From: Winfield Hill on
electro wrote...
>
> I have a TIA with 1.5kohm of gain and 10GHz BW. I have to select a
> Photodiode for this TIA. I was wondering how do I determine the upper
> limit on photodiode junction capacitance when selecting the photodiode.

You've been given some good advice, but here's the relevant
formula. Common resistor-feedback TIA amplifiers need some
feedback capacitance for stability, to cancel the feedback-
resistor / summing-junction capacitance pole. The scene is
often expressed as a maximum Rf Cf bandwidth, due to Rf Cin
and f_T. The important parts are the Rf Cin noise-gain and
the opamp rolloff to f_T, giving us a geometric mean for fc.
More or less, fc = sqrt [f_T * 1 / (2pi Rf Cin)]. We can
rearrange this to get Cin < f_T / 2pi Rf fc^2.

You have Rf = 1.5k, fc = 10GHz, and let's guess f_T = 30GHz.
Just a guess. That gives us Cin < 0.03pF. That's a damn
small capacitance, which means (1) a very small back-biased
detector die, and (2) no budget for wiring capacitance. It
may be that the amplifier has Rf lower than 1.5k, followed
by some gain. That would help. Not an easy scene. That's
why most receivers in that bandwidth are sold as integrated
units. And most of the discrete TIA dies died out.



--
Thanks,
- Win