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From: Piotr Wyderski on 17 Jan 2010 21:49

Is it possible to overload a method M in such a way that the
variant is chosen based on the number of lambda parameters?
For example:

struct S {

template <typename T> void M(...
};

S s;

s.M([](double v) { return v; }); // Variant #1
s.M([](double v, int x, int y) { return v + x + y; }); // Variant #2

If yes, then how?

BTW, what _exactly_ are lambdas expected to be? They are not
functions, as they are passed by a template type parameter, but they
are also not types, as it's impossible to declare:

typedef [](){} nop_t;

Best regards
Piotr Wyderski


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