From: BlindBaby on
On Thu, 10 Jun 2010 19:59:50 -0700, John Larkin
<jjlarkin(a)highNOTlandTHIStechnologyPART.com> wrote:

>On 10 Jun 2010 17:55:23 -0700, Winfield Hill
><Winfield_member(a)newsguy.com> wrote:
>
>>John Larkin wrote...
>>>
>>> I have never called myself a "judge", and Win has never called
>>> himself a "master." You and JT call us that, so you can then
>>> abuse us for saying things we never said. How lame.
>>
>> That's correct. I work hard at what I do, but I'm always
>> on the lookout for mistakes I may make, or more often,
>> things I don't yet understand. Hopefully I'll not pipe
>> up about something I don't yet understand, but oops, oops,
>> sometimes one doesn't yet know that they don't understand
>> something, or they may just make a silly thoughtless mistake.
>
>A lot depends on how fragile your ego is. If you are determined to
>always be "right" in public, or you are determined that someone else
>is always wrong, you'll be a fathead and not learn anything.
>
>Of course, there are some people who are AlwaysWrong.
>
>John

John gazes into the mirror (guffaw) and details for us his... err...
our dilemma.

Yeah... sure... bub.
From: dagmargoodboat on
John Larkin wrote:
> dagmargoodb...(a)yahoo.com wrote:
> >John Larkin wrote:

> >> In my oscillator, a c-b schottky diode would keep the transistor c-b
> >> junction from conducting, and keep the transistor out of saturation.
> >> Tempco would still be low. That simplifies things considerably. Not
> >> bad.
>
> >Good idea.
>
> >> >Oh, and John's oscillator really swings ~ 2* (Vcc + Vbe), not 2* (Vcc
> >> >- Vbe). Reason being, the AGC operates as the average base voltage
> >> >gets sucked down to near 0v, killing the gain.
>
> >> I seem to recall the DC base voltage being about +.6. So the collector
> >> swings to just about zero, and the AC output is 2*Vcc p-p. Somebody
> >> could Spice this, if they were interested, and see exactly what
> >> happens.
>
> >I Spice'd all the circuits I posted.
>
> >> The transformer ratio gets involved some, too.
>
> >Yep, but to a 1rst order: average emitter voltage = 0, ignore the
> >swing 'cause it's small, and that gets you pretty close. V(b) = 120mV
> >in my 5KHz example.
>
>
> How much p-p voltage on the emitter?

1 volt. That might be a bit hot, as I noted in the post. I did that
on purpose, thinking a smaller conduction angle would give better
frequency stability. You know, let the L-C ring unmolested as much as
possible? Might not be helpful though--if the drive is sine-ish, the
tendency to pull might not apply. Not sure.

> That low a DC base voltage suggests more like class-C action. With
> less turns on the emitter winding, the thing gets more class A-ish,
> and I'd expect the DC base voltage to go up some. I think.

Yes, class-C.

> I wonder what happens to the DC base voltage as the base bias resistor
> changes. I'm not even sure which direction things will go.
>
> Complicated, for 5 parts.

I like the schottky. Takes trr(b-c) out of the equation.

James
From: John Larkin on
On Thu, 10 Jun 2010 21:45:08 -0700 (PDT), dagmargoodboat(a)yahoo.com
wrote:

>John Larkin wrote:
>> dagmargoodb...(a)yahoo.com wrote:
>> >John Larkin wrote:
>
>> >> In my oscillator, a c-b schottky diode would keep the transistor c-b
>> >> junction from conducting, and keep the transistor out of saturation.
>> >> Tempco would still be low. That simplifies things considerably. Not
>> >> bad.
>>
>> >Good idea.
>>
>> >> >Oh, and John's oscillator really swings ~ 2* (Vcc + Vbe), not 2* (Vcc
>> >> >- Vbe). Reason being, the AGC operates as the average base voltage
>> >> >gets sucked down to near 0v, killing the gain.
>>
>> >> I seem to recall the DC base voltage being about +.6. So the collector
>> >> swings to just about zero, and the AC output is 2*Vcc p-p. Somebody
>> >> could Spice this, if they were interested, and see exactly what
>> >> happens.
>>
>> >I Spice'd all the circuits I posted.
>>
>> >> The transformer ratio gets involved some, too.
>>
>> >Yep, but to a 1rst order: average emitter voltage = 0, ignore the
>> >swing 'cause it's small, and that gets you pretty close. V(b) = 120mV
>> >in my 5KHz example.
>>
>>
>> How much p-p voltage on the emitter?
>
>1 volt. That might be a bit hot, as I noted in the post. I did that
>on purpose, thinking a smaller conduction angle would give better
>frequency stability. You know, let the L-C ring unmolested as much as
>possible? Might not be helpful though--if the drive is sine-ish, the
>tendency to pull might not apply. Not sure.

