From: Tony Orlow on
Virgil wrote:
> In article <1175275431.897052.225580(a)y80g2000hsf.googlegroups.com>,
> "MoeBlee" <jazzmobe(a)hotmail.com> wrote:
>
>> On Mar 30, 9:39 am, Tony Orlow <t...(a)lightlink.com> wrote:
>>
>>> They
>>> introduce the von Neumann ordinals defined solely by set inclusion,
>> By membership, not inclusion.
>
> By both. Every vN natural is simultaneously a member of and subset of
> all succeeding naturals.
>

Yes, you're both right. Each of the vN ordinals includes as a subset
each previous ordinal, and is a member of the set of all ordinals. In
this sense, they are defined solely by the "element of" operator, or as
MoeBlee puts it, "membership". Members are included in the set. Or,
shall we call it a "club"? :)

Anyway, my point is that the recursive nature of the definition of the
"set" introduces a notion of order which is not present in the mere idea
of membership. Order is defined by x<y ^ y<z -> x<z. This is generally
interpreted as pertaining to real numbers or some subset thereof, but if
you interpret '<' as "subset of", then the same rule holds. I suppose
this is one reason why I think a proper subset should ALWAYS be
considered a lesser set than its proper superset. It's less than the
superset by the very mechanics of what "less than" means.

>>> and
>>> yet, surreptitiously introduce the notion of order by means of this set.
>> "Surreptitiously". You don't know an effing thing you're talking
>> about. Look at a set theory textbook (such as Suppes's 'Axiomatic Set
>> Theory') to see the explicit definitions.
>
> On the other hand, Tony Orlow is considerably less of an ignoramus than
> Lester Zick.

Why, thank you, Virgil. That's the nicest thing you've ever said to me.

:D
From: Tony Orlow on
Virgil wrote:
> In article <460d4813(a)news2.lightlink.com>,
> Tony Orlow <tony(a)lightlink.com> wrote:
>
>
>> An actually infinite sequence is one where there exist two elements, one
>> of which is an infinite number of elements beyond the other.
>
> Not in any standard mathematics.

Well, "actually infinite" isn't a defined term in standard mathematics.

>
> In standard mathematics, an infinite sequence is o more than a function
> whose domain is the set of naturals, no two of which are more that
> finitely different. The codmain of such a function need not have any
> particular structure at all.

That's a countably infinite sequence. Standard mathematics doesn't allow
for uncountable sequences like the adics or T-riffics, because it's been
politically agreed upon that we skirt that issue and leave it to the
clerics. However, where every element of a set has a well defined
successor and predecessor, it's a sequence of some sort.

Is the 2-adic really a pair of countable sets, counting upward from
....000 and downward from ..111? It would appear so, at first glance, but
those two sequences count toward each other. They're really two elements
of a sequence, infinitely far apart, in a single sequence. The problem
is, we can't express any number halfway between the two.

The T-riffics are supposed to address the issue of that point of
intersection by declaring a bit at oo. In that system we count up from
000...000 to 111...111, the midpoint obviously being the transition from
011...111 to 100...000. The ellipses may represent a finite or an
infinite number of bits, without affecting the arithmetic. We can say
that left most bit is number oo, and we're counting from 0 to
2^(oo+1)-1. In that case, the sequence is definitely uncountable, even
though the set or T-riffic numbers we can represent with finite strings
is countable.

Tony
From: Tony Orlow on
Virgil wrote:
> In article <460d489b(a)news2.lightlink.com>,
> Tony Orlow <tony(a)lightlink.com> wrote:
>
>> Lester Zick wrote:
>>> On Thu, 29 Mar 2007 09:37:21 -0500, Tony Orlow <tony(a)lightlink.com>
>>> wrote:
>>>
>>>>> Just ask yourself, Tony, at what magic point do intervals become
>>>>> infinitesimal instead of finite? Your answer should be magnitudes
>>>>> become infintesimal when subdivision becomes infinite.
>>>> Yes.
>>> Yes but that doesn't happen until intervals actually become zero.
>>>
>>>> But the term
>>>>> "infinite" just means undefined and in point of fact doesn't become
>>>>> infinite until intervals become zero in magnitude. But that never
>>>>> happens.
>>>> But, but, but. No, "infinite" means "greater than any finite number" and
>>>> infinitesimal means "less than any finite number", where "less" means
>>>> "closer to 0" and "more" means "farther from 0".
>>> Problem is you can't say when that is in terms of infinite bisection.
>>>
>>> ~v~~
>> Cantorians try with their lame "aleph_0". Better you get used to the
>> fact that there is no more a smallest infinity than a smallest finite,
>> largest finite, or smallest or largest infinitesimal. Those things
>> simply don't exist, except as phantoms.
>
> But all other mathematical objects are equally fantastic, having no
> physical reality, but existing only in the imagination. So any statement
> of mathematical existence is always relative to something like a system
> of axioms.

