Mutual time slowdown means both clocks go slow
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From: artful on 7 Aug 2010 00:02 On Aug 7, 1:42 pm, BURT <macromi...(a)yahoo.com> wrote: > On Aug 6, 8:35 pm, artful <artful...(a)hotmail.com> wrote: > > > > > > > On Aug 7, 1:17 pm, BURT <macromi...(a)yahoo.com> wrote: > > > > On Aug 6, 8:11 pm, artful <artful...(a)hotmail.com> wrote: > > > > > On Aug 7, 10:02 am, BURT <macromi...(a)yahoo.com> wrote: > > > > > > Let us say you are a twin on a high speed train. You are passsing the > > > > > station and its clock is out in the open. When you pass the station by > > > > > SR you are supposed to see its clock going slow. But if this were true > > > > > show when it has an oportunity to age more. Surely it cannot be mutual > > > > > all of the time and what needs to be defined is when it is not. > > > > > Otherwise you don't have a workable theory. > > > > > > Mitch Raemsch > > > > > So .. you still don't get it. Neither clock is running slow .. both > > > > are keeping perfect time. > > > > > They are MEASURED as slower by moving observers. > > > > So all I have to do is move and I can slow down clocks around me? > > > No. Don't you read? You moving does NOTHING AT ALL to the other > > clocks. NEITHER clock is running slow. > > > > > Eg. if a passenger at the font of the train looks at the time on the > > > > station clock (compared to his own clock) as he passes it, and a > > > > passenger at the rear of the train looks at the time n the station > > > > clock (compared to his own clock) as he passes it, and then if they > > > > compare what times they saw on the station clock .. they would say > > > > that the station clock is running SLOWER. HOWEVER, a parson standing > > > > at the station clock, and looking at the clocks of the two passengers > > > > as they pass, would conclude that time was running FASTER for the > > > > train passengers (not slower). There is no contradiction in what they > > > > observe. > > > > > If you reverse the situation (two observers at each end of the > > > > platform and a clock in the middle of the train) you'd get the two > > > > observers on the platform deciding that the train clock is SLOWER, and > > > > an observer at the train clock would see the two people on ends of the > > > > platform's clock running FASTER. > > > > > Its a difference in clock sync for the passengers relative to the > > > > station clock that make the rate of time appear faster or slower. > > > > If the passengers in front and back of the train see the station's > > > clock running slow then how will that station age more than them? > > > No. Don't you read? Both are ticking at the same correct rate .. > > neither ages more than the other. It is differences in clock sync > > that mean you would calculate other clocks as apparently ticking > > slower or faster.- Hide quoted text - > > > - Show quoted text -- Hide quoted text - > > > - Show quoted text - > > One twin ages more than the other. No. Don't you read? > If the twin on the train sees the > station twin time running slow How do you think he determines that? > then when does it happen that the > station twin ages more? He doesn't. Nor does he age less. > In the end one ages more. No. Both age at the same rate. Don't you read? > so there is no mutual > time dilation for the twins. Wrong. You're really not very good at reading and understanding, are you?
