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From: Ostap Bender on 22 May 2010 01:03
I have a very elegant proof that P = NP if and only if N = 1 or P = 0,
but the margins of the Usenet are too narrow for me to write down this
proof. Email me for details.
From: Etienne Rousee on 22 May 2010 05:25
Le 22/05/2010 07:03, Ostap Bender a �crit :
> I have a very elegant proof that P = NP if and only if N = 1 or P = 0,
> but the margins of the Usenet are too narrow for me to write down this
> proof. Email me for details.

There are others solutions in Z/nZ if n is not a prime number.
For example N = 4 and P = 2 in Z/6Z

--

Etienne

From: Ostap Bender on 22 May 2010 19:09
On May 22, 2:25 am, Etienne Rousee <etie...(a)rousee.org> wrote:
> Le 22/05/2010 07:03, Ostap Bender a écrit :
>
> > I have a very elegant proof that P = NP if and only if N = 1 or P = 0,
> > but the margins of the Usenet are too narrow for me to write down this
> > proof.  Email me for details.
>
> There are others solutions in Z/nZ if n is not a prime number.
> For example N = 4 and P = 2 in Z/6Z

Well, I was restricting myself to fields, but with hard work,
humankind may some day be able to generalize my brilliant results to
other, less divisive rings.
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