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From: James Westby on 10 Jan 2006 15:51
haig wrote:
> "VisionSet" <spam(a)ntlworld.com> wrote in news:WOUwf.32187$yu.5572
> @newsfe6-gui.ntli.net:
>
>
>
>>word.charAt(i) returns a char primitive, you can not call methods on a
>>primitive ie equals(String str)
>>For that matter you must make the two objects of the same type to make
>>equals meaningful.
>>
>>so
>>
>>objectOneOfTypeA.equals(objectTwoOfTypeA) // is okay
>>
>>to modify your example
>>
>>char chrPrim = word.charAt(i);
>>Character chrObject = Character.valueOf(chrPrim);
>>boolean isEqual = Character.valueOf('a').equals(chrObject);
>>
>>but since you have a primitive it is easier to just do
>>
>> if ( word.charAt(i) == 'a' ) {...} // !!
>>
>
>
> Thanks
>
> And if I want to compare a string of vouwels
>
> String [] vouwels = {"A", "a", "E", "e", "U", "u", "I", "i", "O", "o"};
>
> if(word.charAt(i) == vouwels[j]){} //?
>
> So I need to count the vouwels in a word...
>
With proper looping and counting that could do it, yes. Take a look at
..toCharArray() method of string, to save repeatedly extracting the same
characters out of the string, then it's just a case of looping over the
two arrays and incrementing a count when the values match.

James
From: Roedy Green on 10 Jan 2006 15:52
On Tue, 10 Jan 2006 20:39:36 GMT, haig <haigremove(a)pandora.be> wrote,
quoted or indirectly quoted someone who said :

>String [] vouwels = {"A", "a", "E", "e", "U", "u", "I", "i", "O", "o"};
>
>if(word.charAt(i) == vouwels[j]){} //?

You would need a nested loop over the chars in word and the possible
vowels and increment a counter when you find a match.

The for:each is neat for this:

for ( char vowel : vowels )

But you need to use a char[] instead of a String[].

--
Canadian Mind Products, Roedy Green.
http://mindprod.com Java custom programming, consulting and coaching.
From: Malte Christensen on 10 Jan 2006 15:54
haig wrote:
> Hello
>
> Ik get an error on this piece of code:
>
> if((word.charAt(i)).equals("a"){
> ....
> }
>
> Error: char cannot be dereferenced
>
> Can someone tell me what's wrong? Or how can I compare each letter of the
> word to the "a"?
>
> Thanks

Seems that charAt() returns a char. A char does not have a method named
equals.

Try

if (word.charAt(i) == 'a') {
....
}
From: Roedy Green on 10 Jan 2006 15:57
On Tue, 10 Jan 2006 20:18:26 GMT, haig <haigremove(a)pandora.be> wrote,
quoted or indirectly quoted someone who said :

>if((word.charAt(i)).equals("a"){

compare Strings with Strings and chars with chars. You have char on
the left and String on the right.
--
Canadian Mind Products, Roedy Green.
http://mindprod.com Java custom programming, consulting and coaching.
From: Thomas Fritsch on 10 Jan 2006 15:58
"haig" <haigremove(a)pandora.be> wrote:
> And if I want to compare a string of vouwels
>
> String [] vouwels = {"A", "a", "E", "e", "U", "u", "I", "i", "O", "o"};
>
> if(word.charAt(i) == vouwels[j]){} //?
>
> So I need to count the vouwels in a word...
>
The compiler will give an error, because you try to compare char with
String.

What you probably want to compare char wit char:
char [] vouwels = {'A', 'a', 'E', 'e', 'U', 'u', 'I', 'i', 'O', 'o'};

if(word.charAt(i) == vouwels[j]){}

--
"TFritsch$t-online:de".replace(':','.').replace('$','@')


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