From: BURT on 7 Aug 2010 00:09 On Aug 6, 9:02 pm, artful <artful...(a)hotmail.com> wrote: > On Aug 7, 1:42 pm, BURT <macromi...(a)yahoo.com> wrote: > > > > > > > On Aug 6, 8:35 pm, artful <artful...(a)hotmail.com> wrote: > > > > On Aug 7, 1:17 pm, BURT <macromi...(a)yahoo.com> wrote: > > > > > On Aug 6, 8:11 pm, artful <artful...(a)hotmail.com> wrote: > > > > > > On Aug 7, 10:02 am, BURT <macromi...(a)yahoo.com> wrote: > > > > > > > Let us say you are a twin on a high speed train. You are passsing the > > > > > > station and its clock is out in the open. When you pass the station by > > > > > > SR you are supposed to see its clock going slow. But if this were true > > > > > > show when it has an oportunity to age more. Surely it cannot be mutual > > > > > > all of the time and what needs to be defined is when it is not. > > > > > > Otherwise you don't have a workable theory. > > > > > > > Mitch Raemsch > > > > > > So .. you still don't get it. Neither clock is running slow .. both > > > > > are keeping perfect time. > > > > > > They are MEASURED as slower by moving observers. > > > > > So all I have to do is move and I can slow down clocks around me? > > > > No. Don't you read? You moving does NOTHING AT ALL to the other > > > clocks. NEITHER clock is running slow. > > > > > > Eg. if a passenger at the font of the train looks at the time on the > > > > > station clock (compared to his own clock) as he passes it, and a > > > > > passenger at the rear of the train looks at the time n the station > > > > > clock (compared to his own clock) as he passes it, and then if they > > > > > compare what times they saw on the station clock .. they would say > > > > > that the station clock is running SLOWER. HOWEVER, a parson standing > > > > > at the station clock, and looking at the clocks of the two passengers > > > > > as they pass, would conclude that time was running FASTER for the > > > > > train passengers (not slower). There is no contradiction in what they > > > > > observe. > > > > > > If you reverse the situation (two observers at each end of the > > > > > platform and a clock in the middle of the train) you'd get the two > > > > > observers on the platform deciding that the train clock is SLOWER, and > > > > > an observer at the train clock would see the two people on ends of the > > > > > platform's clock running FASTER. > > > > > > Its a difference in clock sync for the passengers relative to the > > > > > station clock that make the rate of time appear faster or slower. > > > > > If the passengers in front and back of the train see the station's > > > > clock running slow then how will that station age more than them? > > > > No. Don't you read? Both are ticking at the same correct rate ... > > > neither ages more than the other. It is differences in clock sync > > > that mean you would calculate other clocks as apparently ticking > > > slower or faster.- Hide quoted text - > > > > - Show quoted text -- Hide quoted text - > > > > - Show quoted text - > > > One twin ages more than the other. > > No. Don't you read? > > > If the twin on the train sees the > > station twin time running slow > > How do you think he determines that? Because the clock is on the outside of the station. > > > then when does it happen that the > > station twin ages more? > > He doesn't. Nor does he age less. That is not what Einstein had to say about his twins. Where do you get your argument against Einstein's twin paradox? Mitch Raemsch > > > In the end one ages more. > > No. Both age at the same rate. Don't you read? > > > so there is no mutual > > time dilation for the twins. > > Wrong. You're really not very good at reading and understanding, are > you?- Hide quoted text - > > - Show quoted text -
From: artful on 7 Aug 2010 00:17 On Aug 7, 2:09 pm, BURT <macromi...(a)yahoo.com> wrote: > On Aug 6, 9:02 pm, artful <artful...(a)hotmail.com> wrote: > > > > > > > On Aug 7, 1:42 pm, BURT <macromi...(a)yahoo.com> wrote: > > > > On Aug 6, 8:35 pm, artful <artful...(a)hotmail.com> wrote: > > > > > On Aug 7, 1:17 pm, BURT <macromi...(a)yahoo.com> wrote: > > > > > > On Aug 6, 8:11 pm, artful <artful...(a)hotmail.com> wrote: > > > > > > > On Aug 7, 10:02 am, BURT <macromi...