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From: Carlo Wah on 10 Jun 2010 15:00
It seems to me that the concept of absolute space is necessary to
solve even the simplest problems. If not, can anyone please explain
this simple problem from the point of view of the moving frame.

Rest frame view.
There is a flat target (like a piece of plywood) parallel to the
y-z plane. The target is moving in the -x direction at a constant
velocity. The bottom of the target is L meters above the x-axis. The
center of the target is at L+D meters above the x-axis. When the side
of the target facing the positive x direction crosses x=0, a bullet or
photon is fired from x=0,y=0,z=0. It travels in the second quadrant
and hits the center of the target which is at some x = -L1 and y = L
+D.

Moving frame view.
Let the moving frame be the rest frame of the target. From this
frame's point of view, the bullet leaves x=0,y=0,z=0, and travels
parallel to or along the y-axis, and hence parallel to the surface of
the target.

How does the moving frame explain why the bullet finally hits the
surface at the point y = L+D above the x-axis, if it was fired from
x=0,y=0,z=0 and travels parallel to or along the y-axis?

Thanks,
David Seppala
Bastrop, TX
From: BURT on 10 Jun 2010 16:57
On Jun 10, 12:00 pm, Carlo Wah <kwanalo...(a)gmail.com> wrote:
>  It seems to me that the concept of absolute space is necessary to
> solve even the simplest problems.  If not, can anyone please explain
> this simple problem from the point of view of the moving frame.
>
> Rest frame view.
>      There is a flat target (like a piece of plywood) parallel to the
> y-z plane.  The target is moving in the -x direction at a constant
> velocity.  The bottom of the target is L meters above the x-axis.  The
> center of the target is at L+D meters above the x-axis. When the side
> of the target facing the positive x direction crosses x=0, a bullet or
> photon is fired from x=0,y=0,z=0.  It travels in the second quadrant
> and hits the center of the target which is at some x = -L1 and y = L
> +D.
>
> Moving frame view.
>       Let the moving frame be the rest frame of the target.  From this
> frame's point of view, the bullet leaves x=0,y=0,z=0, and travels
> parallel to  or along the y-axis, and hence parallel to the surface of
> the target.
>
> How does the moving frame explain why the bullet finally hits the
> surface at the point y = L+D above the x-axis, if it was fired from
> x=0,y=0,z=0 and travels parallel to or along  the y-axis?
>
> Thanks,
> David Seppala
> Bastrop, TX

Matter can move behind light in the same direction of its propagation.
They can flow together in the same direction. So light has a
seperating speed of very slow motion; that is it inches ahead of
matter in absolute space. But this will increase because of the
difference over time.

The reverse is also true. You can leave light behind by moving at near
light speed ahead of it. When you are already at high speed and
accelerating ahead of light there is a temporary black hole called a
motion black hole. Without acceleration light is left behind for
lesser time.

Mitch Raemsch
From: xxein on 10 Jun 2010 20:22
On Jun 10, 3:00 pm, Carlo Wah <kwanalo...(a)gmail.com> wrote:
>  It seems to me that the concept of absolute space is necessary to
> solve even the simplest problems.  If not, can anyone please explain
> this simple problem from the point of view of the moving frame.
>
> Rest frame view.
>      There is a flat target (like a piece of plywood) parallel to the
> y-z plane.  The target is moving in the -x direction at a constant
> velocity.  The bottom of the target is L meters above the x-axis.  The
> center of the target is at L+D meters above the x-axis. When the side
> of the target facing the positive x direction crosses x=0, a bullet or
> photon is fired from x=0,y=0,z=0.  It travels in the second quadrant
> and hits the center of the target which is at some x = -L1 and y = L
> +D.
>
> Moving frame view.
>       Let the moving frame be the rest frame of the target.  From this
> frame's point of view, the bullet leaves x=0,y=0,z=0, and travels
> parallel to  or along the y-axis, and hence parallel to the surface of
> the target.
>
> How does the moving frame explain why the bullet finally hits the
> surface at the point y = L+D above the x-axis, if it was fired from
> x=0,y=0,z=0 and travels parallel to or along  the y-axis?
>
> Thanks,
> David Seppala
> Bastrop, TX

xxein: You are asking why a muslim god is different than a christian
god?

You don't understand sh*t and are an idiot.
From: whoever on 10 Jun 2010 21:06
"Carlo Wah" <kwanalouie(a)gmail.com> wrote in message
news:bb13751a-2245-4a6f-90b8-8561319ef5c4(a)y11g2000yqm.googlegroups.com...
> It seems to me that the concept of absolute space is necessary to
> solve even the simplest problems.

No .. its not. What on earth gives you that idea? We cannot even tell
where any absolute frame / space is (if there is such a thing) and we don't
need one because physics works the same in ALL inertial frames anyway.

> If not, can anyone please explain
> this simple problem from the point of view of the moving frame.
>
> Rest frame view.

That's not the absolute frame .. just an arbitrarily chosen frame that you
have labelled as 'rest frame'. So it is not relevant to your assertion
above about absolute space/frames.

[snip unrelated problem]

So .. please show why one needs an absolute space/frames?



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From: eric gisse on 10 Jun 2010 21:21
Carlo Wah wrote:

> It seems to me that the concept of absolute space is necessary to
> solve even the simplest problems. If not, can anyone please explain
> this simple problem from the point of view of the moving frame.
>
> Rest frame view.
> There is a flat target (like a piece of plywood) parallel to the
> y-z plane. The target is moving in the -x direction at a constant
> velocity. The bottom of the target is L meters above the x-axis. The
> center of the target is at L+D meters above the x-axis. When the side
> of the target facing the positive x direction crosses x=0, a bullet or
> photon is fired from x=0,y=0,z=0. It travels in the second quadrant
> and hits the center of the target which is at some x = -L1 and y = L
> +D.
>
> Moving frame view.
> Let the moving frame be the rest frame of the target. From this
> frame's point of view, the bullet leaves x=0,y=0,z=0, and travels
> parallel to or along the y-axis, and hence parallel to the surface of
> the target.
>
> How does the moving frame explain why the bullet finally hits the
> surface at the point y = L+D above the x-axis, if it was fired from
> x=0,y=0,z=0 and travels parallel to or along the y-axis?
>
> Thanks,
> David Seppala
> Bastrop, TX

Why don't you open up an introductory textbook on SR THEN ask questions?

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