Sure, but the question is whether any such assumption of existence
introduces nonsense into your system. With the very basic assumption
that subtracting a positive amount from anything makes it less, the
inductive logic that proves there is no largest finite can be applied to
prove there is no smallest infinite:

Assume we are working with positive numbers. Subtract a finite number
from an infinite number. The result must be an infinite number, because
if it were finite, then its addition to the finite number we subtracted
would not yield the original infinite number. The result must be smaller
than the original infinite number, because we have subtracted a positive
amount from it. Therefore, for any infinite number, one can produce a
smaller infinite number, and there is thus no smallest infinite number.

In order to support the notion of aleph_0, one has to discard the basic
notion of subtraction in the infinite case. That seems like an undue
sacrifice to me, for the sake of nonsense. Sorry.

Tony
From: Tony Orlow on
Mike Kelly wrote:
> On 30 Mar, 18:25, Tony Orlow <t...(a)lightlink.com> wrote:
>> Lester Zick wrote:
>>> On Thu, 29 Mar 2007 09:37:21 -0500, Tony Orlow <t...(a)lightlink.com>
>>> wrote:
>>>>>> If n is
>>>>>> infinite, so is 2^n. If you actually perform an infinite number of
>>>>>> subdivisions, then you get actually infinitesimal subintervals.
>>>>> And if the process is infinitesimal subdivision every interval you get
>>>>> is infinitesimal per se because it's the result of a process of
>>>>> infinitesimal subdivision and not because its magnitude is
>>>>> infinitesimal as distinct from the process itself.
>>>> It's because it's the result of an actually infinite sequence of finite
>>>> subdivisions.
>>> And what pray tell is an "actually infinite sequence"?
>>>> One can also perform some infinite subdivision in some
>>>> finite step or so, but that's a little too hocus-pocus to prove. In the
>>>> meantime, we have at least potentially infinite sequences of
>>>> subdivisions, increments, hyperdimensionalities, or whatever...
>>> Sounds like you're guessing again, Tony.
>>> ~v~~
>> An actually infinite sequence is one where there exist two elements, one
>> of which is an infinite number of elements beyond the other.
>>
>> 01oo
>
> Under what definition of sequence?
>
> --
> mike.
>

A set where each element has a well defined unique successor within the
set. Good enough?

tony.
From: Tony Orlow on
stephen(a)nomail.com wrote:
> In sci.math Virgil <virgil(a)comcast.net> wrote:
>> In article <460d4813(a)news2.lightlink.com>,
>> Tony Orlow <tony(a)lightlink.com> wrote:
>
>
>>> An actually infinite sequence is one where there exist two elements, one
>>> of which is an infinite number of elements beyond the other.
>>
>> Not in any standard mathematics.
>
> It is not even true in Tony's mathematics, at least it was not true
> the last time he brought it up. According to this
> definition {1, 2, 3, ... } is not actually infinite, but
> {1, 2, 3, ..., w} is actually infinite. However, the last time this
> was pointed out, Tony claimed that {1, 2, 3, ..., w} was not
> actually infinite.
>
> Stephen

No, adding one extra element to a countable set doesn't make it
uncountable. If all other elements in the sequence are a finite number
of steps from the start, and w occurs directly after those, then it is
one step beyond some step which is finite, and so is at a finite step.

Try (...000, ..001, ...010, ......, ...101, ...110, ...111)

Tony