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From: tyler on 22 May 2010 00:00
(r1+150)^2 = (r1+200)^2 + r4^2 -2*(r1+200) * 499.1 * cos(16.177 )

r1^2 = (r1+200)^2 + 1267.9^2 -2*(r1+200) * 1267.9* cos (teta - 16.177 )


Unknown: r1, teta

please help me solve this using matlab!!!

Thanks
From: Torsten Hennig on 22 May 2010 02:49
> (r1+150)^2 = (r1+200)^2 + r4^2 -2*(r1+200) * 499.1 *
> cos(16.177 )
>
> r1^2 = (r1+200)^2 + 1267.9^2 -2*(r1+200) * 1267.9*
> cos (teta - 16.177 )
>
>
> Unknown: r1, teta
>
> please help me solve this using matlab!!!
>
> Thanks

The first equation is a linear equation in r1 alone ;
you can directly solve for r1.
Now insert the r1 obtained in the second equation
and solve for t(h)eta.

Best wishes
Torsten.
From: tyler on 23 May 2010 06:55
Thank You for your reply Torsten.

I have made a mistake in the equations, these are the fixed equations:

(r1+150)^2 = (r1+200)^2 + 499.1^2 -2*(r1+200) * 499.1 * cos(teta)

o
r1^2 = (r1+200)^2 + 1267.9^2 -2*(r1+200) * 1267.9* cos (teta - 16.177 )

Thank you for your kind help

Tyler
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