From: Nam Nguyen on
Nam Nguyen wrote:
> Marshall wrote:
>> On Jun 7, 7:36 pm, Nam Nguyen <namducngu...(a)shaw.ca> wrote:
>>> Marshall wrote:
>>>> On Jun 6, 8:30 pm, "Jesse F. Hughes" <je...(a)phiwumbda.org> wrote:
>>>>> Marshall <marshall.spi...(a)gmail.com> writes:
>>>>>> Prolly a bad habit in a forum that's so oriented on FOL.
>>>>> I don't know whether it's a bad habit or not, but Nam claims to be
>>>>> sticking closely to Shoenfield's presentation, and in that text, the
>>>>> author treats the two formulas differently.
>>>> Right.
>>> Of course Shoenfield did treat the 2 formulas differently: he mentioned
>>> 1 kind on pg. 19 but not the other kind. But how does that have anything
>>> to bear on the arguments here? Specifically, how does such observation
>>> help you to prove there's no context in FOL in which x=x (or even
>>> Ax[x=x])
>>> is false?
>>
>> See any of the previous hundreds of messages pointing out how
>> completely untenable your position is. My favorite was Phil Carmody's:
>>
>> "I always try skip past your long drawn-out threads, and have never
>> spend enough time to ascertain whether you are a loon or not. I think
>> finally I have the evidence that you really don't have a clue what
>> you're talking about.... *PLONK*."
>
> And you call that _your_ _technical_ refutes?

So in the end Marshall and few others are wrong in saying there's
there's no context in FOL in which x=x (Ax[x=x]) is false.
From: Marshall on
On Jun 7, 8:02 pm, Nam Nguyen <namducngu...(a)shaw.ca> wrote:
>
> So in the end Marshall and few others are wrong in saying there's
> there's no context in FOL in which x=x (Ax[x=x]) is false.

A "few" others? You have been the butt of near-universal ridicule.
Only the tireless crusader known as Transfer Principle has said
anything in your defense, and he's a cheap date.

Basically, EVERYONE disagrees with you.


Marshall
From: Nam Nguyen on
Marshall wrote:
> On Jun 7, 8:02 pm, Nam Nguyen <namducngu...(a)shaw.ca> wrote:
>> So in the end Marshall and few others are wrong in saying there's
>> there's no context in FOL in which x=x (Ax[x=x]) is false.
>
> A "few" others? You have been the butt of near-universal ridicule.
> Only the tireless crusader known as Transfer Principle has said
> anything in your defense, and he's a cheap date.

Come on Marshall. You couldn't technically support your refute
then just accept it, or at least keep silent. Your idiotic
calling _somebody else_ a "cheap date" to cover your incompetence
is very ... very pathetic!


>
> Basically, EVERYONE disagrees with you.

I don't know for fact if by now _everybody_ but you agrees or
disagrees with me. I only know at least you do disagree and
_you could NOT support your position_.

Bye.
From: Daryl McCullough on
Nam Nguyen says...

>Of course Shoenfield did treat the 2 formulas differently: he mentioned
>1 kind on pg. 19 but not the other kind. But how does that have anything
>to bear on the arguments here? Specifically, how does such observation
>help you to prove there's no context in FOL in which x=x (or even Ax[x=x])
>is false?

Because (Ax x=x) is true in every model.

--
Daryl McCullough
Ithaca, NY

From: Marshall on
On Jun 7, 8:47 pm, Nam Nguyen <namducngu...(a)shaw.ca> wrote:
>
> > Basically, EVERYONE disagrees with you.
>
> I don't know for fact if by now _everybody_ but you agrees or
> disagrees with me.

I guess we can add "universal disagreement" to the list of
things Nam doesn't recognize about a conversation.

> I only know at least you do disagree and
> _you could NOT support your position_.

I supported it fine. I just wasn't able to convince
this one particular talentless buffoon.


Marshall