From: Jon Slaughter on
John Larkin wrote:
> On Tue, 22 Dec 2009 10:18:04 -0600, "Jon Slaughter"
> <Jon_Slaughter(a)Hotmail.com> wrote:
>
>> Is it possible to drive the gate of a high side n-ch mosfet using an
>> optocoupler to isolate and float the gate w.r.t to the source and
>> still be effective?
>>
>> I want to continuously control the gate of a high side n-ch mosfet
>> to prove a variable resistance for a high voltage load.
>>
>>
>> G = Gate, S = Source, D = Drain
>> OE = Opto Emitter, OC = Opto Collector
>>
>> Vcc--D
>>
>>
>> OC--R2--D
>> OE--G
>>
>> G--R1--S
>> |
>> Load
>> |
>> Gnd
>>
>>
>> The idea is simple, a resistor(R1) connects the gate to the source.
>> When no current is flowing the gate is then held at the same voltage
>> as the source and the mosfet is turned off.
>>
>> An optocoupler is added to control current through that gate/source
>> resistor which will "bias" the gate relative to the source and allow
>> turning on the mosfet. A simple simulation shows this works but I'm
>> not use how useful it is. Some protection mechanism for the opto
>> would be needed as well as driving the gate too high.
>>
>> The isolation is necessary because of the high voltage used. I'm not
>> worried about the "speed" as this isn't used for switching.
>>
>>
>
> If I understand your circuit, it puts a lot of voltage across the opto
> output. A shunt circuit wouldn't. But then there *are* optos with 400
> volt phototransistors. [1]
>
> A photovoltaic coupler would be nice, as it can drive the gate
> directly and doesn't need a high-side supply. They tend to be wimpy,
> 10s of uA output, so they would be pretty slow. An advantage is that
> there's no sneak current path to the load.
>
>
> Or do this maybe:
>
>
> V+-------+---------+
> | |
> | |
> Q |
> | |
> | d
> +--------g
> | s
> c |
> b |
> e |
> | |
> | |
> +---------+
> |
> |
> |
> load
>
> where Q is a Supertex depletion fet current limiter, cbe is the opto
> phototransistor, and there should be a zener g-s which I'm too lazy to
> draw. It does leak a litle current into the load.
>

My original idea was somewhat similar. The problem is that the initial state
is with the load recieving the full voltage. Hammy gave a datasheet where
they use a jfet to discharge the gate and keep it at 0V relative to the
source when no current. It should work well and also removes any need for
protection.

From: Hammy on
On Tue, 22 Dec 2009 20:32:05 -0600, "Jon Slaughter"
<Jon_Slaughter(a)Hotmail.com> wrote:


>
>Thanks, That might do the trick. A bit expensive though for something that
>seems relatively simple. The method they use with the fet for discharging
>the gate might be all I need with any old optocoupler method.
>
Yes but it saves you from having to make an isolated supply.

Page 18 of this pdf shows how to use a HS driver for continuous on
time. It also shows some of IR's HS drivers.

http://www.irf.com/technical-info/appnotes/an-978.pdf

Some of Fairchild's HS drivers.

FAN7371 4A, FAN7382 HI/LOW , FAN7361
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