Lemma. (1)
in [Math]
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From: fernando revilla on 5 May 2010 03:35 (i) Let a be an even number (a >= 16, a - 3 and a/2 composite). Consider any Goldbach Conjecture function associated to a: G : [ 4^, (a / 2)^ ] -> IR with coefficients b_ 2, b_ 3, ... , b_{a / 2}, ... , b_{a - 5} and denote m = b_2^2 / b_{a / 2}^2. Then, 1 < m < (a - 4 ) / 4 => G ( 4^ ) > 0 and G ( (a / 2)^ ) < 0. (ii) For any prime p ( 3 < p < a / 2 ) we can choose m such that: G ( p^ ) = 0. ------------ This result will allow to compare the "decreasing order" of G according to de cases a - p prime or a - p composite. --- http://ficus.pntic.mec.es/~frej0002/
From: fernando revilla on 5 May 2010 03:42 Typo: "according to the cases" instead of "according to de cases" --- http://ficus.pntic.mec.es/~frej0002/
From: master1729 on 5 May 2010 10:31 > (i) Let a be an even number (a >= 16, a - 3 and a/2 > composite). > Consider any Goldbach Conjecture function associated > to a: > > G : [ 4^, (a / 2)^ ] -> IR > > with coefficients b_ 2, b_ 3, ... , b_{a / 2}, ... , > b_{a - 5} and > denote m = b_2^2 / b_{a / 2}^2. Then, > > 1 < m < (a - 4 ) / 4 => G ( 4^ ) > 0 and G ( (a / 2)^ > ) < 0. > > (ii) For any prime p ( 3 < p < a / 2 ) we can choose > m such that: > > G ( p^ ) = 0. what ?
From: fernando revilla on 5 May 2010 11:35 master1729 wrote: > what ? Continuing a previous theory. Regards --- http://ficus.pntic.mec.es/~frej0002/
From: Gerry Myerson on 5 May 2010 19:41
In article <225747014.77894.1273088134405.JavaMail.root(a)gallium.mathforum.org>, fernando revilla <frej0002(a)ficus.pntic.mec.es> wrote: > master1729 wrote: > > > what ? > > Continuing a previous theory. Regards In other words, talking to yourself. -- Gerry Myerson (gerry(a)maths.mq.edi.ai) (i -> u for email) |