From: John Fields on
On Thu, 06 Apr 2006 18:40:11 GMT, Rich Grise <richgrise(a)example.net>
wrote:

>On Tue, 04 Apr 2006 17:20:49 -0500, John Fields wrote:
>...
>> And then you need to backtrack through the thread to find out what
>> the OP _really_ wanted. Sound like fun?
>
>Nothing to it:
>------------------------------------
>On Wed, 29 Mar 2006 10:49:27 -0800, john wrote:
>
>Hi,
>
>I have to design a voltage source ( +/- 18volts, 13A ) using lead acid
>batteries. My circuit draw is 700mA and requires plus minus 18 volts to
>operate efficiently. I need batteries that can atleast run for 10 to 12
>hours before the voltage drops to +/- 17 volts. I am thinking of adding
>three 6 volts, 13AH ( rated for 20AH ) batteries in series to produce
>+18 volts and adding three 6 volts to generate -18 volts. I choose the
>battery ( BP13-6V ), http://www.zbattery.com/zbattery/ub13-6.html.
>
>Can anybody advice me that am I doing the right thing that will these
>six batteries last for 10 to 12 hours maintaining +/- 18 volts @
>600mA.
>
>Thanks
>Regards
>John
>------------------------------------
>
>I guess when I saw "My circuit draw is 700 mA" I assumed that he means
>that his circuit draws 700 mA. I also assume that when he said "18 volts,
>13A", he really meant the 13 AH capacity that he mentions five lines
>later, and the lack of the "H" in the first line is an oversignt. The
>batteries he linked to are, in fact, 13 AH.

---
You've got a lot of "I guess" and "I assume in there, Rich.

First he says his circuit draws 700mA at +/- 18V and he wants to run
for 10-12 hours before the battery voltage drops to +/-17V, and then
he wants to run at 600mA for 10 to 12 hours with no voltage drop at
all, which is bullshit.

He was given everything he needed to know early on.

--
John Fields
Professional Circuit Designer
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