From: Andre Hautot on
x= Sqrt[2] + Sqrt[3] + Sqrt[5] is an algebraic number

MinimalPolynomial[Sqrt[2] + Sqrt[3] + Sqrt[5], x]

returns the polynomial : 576 - 960 x^2 + 352 x^4 - 40 x^6 + x^8 as
expected

Now suppose we only know the N first figures of x (N large enough), say
: N[x,50] = 5.3823323474417620387383087344468466809530954887989

is it possible to recognize x as a probably algebraic number and to
deduce its minimal polynomial ?

Thanks for a hint,
ahautot


From: Bob Hanlon on

Use RootApproximant. In this case it takes at least 33-digit precision

x = Sqrt[2] + Sqrt[3] + Sqrt[5];

RootApproximant /@ Table[N[x, n], {n, 30, 35}] // ColumnForm


Bob Hanlon

---- Andre Hautot <ahautot(a)ulg.ac.be> wrote:

=============
x= Sqrt[2] + Sqrt[3] + Sqrt[5] is an algebraic number

MinimalPolynomial[Sqrt[2] + Sqrt[3] + Sqrt[5], x]

returns the polynomial : 576 - 960 x^2 + 352 x^4 - 40 x^6 + x^8 as
expected

Now suppose we only know the N first figures of x (N large enough), say
: N[x,50] = 5.3823323474417620387383087344468466809530954887989

is it possible to recognize x as a probably algebraic number and to
deduce its minimal polynomial ?

Thanks for a hint,
ahautot



From: Robert Coquereaux on
What about

z= 5.3823323474417620387383087344468466809530954887989;

In[1]:= RootApproximant[z,8]
Out[1]= Root[576-960 #1^2+352 #1^4-40 #1^6+#1^8&,8] (* you get back
your minimal polynomial in one stroke *)

In[2]:= ToRadicals[%,8]]
Out[2]= Sqrt[2 (5+Sqrt[15]+2 Sqrt[4+Sqrt[15]])]

In[3]:= RootReduce[% ==Sqrt[2]+Sqrt[3]+Sqrt[5]] (* check *)
Out[3]= True

Notice that RootApproximant stabilizes after s=8

In[4]:= Table[RootApproximant[z, s], {s, 7, 10}]
Out[4]= {Root[421813 + 165807 #1 + 636917 #1^2 + 855877 #1^3 - 1050961
#1^4 -
172764 #1^5 - 22412 #1^6 + 15697 #1^7 &, 3],
Root[576 - 960 #1^2 + 352 #1^4 - 40 #1^6 + #1^8 &, 8],
Root[576 - 960 #1^2 + 352 #1^4 - 40 #1^6 + #1^8 &, 8],
Root[576 - 960 #1^2 + 352 #1^4 - 40 #1^6 + #1^8 &, 8]}

However there are many (!) algebraic numbers that share the same first
N digits...
If you give less digits for z, you will get another candidate for the
minimal polynomial.

In[5]:= Table[RootApproximant[N[z,s],8],{s,25,27}]
Out[5]= {
Root[443+275 #1+146 #1^2-261 #1^3+234 #1^4-13 #1^5-340 #1^6-126
#1^7+35 #1^8&,2],
Root[576-960 #1^2+352 #1^4-40 #1^6+#1^8&,8],
Root[576-960 #1^2+352 #1^4-40 #1^6+#1^8&,8]}

In any case, you will get get an answer (a polynomial) even if x is
not algebraic, whatever the number of digits you give.
In[6]:= Table[RootApproximant[N[Pi,10],s],{s,8,10}]
Out[6]= {Root[5-#1+7 #1^2-14 #1^3-3 #1^4-#1^5+#1^6&,2],Root[1+#1+6
#1^2+#1^3-5 #1^4-5 #1^5+2 #1^6&,2],Root[1+#1+6 #1^2+#1^3-5 #1^4-5
#1^5+2 #1^6&,2]}

To recognize a number x as algebraic, from its N first figures, is
impossible.
And to recognize it as "probably algebraic", as you write, does not
make much sense to me (using measure theory would give probability 0,
anyway).
Now, if you already know that, for some reason, x is algebraic, like
in your example, using RootApproximant may help you to recognize it.

Robert



Le 29 d=E9c. 09 =E0 07:20, Andre Hautot a =E9crit :

> x= Sqrt[2] + Sqrt[3] + Sqrt[5] is an algebraic number
>
> MinimalPolynomial[Sqrt[2] + Sqrt[3] + Sqrt[5], x]
>
> returns the polynomial : 576 - 960 x^2 + 352 x^4 - 40 x^6 + x^8 as
> expected
>
> Now suppose we only know the N first figures of x (N large enough), =

> say
> : N[x,50] = 5.3823323474417620387383087344468466809530954887989
>
> is it possible to recognize x as a probably algebraic number and to
> deduce its minimal polynomial ?
>
> Thanks for a hint,
> ahautot
>
>


From: David W. Cantrell on
Andre Hautot <ahautot(a)ulg.ac.be> wrote:
> x= Sqrt[2] + Sqrt[3] + Sqrt[5] is an algebraic number
>
> MinimalPolynomial[Sqrt[2] + Sqrt[3] + Sqrt[5], x]
>
> returns the polynomial : 576 - 960 x^2 + 352 x^4 - 40 x^6 + x^8 as
> expected
>
> Now suppose we only know the N first figures of x (N large enough), say
> : N[x,50] = 5.3823323474417620387383087344468466809530954887989
>
> is it possible to recognize x as a probably algebraic number and to
> deduce its minimal polynomial ?

In[1]:= RootApproximant[5.3823323474417620387383087344468466809530954887989]

Out[1]= Root[576 - 960*#1^2 + 352*#1^4 - 40*#1^6 + #1^8 & , 8]

David

From: Francesco on

"Andre Hautot" <ahautot(a)ulg.ac.be> ha scritto nel messaggio
news:hhc7a1$2o2$1(a)smc.vnet.net...
> x= Sqrt[2] + Sqrt[3] + Sqrt[5] is an algebraic number
>
> MinimalPolynomial[Sqrt[2] + Sqrt[3] + Sqrt[5], x]
>
> returns the polynomial : 576 - 960 x^2 + 352 x^4 - 40 x^6 + x^8 as
> expected
>
> Now suppose we only know the N first figures of x (N large enough), say
> : N[x,50] = 5.3823323474417620387383087344468466809530954887989
>
> is it possible to recognize x as a probably algebraic number and to
> deduce its minimal polynomial ?

I have the impression that in your case the MinimalPolynomial is simply
x-N.

If you add a figure to N, let say ......9891, you will get a different
polynomial.



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