(a)yahoo.com> wrote: > > > > > > > > Let us say you are a twin on a high speed train. You are passsing the > > > > > > > station and its clock is out in the open. When you pass the station by > > > > > > > SR you are supposed to see its clock going slow. But if this were true > > > > > > > show when it has an oportunity to age more. Surely it cannot be mutual > > > > > > > all of the time and what needs to be defined is when it is not. > > > > > > > Otherwise you don't have a workable theory. > > > > > > > > Mitch Raemsch > > > > > > > So .. you still don't get it. Neither clock is running slow .. both > > > > > > are keeping perfect time. > > > > > > > They are MEASURED as slower by moving observers. > > > > > > So all I have to do is move and I can slow down clocks around me? > > > > > No. Don't you read? You moving does NOTHING AT ALL to the other > > > > clocks. NEITHER clock is running slow. > > > > > > > Eg. if a passenger at the font of the train looks at the time on the > > > > > > station clock (compared to his own clock) as he passes it, and a > > > > > > passenger at the rear of the train looks at the time n the station > > > > > > clock (compared to his own clock) as he passes it, and then if they > > > > > > compare what times they saw on the station clock .. they would say > > > > > > that the station clock is running SLOWER. HOWEVER, a parson standing > > > > > > at the station clock, and looking at the clocks of the two passengers > > > > > > as they pass, would conclude that time was running FASTER for the > > > > > > train passengers (not slower). There is no contradiction in what they > > > > > > observe. > > > > > > > If you reverse the situation (two observers at each end of the > > > > > > platform and a clock in the middle of the train) you'd get the two > > > > > > observers on the platform deciding that the train clock is SLOWER, and > > > > > > an observer at the train clock would see the two people on ends of the > > > > > > platform's clock running FASTER. > > > > > > > Its a difference in clock sync for the passengers relative to the > > > > > > station clock that make the rate of time appear faster or slower. > > > > > > If the passengers in front and back of the train see the station's > > > > > clock running slow then how will that station age more than them? > > > > > No. Don't you read? Both are ticking at the same correct rate .. > > > > neither ages more than the other. It is differences in clock sync > > > > that mean you would calculate other clocks as apparently ticking > > > > slower or faster.- Hide quoted text - > > > > > - Show quoted text -- Hide quoted text - > > > > > - Show quoted text - > > > > One twin ages more than the other. > > > No. Don't you read? > > > > If the twin on the train sees the > > > station twin time running slow > > > How do you think he determines that? > > Because the clock is on the outside of the station. You didn't answer the question .. where the clock is located is NOT how the rate is determined. So .. how about you answer the question: How does the observer on the train determine that the station clock is ticking slower? > > > then when does it happen that the > > > station twin ages more? > > > He doesn't. Nor does he age less. > > That is not what Einstein had to say about his twins. *YOU* and *I* are talking about 'twins' on a train and station, and *mutual* time dilation. That is very different to the 'twin paradox' where one twin moves away from the other and the changes velocity and returns. You are nowhere NEAR ready to talk about that until you understand mutual time dilation and what it actually means. Don't run before you can walk. > Where do you get your argument against Einstein's twin paradox? I'm not arguing against it .. I wan't even talking about it. And neither were you. What I AM trying (in vain) to do is to educate you. Are you willing to learn, or are you going to remain a troll? Now .. back to mutual time dilation. Both clocks tick at the correct rate. Neither slows down. Neither speeds up. A moving observer has NO EFFECT on the ticking rate of a clock. In your scenario of a passenger on a train and a station clock .. How does the passenger determine that the station clock is ticking slower?
From: BURT on 7 Aug 2010 00:21 On Aug 6, 9:17 pm, artful <artful...(a)hotmail.com> wrote: > On Aug 7, 2:09 pm, BURT <macromi...(a)yahoo.com> wrote: > > > > > > > On Aug 6, 9:02 pm, artful <artful...(a)hotmail.com> wrote: > > > > On Aug 7, 1:42 pm, BURT <macromi...(a)yahoo.com> wrote: > > > > > On Aug 6, 8:35 pm, artful <artful...(a)hotmail.com> wrote: > > > > > > On Aug 7, 1:17 pm, BURT <macromi...(a)yahoo.com> wrote: > > > > > > > On Aug 6, 8:11 pm, artful <artful...(a)hotmail.com> wrote: > > > > > > > > On Aug 7, 10:02 am, BURT <macromi...