From: Virgil on
In article <460e8251(a)news2.lightlink.com>,
Tony Orlow <tony(a)lightlink.com> wrote:

> Mike Kelly wrote:
> > On 31 Mar, 13:41, Tony Orlow <t...(a)lightlink.com> wrote:
> >> Mike Kelly wrote:
> >>> On 30 Mar, 18:25, Tony Orlow <t...(a)lightlink.com> wrote:
> >>>> Lester Zick wrote:
> >>>>> On Thu, 29 Mar 2007 09:37:21 -0500, Tony Orlow <t...(a)lightlink.com>
> >>>>> wrote:
> >>>>>>>>
> >>>>>>>> If n is
> >>>>>>>> infinite, so is 2^n. If you actually perform an infinite number of
> >>>>>>>> subdivisions, then you get actually infinitesimal subintervals.
> >>>>>>> And if the process is infinitesimal subdivision every interval you
> >>>>>>> get
> >>>>>>> is infinitesimal per se because it's the result of a process of
> >>>>>>> infinitesimal subdivision and not because its magnitude is
> >>>>>>> infinitesimal as distinct from the process itself.
> >>>>>> It's because it's the result of an actually infinite sequence of
> >>>>>> finite
> >>>>>> subdivisions.
> >>>>> And what pray tell is an "actually infinite sequence"?
> >>>>>> One can also perform some infinite subdivision in some
> >>>>>> finite step or so, but that's a little too hocus-pocus to prove. In
> >>>>>> the
> >>>>>> meantime, we have at least potentially infinite sequences of
> >>>>>> subdivisions, increments, hyperdimensionalities, or whatever...
> >>>>> Sounds like you're guessing again, Tony.
> >>>>> ~v~~
> >>>> An actually infinite sequence is one where there exist two elements, one
> >>>> of which is an infinite number of elements beyond the other.
> >>>> 01oo
> >>> Under what definition of sequence?
> >>> --
> >>> mike.
> >> A set where each element has a well defined unique successor within the
> >> set.
> >
> > So any set is a sequence? For any set, take the successor of each
> > element as itself.
>
> There is no successor in a pure set. That only occurs in a discrete
> linear order.
>
> >
> >> Good enough?
> >
> > You tell me. Did you mean to say "a sequence is a set"? If so, good
> > enough.
> >
> > --
> > mike.
> >
>
> Not exactly, and no, what I said is not good enough.
>
> A set with an order where each element has a unique successor is a
> forward-infinite sequence. Each can have a unique predecessor, and then
> it's backward-infinite. And if every element has both a unique successor
> and predecessor, then it's bi-infinite, like the integers, or within the
> H-riffics, the reals. One can further impose that x<y ->~y<x, to
> eliminate circularity.
>
> Good enough? Probably not yet.


You are right, not yet.

Every "sequence" must be a totally ordered set which is order isomorphic
either to the ordered set of naturals, if it has a first element, or to
the ordered set of integers, if it does not have a first element.

Note that since the obvious mapping between the natural numbers and the
negative integers is an order isomorphism with order reversal, one need
not include that third case separately.
From: Lester Zick on
On Fri, 30 Mar 2007 12:13:57 -0500, Tony Orlow <tony(a)lightlink.com>
wrote:

>Lester Zick wrote:
>> On Thu, 29 Mar 2007 09:37:21 -0500, Tony Orlow <tony(a)lightlink.com>
>> wrote:
>>
>>>>> It's the same as Peano.
>>>> Not it isn't, Tony. Cumulative addition doesn't produce straight lines
>>>> or even colinear straight line segments. Some forty odd years ago at
>>>> the Academy one of my engineering professors pointed out that just
>>>> because there is a stasis across a boundary doesn't necessarily mean
>>>> that there is no flow across the boundary only that the net flow back
>>>> and forth is zero.I've always been impressed by the line of reasoning.
>>> The question is whether adding an infinite number of finite segments
>>> yields an infinite distance.
>>
>> I have no idea what you mean by "infinite" Tony. An unlimited number
>> of line segments added together could just as easily produce a limited
>> distance.
>>
>> ~v~~
>
>Not unless the vast majority are infinitesimal.

No that isn't what I'm talking about. You seem to assume consecutive
segments would have to be colinear and lie along a straight line. I've
already tried to explain why this isn't so. They could all connect in
completely different directions even though mathematikers commonly
assume they somehow for some reason would very plolitely line up in
one direction alone. Line segments are only connected by points, Tony.
And their direction is not determined by those points because there is
no definable slope at point intersections.

> If there is a nonzero
>lower bound on the interval lengths, an unlimited number concatenated
>produces unlimited distance.

And if segments were all of equal finite size we could make a finite
plane hexagon out them which would be quite limited in distance.

~v~~
From: Virgil on
In article <460e82b1(a)news2.lightlink.com>,
Tony Orlow <tony(a)lightlink.com> wrote:


> As I said to Brian, it's provably the size of the set of finite natural
> numbers greater than or equal to 1. No, there is no last finite natural,
> and no, there is no "size" for N. Aleph_0 is a phantom.

All numbers are equally phantasmal in the physical world and equally
real in the mental world.
From: Lester Zick on
On Fri, 30 Mar 2007 12:24:12 -0500, Tony Orlow <tony(a)lightlink.com>
wrote:

>Lester Zick wrote:
>> On Thu, 29 Mar 2007 09:37:21 -0500, Tony Orlow <tony(a)lightlink.com>
>> wrote:
>>
>>>>> Add 1 n
>>>>> times to 0 and you get n. If n is infinite, then n is infinite.
>>>> This is reasoning per say instead of per se.
>>>>
>>> Pro se, even. If the first natural is 1, then the nth is n, and if there
>>> are n of them, there's an nth, and it's a member of the set. Just ask
>>> Mueckenheim.
>>
>> Pro se means for yourself and not for itself.
>
>In my own behalf, yes.
>
>>I don't have much to do
>> with Mueckenheim because he seems more interested in special pleading
>> than universal truth. At least his assumptions of truth don't seem
>> especially better or worse than any other assumptions of truth.
>>
>> ~v~~
>
>He has some valid points about the condition of the patient, but of
>course he and I have different remedies.

Some of which may prove deadly.

~v~~
From: Lester Zick on
On Fri, 30 Mar 2007 12:22:53 -0600, Virgil <virgil(a)comcast.net> wrote:

>In article <460d4813(a)news2.lightlink.com>,
> Tony Orlow <tony(a)lightlink.com> wrote:
>
>
>> An actually infinite sequence is one where there exist two elements, one
>> of which is an infinite number of elements beyond the other.
>
>Not in any standard mathematics.
>
>In standard mathematics, an infinite sequence is o more than a function
>whose domain is the set of naturals, no two of which are more that
>finitely different. The codmain of such a function need not have any
>particular structure at all.

Oh that really clears it all up.

~v~~