From: William Elliot on
What are the solutions to the equations

sin^-1 x = 1/sin x,

cos^-1 x = 1/cos x?

Since
sin^-2 x = 1/sin^2 x,
x can be anything not in pi.Z.

Since
cos^-2 x = 1/cos^2 x?
x can be anything not in pi(Z + 1/2).
From: Henry on
On 30 July, 05:56, William Elliot <ma...(a)rdrop.remove.com> wrote:
> What are the solutions to the equations
>
>         sin^-1 x = 1/sin x,

If "sin^-1 x" means arcsin(x) then there are real solutions of
about +/- 0.944039.




From: Ray Vickson on
On Jul 29, 9:56 pm, William Elliot <ma...(a)rdrop.remove.com> wrote:
> What are the solutions to the equations
>
>         sin^-1 x = 1/sin x,
>
>         cos^-1 x = 1/cos x?
>
> Since
>         sin^-2 x = 1/sin^2 x,

If sin^-1 x means arcsin(x), then what the heck does sin^-2 x mean? Is
it arcsin(arcsin(x))?

R.G. Vickson


> x can be anything not in pi.Z.
>
> Since
>         cos^-2 x = 1/cos^2 x?
> x can be anything not in pi(Z + 1/2).

From: William Elliot on
On Fri, 30 Jul 2010, Ray Vickson wrote:

> On Jul 29, 9:56�pm, William Elliot <ma...(a)rdrop.remove.com> wrote:
>> What are the solutions to the equations
>>
>> sin^-1 x = 1/sin x,
>>
>> cos^-1 x = 1/cos x?
>>
>> Since
>> sin^-2 x = 1/sin^2 x,
>
> If sin^-1 x means arcsin(x), then what the heck does sin^-2 x mean? Is
> it arcsin(arcsin(x))?
>
Does sin^2 x = sin sin x?

>> x can be anything not in pi.Z.
>>
>> Since
>> cos^-2 x = 1/cos^2 x?
>> x can be anything not in pi(Z + 1/2).
>
>
From: Ray Vickson on
On Jul 31, 12:42 am, William Elliot <ma...(a)rdrop.remove.com> wrote:
> On Fri, 30 Jul 2010, Ray Vickson wrote:
> > On Jul 29, 9:56 pm, William Elliot <ma...(a)rdrop.remove.com> wrote:
> >> What are the solutions to the equations
>
> >> sin^-1 x = 1/sin x,
>
> >> cos^-1 x = 1/cos x?
>
> >> Since
> >> sin^-2 x = 1/sin^2 x,
>
> > If sin^-1 x means arcsin(x), then what the heck does sin^-2 x mean? Is
> > it arcsin(arcsin(x))?
>
> Does sin^2 x = sin sin x?

No, but that is not the issue: YOU used the notation sin^-2 x, not me.
Why can't you just say what you mean? Is that so hard?

R.G. Vickson


>
> >> x can be anything not in pi.Z.
>
> >> Since
> >> cos^-2 x = 1/cos^2 x?
> >> x can be anything not in pi(Z + 1/2).
>
>