I prefer smaller drive, a tenth or so p-p on the emitter. Maybe even
less, basically class A.

The whole thing behaves differently if the secondary drive is large
and the transistor conduction angle is small: the emitter voltage will
swing down, way below ground, and pull the base down with it before
the collector voltage gets down to ground... blasting a spike of
collector current into the tank. Then it will swing way up and turn
the base off. Brutality! Chaos!

I prefer a more delicate touch: the collector dips down elegantly,
like a swan landing on a pond. It just barely touches the water, err,
emitter, and together they remove a bit of charge from the base cap.
And then it flies away. Did I mention the sunset in the background?

John

From: dagmargoodboat on
On Jun 10, 11:45 pm, dagmargoodb...(a)yahoo.com wrote:
> John Larkin wrote:
> > dagmargoodb...(a)yahoo.com wrote:
> > >John Larkin  wrote:

> > >> The transformer ratio gets involved some, too.
>
> > >Yep, but to a 1rst order: average emitter voltage = 0, ignore the
> > >swing 'cause it's small, and that gets you pretty close.  V(b) = 120mV
> > >in my 5KHz example.
>
> > How much p-p voltage on the emitter?
>
> 1 volt.  That might be a bit hot, as I noted in the post.  I did that
--^^^^^^

Ooops. That was for another sim, which uses 1mH and 10uH. The posted
5 KHz ckt used 1mH / 25uH, so the emitter swing was about 1.8v p-p.

James Arthur
From: Grant on
On Thu, 10 Jun 2010 18:11:44 -0700, John Larkin <jjlarkin(a)highNOTlandTHIStechnologyPART.com> wrote:

>On Thu, 10 Jun 2010 17:21:02 -0700 (PDT), MooseFET
><kensmith(a)rahul.net> wrote:
>
>>On Jun 11, 12:01 am, John Larkin
>>[....]
>>> I don't think so. People designed radar, magnetrons and klystrons and
>>> waveguides and servos and all that, without computers. They did the
>>> math. Early computers were obviously designed without help from
>>> computers.
>>
>><PITA>
>>Make that "electronic computers". At one time, a computer was
>>a person who computed. Companies had rooms full of people
>>grinding through the numbers to make sure that the sums were
>>right.
>></PITA>
>
>
><OLDFARTSTORY>
>
>My first real job was a research assistant in microwave spectroscopy,
>a summer tech job. Two grad students on the same project spent the
>entire summer hunched over a Friden calculator in a small room,
>calculating rotational resonances for some organic thing. My PC could
>do all that now in, probably, a millisecond.
>
></OLDFARTSTORY>
>
>
>
>>
>>There were also some analog computers and mechanical
>>computers. Each generation has used the tools made by
>>the previous. Just try to imagine designing with Roman
>>numerals and not even a slide rule.
>>
>>
>>> I don't use Spice a lot, and could certainly get along without it. It
>>> is helpful when evaluating nonlinear systems, where math solutions >get messy.
>>
>>I use spice as a sanity check. Sometimes it even finds some.
>>
>>LTSpice is also nice for making a schematic to email to someone.
>
>It is just about the only portable schematic format the industry has
>ever seen. Not a bad editor, but the circuits seem to wander all over
>the screen as you zoom. I have to keep selecting my whole circuit and
>dragging it back into sight.

Minor problem, return for full refund? :)

Grant.
>
>John
>
--
http://bugs.id.au/