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From: Charles Koehler on 9 Apr 2010 03:31
Hello,



If possible I could use a little help on this.



I have a list of x and y data and based on the value of x I would like to
manipulate the value y.

I joined the data using:

pts=MapThread[{##1}&,{x,y}]

I assumed that by testing the x value using #[[1]], I could change the value
of y using #[[2]] as shown below. If no manipulation was required based on
the value of x, I would keep that point unchanged, but I'm definitely
missing something.



filtered=If[a<#[[1]]&<b,#[[2]]&=0],{#[[1]],#[[2]]}&,pts]



a and b are the range of x values





Any insight would be much appreciated.



Thanks,



Chuck Koehler

From: Bill Rowe on 10 Apr 2010 06:54
On 4/9/10 at 3:31 AM, cjkphd(a)wi.rr.com (Charles Koehler) wrote:


>I joined the data using:

>pts=MapThread[{##1}&,{x,y}]

While this will clearly work and there is nothing wrong with it,
it seems to me more direct and clearer to do

Transpose@{x,y} or even
MapThread[List, {x,y}]

>I assumed that by testing the x value using #[[1]], I could change
>the value of y using #[[2]] as shown below. If no manipulation was
>required based on the value of x, I would keep that point unchanged,
>but I'm definitely missing something.

>filtered=If[a<#[[1]]&<b,#[[2]]&=0],{#[[1]],#[[2]]}&,pts]

>a and b are the range of x values

One way to accomplish what you want would be to use pattern
matching as follows:

In[28]:= x = RandomReal[1, 10];
y = RandomReal[2, 10];
Sort[Transpose[{x, y}]] /. {a_?(.2 < # < .8 &), b_} :> {a, 0}

Out[30]= {{0.0761041, 1.91884}, {0.129938, 0.115834}, {0.304408,
0}, {0.439366, 0}, {0.505744, 0}, {0.58412, 0}, {0.616887,
0}, {0.672258, 0}, {0.808959, 0.600491}, {0.827083, 1.27203}}

Here, I sorted the x,y pairs simply to make it easy to see the
output has 0 for y whenever x is between the two specified values.


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