From: Yaroslav Bulatov on 15 Jun 2010 02:30 I'd like to verify that the following expression is true for a,b real. It seems to hold numerically. 1/2 Log[(Exp[a + b] + Exp[-a - b])/(Exp[-a + b] + Exp[a - b])] == ArcTanh[Tanh[a] Tanh[b]] I tried Reduce and combinations of TrigToExp/Simplify with no luck, any suggestions?
From: Bill Rowe on 16 Jun 2010 05:36 On 6/15/10 at 2:30 AM, yaroslavvb(a)gmail.com (Yaroslav Bulatov) wrote: >I'd like to verify that the following expression is true for a,b >real. It seems to hold numerically. >1/2 Log[(Exp[a + b] + Exp[-a - b])/(Exp[-a + b] + Exp[a - b])] == >ArcTanh[Tanh[a] Tanh[b]] >I tried Reduce and combinations of TrigToExp/Simplify with no luck, >any suggestions? In[7]:= eq = 1/2 Log[(Exp[a + b] + Exp[-a - b])/(Exp[-a + b] + Exp[a - b])] == ArcTanh[Tanh[a] Tanh[b]]; In[8]:= Assuming[{a, b} \[Element] Reals, FullSimplify[TrigToExp[eq]]] Out[8]= True In[9]:= $Version Out[9]= 7.0 for Mac OS X x86 (64-bit) (February 19, 2009)
From: Peter Breitfeld on 16 Jun 2010 05:37 Yaroslav Bulatov wrote: > I'd like to verify that the following expression is true for a,b real. > It seems to hold numerically. > > 1/2 Log[(Exp[a + b] + Exp[-a - b])/(Exp[-a + b] + Exp[a - b])] == > ArcTanh[Tanh[a] Tanh[b]] > > I tried Reduce and combinations of TrigToExp/Simplify with no luck, > any suggestions? > At least for Reals you can verify it: 1/2 Log[(Exp[a + b] + Exp[-a - b])/(Exp[-a + b] + Exp[a - b])] == ArcTanh[Tanh[a] Tanh[b]] // TrigToExp // FullSimplify[#, {a, b} \[Element] Reals] & //Peter -- _________________________________________________________________ Peter Breitfeld, Bad Saulgau, Germany -- http://www.pBreitfeld.de
From: Daniel Huber on 16 Jun 2010 05:37 Hi, sometimes mathematica needds just a little help from a friend... Assuming[Element[{a, b,}, Reals], 1/2 Log[(Exp[a + b] + Exp[-a - b])/(Exp[-a + b] + Exp[a - b])] == ArcTanh[Tanh[a] Tanh[b]] // TrigToExp // Simplify] cheers, Daniel Am 15.06.2010 08:30, schrieb Yaroslav Bulatov: > I'd like to verify that the following expression is true for a,b real. > It seems to hold numerically. > > 1/2 Log[(Exp[a + b] + Exp[-a - b])/(Exp[-a + b] + Exp[a - b])] == > ArcTanh[Tanh[a] Tanh[b]] > > I tried Reduce and combinations of TrigToExp/Simplify with no luck, > any suggestions? >
From: Adriano Pascoletti on 16 Jun 2010 05:37 Considering the difference of the two sides the answer is returned instantly In[1]:== FullSimplify[1/2 Log[(Exp[a + b] + Exp[-a - b])/(Exp[-a + b] + Exp[a - b])] - ArcTanh[Tanh[a] Tanh[b]], a =E2=88=88 Reals && b =E2=88=88 Reals] Out[1]== 0 Adriano Pascoletti 2010/6/15 Yaroslav Bulatov <yaroslavvb(a)gmail.com> > I'd like to verify that the following expression is true for a,b real. > It seems to hold numerically. > > 1/2 Log[(Exp[a + b] + Exp[-a - b])/(Exp[-a + b] + Exp[a - b])] ==== > ArcTanh[Tanh[a] Tanh[b]] > > I tried Reduce and combinations of TrigToExp/Simplify with no luck, > any suggestions? > >
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