evidenced by Hubble > >>> redshift. > > >> Did you forget that the speed of light is a defined constant! > > > Did you forget that is a scientific postulate, possibly with a limited > > domain of applicability, not a Universal and Absolute truth protected > > by taboo! > > Did you forget it is a measured constant! I hate to say this Mike, > but you really put up a resistance to credible information and > learning. Why is that? Did you fail some classes? Directly measuring the speed of light after million of years would require an experiment that lasted millions of years. Hubble redshift on the other hand is a directly measured phenomena in light that was actually emitted millions of years ago. I say in Hubble Redshift we are looking directly at a loss of frequency, loss of energy, and a loss of speed over the millions of years. You say we are looking at a loss of frequency and energy, and an increase in wavelength. I say the wavelength is increased when the speed is restored after the light is absorbed and re-emitted. My conclusions are the necessary result of this formula, v = c - Ht. When the light is absorbed and re-emitted, t goes back to 0 because t represents how long light has been traveling since being emitted. What my formula demands is confirmed by direct observations. > >> Physics FAQ: What is the experimental basis of special relativity? > >> http://math.ucr.edu/home/baez/physics/Relativity/SR/experiments.html Show me an experiment that last for millions of years, and I'll accept that we directly measure the speed of light after millions of years. In the meantime, it might be worth preparing yourself for the realization that SR does not have a Universal domain. Hubble redshift is direct evidence that the light cone of an observer doesn't not stretch indefinitely out like a martini glass: \ / \ / \/ Instead it curves out, producing Hubble redshift, like a wine glass | | \ / | | \ / \ / \/ This means at huge distances, some light cones may never intersect (which is true whether the expansion of space is act work or if the light simply has a finite range).
From: Michael Helland on 10 Jul 2010 02:39 On Jul 9, 10:54 pm, Sam Wormley <sworml...(a)gmail.com> wrote: > On 7/10/10 12:18 AM, Michael Helland wrote: > > > On Jul 9, 5:16 pm, Sam Wormley<sworml...(a)gmail.com> wrote: > > >>> On a quantum level, that means the light will be absorbed (with the > >>> redshifted frequency) and re-emitted without adding an energy. > > >> What ever gave you that the wavelength was shifted by a mirror? > > > Measurements of increased wavelength and decreased frequency from > > cosmological light. > > One can measure the spectra of a light source directly and then > reflected by a mirror and see that the spectra are identical. Not if the light source is millions of miles away. I'm suggesting Hubble redshift places a limits to the domains of applicability to the theories you seem to regarding as absolute truths, even at scales where they have never been directly demonstrated to hold, and where the evidence of Hubble redshift suggests that they do not hold. > Do the experiment Mike! It doesn't matter if the light source is > cosmic or in the lab. The mirror doesn't change the spectra.
From: Michael Helland on 10 Jul 2010 02:41 On Jul 9, 10:39 pm, eric gisse <jowr.pi.nos...(a)gmail.com> wrote: > Michael Helland wrote: > > On Jul 9, 5:34 pm, eric gisse <jowr.pi.nos...(a)gmail.com> wrote: > >> Michael Helland wrote: > > >> [...] > > >> >> > Except in a model where light slows down as evidenced by Hubble > >> >> > redshift. > > >> >> Wrong and stupid. Frequency and wavelength are measured separately, > >> >> and still multiple together to obtain 'c' even from cosmic sources. > > >> > In order to measure the wavelength of light you'll be bouncing it off > >> > a mirror and focusing it through lenses. > > >> Wrong and stupid again. Learn about diffraction gratings. > > > You think you can point a device without mirrors and a lens at an > > object 50 million light years away? > > > You're on crack. > > And you are reinventing electromagnetic theory to support your latest > uneducated guess about how the universe works, all the while demonstrating > your complete ignorance of basic observational astronomy. I'm reinventing EM theory to fit Hubble Evidence. What the Big Bang has done has changed the motion of every galaxy in the Universe and space itself, in order to avoid doing exactly that. There is no need for any type of inflation or dark energy if what I say is true. The Big Bang is far too contrived to justify not making any changes to EM theory to fit Hubble redshift which is observed in EM radiation.
From: Michael Helland on 10 Jul 2010 02:44 On Jul 9, 11:01 pm, Sam Wormley <sworml...(a)gmail.com> wrote: > On 7/10/10 12:19 AM, Michael Helland wrote: > > > > > > > On Jul 9, 5:34 pm, eric gisse<jowr.pi.nos...(a)gmail.com> wrote: > >> Michael Helland wrote: > > >> [...] > > >>>>> Except in a model where light slows down as evidenced by Hubble > >>>>> redshift. > > >>>> Wrong and stupid. Frequency and wavelength are measured separately, and > >>>> still multiple together to obtain 'c' even from cosmic sources. > > >>> In order to measure the wavelength of light you'll be bouncing it off > >>> a mirror and focusing it through lenses. > > >> Wrong and stupid again. Learn about diffraction gratings. > > > You think you can point a device without mirrors and a lens at an > > object 50 million light years away? > > I can see the Andromeda Galaxy (M31) with my naked eye, at 2.5 Mly.. > What's another 20 times that? > > Don't forget other parts of the electromagnetic spectrum. We have > gamma, x-ray, UV, visible IR, microwave and radio telescopes. None > of them alter the wavelength of the "light" they collect. If they absorb redshifted light and re-emit it (which happens at the quantum level when it is reflected or observed), I propose that is exactly what it is doing, and that is what is observed. > > You're on crack.
From: Sam Wormley on 10 Jul 2010 09:46
On 7/10/10 1:39 AM, Michael Helland wrote: > On Jul 9, 10:54 pm, Sam Wormley<sworml...(a)gmail.com> wrote: >> On 7/10/10 12:18 AM, Michael Helland wrote: >> >>> On Jul 9, 5:16 pm, Sam Wormley<sworml...(a)gmail.com> wrote: >> >>>>> On a quantum level, that means the light will be absorbed (with the >>>>> redshifted frequency) and re-emitted without adding an energy. >> >>>> What ever gave you that the wavelength was shifted by a mirror? >> >>> Measurements of increased wavelength and decreased frequency from >>> cosmological light. >> >> One can measure the spectra of a light source directly and then >> reflected by a mirror and see that the spectra are identical. > > Not if the light source is millions of miles away. Take the sun for example--millions of miles away. Using a diffraction grating, sunlight is broken into its spectra. See: http://antwrp.gsfc.nasa.gov/apod/ap100627.html Reflect the sunlight with a mirror before the diffraction grating and on gets identical spectra. The same is true for any other star or galaxy. Any Doppler or and cosmic red shift is preserved by the mirror. The distance photons traveled from their sources and the associate red or blue shift is not altered by the optics of the telescope. Anyone who would continue to be confused by that might be dumber than a pail of nails (which is not as bad as being dumber than a box of rocks). I'm not saying you are dumb, Michael, but I'm starting to raise my eyebrows. |