(a)yahoo.com> wrote: > > > > > > > > > Let us say you are a twin on a high speed train. You are passsing the > > > > > > > > station and its clock is out in the open. When you pass the station by > > > > > > > > SR you are supposed to see its clock going slow. But if this were true > > > > > > > > show when it has an oportunity to age more. Surely it cannot be mutual > > > > > > > > all of the time and what needs to be defined is when it is not. > > > > > > > > Otherwise you don't have a workable theory. > > > > > > > > > Mitch Raemsch > > > > > > > > So .. you still don't get it. Neither clock is running slow ... both > > > > > > > are keeping perfect time. > > > > > > > > They are MEASURED as slower by moving observers. > > > > > > > So all I have to do is move and I can slow down clocks around me? > > > > > > No. Don't you read? You moving does NOTHING AT ALL to the other > > > > > clocks. NEITHER clock is running slow. > > > > > > > > Eg. if a passenger at the font of the train looks at the time on the > > > > > > > station clock (compared to his own clock) as he passes it, and a > > > > > > > passenger at the rear of the train looks at the time n the station > > > > > > > clock (compared to his own clock) as he passes it, and then if they > > > > > > > compare what times they saw on the station clock .. they would say > > > > > > > that the station clock is running SLOWER. HOWEVER, a parson standing > > > > > > > at the station clock, and looking at the clocks of the two passengers > > > > > > > as they pass, would conclude that time was running FASTER for the > > > > > > > train passengers (not slower). There is no contradiction in what they > > > > > > > observe. > > > > > > > > If you reverse the situation (two observers at each end of the > > > > > > > platform and a clock in the middle of the train) you'd get the two > > > > > > > observers on the platform deciding that the train clock is SLOWER, and > > > > > > > an observer at the train clock would see the two people on ends of the > > > > > > > platform's clock running FASTER. > > > > > > > > Its a difference in clock sync for the passengers relative to the > > > > > > > station clock that make the rate of time appear faster or slower. > > > > > > > If the passengers in front and back of the train see the station's > > > > > > clock running slow then how will that station age more than them? > > > > > > No. Don't you read? Both are ticking at the same correct rate .. > > > > > neither ages more than the other. It is differences in clock sync > > > > > that mean you would calculate other clocks as apparently ticking > > > > > slower or faster.- Hide quoted text - > > > > > > - Show quoted text -- Hide quoted text - > > > > > > - Show quoted text - > > > > > One twin ages more than the other. > > > > No. Don't you read? > > > > > If the twin on the train sees the > > > > station twin time running slow > > > > How do you think he determines that? > > > Because the clock is on the outside of the station. > > You didn't answer the question .. where the clock is located is NOT > how the rate is determined. So .. how about you answer the question: > How does the observer on the train determine that the station clock is > ticking slower? > > > > > then when does it happen that the > > > > station twin ages more? > > > > He doesn't. Nor does he age less. > > > That is not what Einstein had to say about his twins. > > *YOU* and *I* are talking about 'twins' on a train and station, and > *mutual* time dilation. > > That is very different to the 'twin paradox' where one twin moves away > from the other and the changes velocity and returns. You are nowhere > NEAR ready to talk about that until you understand mutual time > dilation and what it actually means. Don't run before you can walk. > > > Where do you get your argument against Einstein's twin paradox? > > I'm not arguing against it .. I wan't even talking about it. And > neither were you. > > What I AM trying (in vain) to do is to educate you. Are you willing > to learn, or are you going to remain a troll? > > Now .. back to mutual time dilation. Both clocks tick at the correct > rate. Neither slows down. Neither speeds up. A moving observer has > NO EFFECT on the ticking rate of a clock. In your scenario of a > passenger on a train and a station clock .. How does the passenger > determine that the station clock is ticking slower?- Hide quoted text - > > - Show quoted text - Asuming the stations clock is outside he should have no problem seeing it and recording it as he passes. But if it is slow as Special Relativity says when does it get to age faster? Mitch Raemsch
From: artful on 7 Aug 2010 00:26
On Aug 7, 2:21 pm, BURT <macromi...(a)yahoo.com> wrote: > On Aug 6, 9:17 pm, artful <artful...(a)hotmail.com> wrote: > > > > > > > On Aug 7, 2:09 pm, BURT <macromi...(a)yahoo.com> wrote: > > > > On Aug 6, 9:02 pm, artful <artful...(a)hotmail.com> wrote: > > > > > On Aug 7, 1:42 pm, BURT <macromi...(a)yahoo.com> wrote: > > > > > > On Aug 6, 8:35 pm, artful <artful...(a)hotmail.com> wrote: > > > > > > > On Aug 7, 1:17 pm, BURT <macromi...(a)yahoo.com> wrote: > > > > > > > > On Aug 6, 8:11 pm, artful <artful...(a)hotmail.com> wrote: > > > > > > > > > On Aug 7, 10:02 am, BURT <macromi...