Prev: Unable to passivate due to ctx lock warning on JBoss 4.0.2
Next: EXCEPTION_ACCESS_VIOLATION
From: James Westby on 10 Jan 2006 16:09
James Westby wrote:
> haig wrote:
>
>> "VisionSet" <spam(a)ntlworld.com> wrote in news:WOUwf.32187$yu.5572
>> @newsfe6-gui.ntli.net:
>>
>>
>>
>>> word.charAt(i) returns a char primitive, you can not call methods on a
>>> primitive ie equals(String str)
>>> For that matter you must make the two objects of the same type to make
>>> equals meaningful.
>>>
>>> so
>>>
>>> objectOneOfTypeA.equals(objectTwoOfTypeA) // is okay
>>>
>>> to modify your example
>>>
>>> char chrPrim = word.charAt(i);
>>> Character chrObject = Character.valueOf(chrPrim);
>>> boolean isEqual = Character.valueOf('a').equals(chrObject);
>>>
>>> but since you have a primitive it is easier to just do
>>>
>>> if ( word.charAt(i) == 'a' ) {...} // !!
>>>
>>
>>
>> Thanks
>>
>> And if I want to compare a string of vouwels
>> String [] vouwels = {"A", "a", "E", "e", "U", "u", "I", "i", "O", "o"};
>> if(word.charAt(i) == vouwels[j]){} //?
>>
>> So I need to count the vouwels in a word...
>>
> With proper looping and counting that could do it, yes. Take a look at
> .toCharArray() method of string, to save repeatedly extracting the same
> characters out of the string, then it's just a case of looping over the
> two arrays and incrementing a count when the values match.
>
> James

As Roedy pointed out you need a char[] not String[] of vowels. This
applies to this method as well.

James
From: Thomas Hawtin on 10 Jan 2006 16:27
Thomas Fritsch wrote:
> "haig" <haigremove(a)pandora.be> wrote:
>
>>And if I want to compare a string of vouwels
>>
>>String [] vouwels = {"A", "a", "E", "e", "U", "u", "I", "i", "O", "o"};
>>
>>if(word.charAt(i) == vouwels[j]){} //?
>>
>>So I need to count the vouwels in a word...
>>
>
> The compiler will give an error, because you try to compare char with
> String.
>
> What you probably want to compare char wit char:
> char [] vouwels = {'A', 'a', 'E', 'e', 'U', 'u', 'I', 'i', 'O', 'o'};

Or, easier to read:

char[] vowels = "AaEeIiOoUu".toCharArray();

Tom Hawtin
--
Unemployed English Java programmer
http://jroller.com/page/tackline/
From: Roedy Green on 10 Jan 2006 16:30
On Tue, 10 Jan 2006 21:54:09 +0100, Malte Christensen
<You_can_spam_me_here(a)nmalte.dk> wrote, quoted or indirectly quoted
someone who said :

>Seems that charAt() returns a char. A char does not have a method named
>equals.

In fact, because char is a primitive, it does not have ANY methods.
Only Objects have methods, e.g. Character or String.
--
Canadian Mind Products, Roedy Green.
http://mindprod.com Java custom programming, consulting and coaching.
From: Mike Schilling on 10 Jan 2006 21:52

"Roedy Green" <my_email_is_posted_on_my_website(a)munged.invalid> wrote in
message news:pf78s11h1nf7iafoiu4t0ghcoc42liql26(a)4ax.com...
> On Tue, 10 Jan 2006 20:39:36 GMT, haig <haigremove(a)pandora.be> wrote,
> quoted or indirectly quoted someone who said :
>
>>String [] vouwels = {"A", "a", "E", "e", "U", "u", "I", "i", "O", "o"};
>>
>>if(word.charAt(i) == vouwels[j]){} //?
>
> You would need a nested loop over the chars in word and the possible
> vowels and increment a counter when you find a match.
>
> The for:each is neat for this:
>
> for ( char vowel : vowels )
>
> But you need to use a char[] instead of a String[].

Simpler, though is:

int index = "AaEeIiOoUu".indexOf (word.charAt(i));
if (index >= 0) ...


From: Malte Christensen on 11 Jan 2006 10:03
Roedy Green wrote:
> On Tue, 10 Jan 2006 21:54:09 +0100, Malte Christensen
> <You_can_spam_me_here(a)nmalte.dk> wrote, quoted or indirectly quoted
> someone who said :
>
>
>>Seems that charAt() returns a char. A char does not have a method named
>>equals.
>
>
> In fact, because char is a primitive, it does not have ANY methods.
> Only Objects have methods, e.g. Character or String.
Tnx for stating the obvious, I had left it to the OP.
First  |  Prev  |  Next  |  Last
Pages: 1 2 3 4
Prev: Unable to passivate due to ctx lock warning on JBoss 4.0.2
Next: EXCEPTION_ACCESS_VIOLATION