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From: OsherD on 25 Feb 2010 22:47 From Osher Doctorow It sometimes appears to us that the complex variable z argument of complex functions f(z), where z = y + ix (or z = x + iy), is the most difficult part of looking for a real "analog" of f(z) at least under + and -. However, with Probable Causation/Influence P(A-->B) = 1 + P(AB) - P(A) = 1 + y - x, y of z = y + ix goes over to y and ix goes over to -x for addition and subtraction, so z is not the complication. Now let us examine the first "inverse" term of a Laurent series, a_(-1)/(z - a), where constant a_(-1) is the symbol for the first constant coefficient of the inverse term. We use the usual "change": 1) y/x --> 1 + y - x (--> denotes "conversion to" or "change to" here) from Conditional Probability y/x with x not 0 to Probable Causation/ Influence (PI) 1 + y - x, with a_(-1)/(z - a) being y/x. This yields: 2) a_(-1)/(z - a) --> 1 + a_(-1) - (z - a) = 1 + (a_-1) + a - z = 1 + [a_(-1) + a] - z Now convert z to a real variable, which will be denoted x (not the x of (1)), and for simplicity convert a_(-1) + a to a nonnegative real constant. We get: 3) a_(-1)/(z - a) --> 1 + y - x, where z = x, y = a_(-1) + a It turns out to be not much more difficult to convert remaining terms of the "inverse" part of Laurent Series to PI, using such things as: 4) 1/(x - a)^2 = 1/(x^2 + a^2 - 2ax) and then noticing that: 5) 1/(x - a)^2 --> 1 + 1 + 2ax - x^2 - a^2, where x^2 + a^2 > 2ax from (x - a)^2 > 0. From the last few posts, this ties in with the Memory scenario. Osher Doctorow |