(a)yahoo.com> wrote: > > > > > > > > > > Let us say you are a twin on a high speed train. You are passsing the > > > > > > > > > station and its clock is out in the open. When you pass the station by > > > > > > > > > SR you are supposed to see its clock going slow. But if this were true > > > > > > > > > show when it has an oportunity to age more. Surely it cannot be mutual > > > > > > > > > all of the time and what needs to be defined is when it is not. > > > > > > > > > Otherwise you don't have a workable theory. > > > > > > > > > > Mitch Raemsch > > > > > > > > > So .. you still don't get it. Neither clock is running slow .. both > > > > > > > > are keeping perfect time. > > > > > > > > > They are MEASURED as slower by moving observers. > > > > > > > > So all I have to do is move and I can slow down clocks around me? > > > > > > > No. Don't you read? You moving does NOTHING AT ALL to the other > > > > > > clocks. NEITHER clock is running slow. > > > > > > > > > Eg. if a passenger at the font of the train looks at the time on the > > > > > > > > station clock (compared to his own clock) as he passes it, and a > > > > > > > > passenger at the rear of the train looks at the time n the station > > > > > > > > clock (compared to his own clock) as he passes it, and then if they > > > > > > > > compare what times they saw on the station clock .. they would say > > > > > > > > that the station clock is running SLOWER. HOWEVER, a parson standing > > > > > > > > at the station clock, and looking at the clocks of the two passengers > > > > > > > > as they pass, would conclude that time was running FASTER for the > > > > > > > > train passengers (not slower). There is no contradiction in what they > > > > > > > > observe. > > > > > > > > > If you reverse the situation (two observers at each end of the > > > > > > > > platform and a clock in the middle of the train) you'd get the two > > > > > > > > observers on the platform deciding that the train clock is SLOWER, and > > > > > > > > an observer at the train clock would see the two people on ends of the > > > > > > > > platform's clock running FASTER. > > > > > > > > > Its a difference in clock sync for the passengers relative to the > > > > > > > > station clock that make the rate of time appear faster or slower. > > > > > > > > If the passengers in front and back of the train see the station's > > > > > > > clock running slow then how will that station age more than them? > > > > > > > No. Don't you read? Both are ticking at the same correct rate .. > > > > > > neither ages more than the other. It is differences in clock sync > > > > > > that mean you would calculate other clocks as apparently ticking > > > > > > slower or faster.- Hide quoted text - > > > > > > > - Show quoted text -- Hide quoted text - > > > > > > > - Show quoted text - > > > > > > One twin ages more than the other. > > > > > No. Don't you read? > > > > > > If the twin on the train sees the > > > > > station twin time running slow > > > > > How do you think he determines that? > > > > Because the clock is on the outside of the station. > > > You didn't answer the question .. where the clock is located is NOT > > how the rate is determined. So .. how about you answer the question: > > How does the observer on the train determine that the station clock is > > ticking slower? > > > > > > then when does it happen that the > > > > > station twin ages more? > > > > > He doesn't. Nor does he age less. > > > > That is not what Einstein had to say about his twins. > > > *YOU* and *I* are talking about 'twins' on a train and station, and > > *mutual* time dilation. > > > That is very different to the 'twin paradox' where one twin moves away > > from the other and the changes velocity and returns. You are nowhere > > NEAR ready to talk about that until you understand mutual time > > dilation and what it actually means. Don't run before you can walk. > > > > Where do you get your argument against Einstein's twin paradox? > > > I'm not arguing against it .. I wan't even talking about it. And > > neither were you. > > > What I AM trying (in vain) to do is to educate you. Are you willing > > to learn, or are you going to remain a troll? > > > Now .. back to mutual time dilation. Both clocks tick at the correct > > rate. Neither slows down. Neither speeds up. A moving observer has > > NO EFFECT on the ticking rate of a clock. In your scenario of a > > passenger on a train and a station clock .. How does the passenger > > determine that the station clock is ticking slower?- Hide quoted text - > > > - Show quoted text - > > Asuming the stations clock is outside he should have no problem seeing > it and recording it as he passes. Seeing and recording a single time as as passes tell you NOTHING about the ticking rate. How does the passenger determine that the station clock is ticking slower? Tell me the process he uses. NOTE: He is allowed to have other friends on the station or the train help him. |