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From: Archimedes Plutonium on 14 Jul 2010 21:14 Archimedes Plutonium wrote: > Archimedes Plutonium wrote: > > Alright, I am in no sort of rush. The proof of the Infinitude of > > Perfect Numbers has > > been waiting since Pythagoras of 3,000 years old, so what is 3 weeks > > more. > > > > When a new technique is found in mathematics that clears out a > > problem-- infinitude > > of Twin Primes and Polignac Conjecture, you can usually bet that the > > new technique > > does alot more, that it can clear out a whole class of unsolved > > problems. The new > > technique I speak of is the fact that in Euclid's Infinitude of Primes > > proof when in Indirect > > delivers two new necessarily primes as Euclid's Numbers. It was a > > mistake found > > in the Logical setup of Indirect Method that ekes out two new > > necessarily primes and > > with this found mistake one easily proves infinitude of Twin Primes > > and Polignac conjecture. > > But can this new technique be marshalled to conquer Infinitude of > > Perfect Numbers and a > > entire gigantic list of primes of specific form? That is what I am > > trying to resolve. > > > > Whether I can extend the new technique to conquer most conjectures of > > prime form, begging > > for a proof of infinity. > > > > With Twin Primes and Polignac conjecture they are easily fit into the W > > +1, W-1, then into > > W+2, W-2 then into W+3, W-3, etc etc. > > > > But what about when Mersenne primes of form (2^p)-1 pop up on the > > radar? I believe the new > > technique is powerful enough for it delivers two new necessarily > > primes. The problem is to > > finagle the form (2^p)-1 into Euclid Numbers. If I can finagle them > > into being Euclid Numbers > > then the proof of Mersenne primes and Infinitude of Perfect Numbers > > falls out. > > > > So here I have a new technique-- Indirect Method yields two new > > primes. Now I attach > > another tool, that of Mathematical Induction. I do this so that I can > > finagle the Euclid Numbers > > to be of form (2^p)-1. > > > > Now I am rusty on Mathematical Induction but let me just spearhead a > > attack. > > > > Indirect Method > > (1) definition of prime > > (2) hypothetical assumption step; suppose .. where last number in list > > is largest prime > > (3) form Euclid's Number/s > > (4) Euclid's Number/s are necessarily prime > > (5) contradiction to largest prime of list > > (6) set infinite > > > > So the above worked splendidly for Twin Primes and the Polignac > > Conjecture of all prime > > pairs of form P, P+2k. > > > > But now we tackle primes of more complicated form such as Mersenne > > primes (2^p)-1 > > > > The first few Mersenne primes are 3,7,31, 127 > > > > So the initial case of a Math Induction works for Euclid's Number as W > > +1 > > > > {2,3} are all the primes that exist yields Euclid Number (2x3)+1 = 7 > > {2,3,5} are all the primes that exist yields Euclid Number (2x3x5)+1 = > > 31 > > > > So I have the initial case of a Mathematical Induction on Mersenne > > Primes > > > > Now I suppose true for case N on Mersenne Primes: > > > > {2,3,5,7,11, . . . , p_N} yields (2x3x5x7x11x . . . x p_N) + 1 is a > > prime of form (2^p)-1 > > > > Now I have to show that {2,3,5,7,11, . . . , p_N, p_N+1} is also a > > prime of form (2^p)-1 > > > > Now pardon me, and hope you do not mind this next trick up my sleeve, > > but it looks > > to me as though there is a repeat of the Twin Primes proof here where > > I look upon > > p_N as that of W-1 and look upon p_N+1 as W+1 > > > > And thus achieve the infinitude of Mersenne Primes which thus achieves > > Infinitude > > of Perfect Numbers. > > > > > So I have no worries, none whatsoever that the Euclid Number is prime > for > the method guarantees it prime. My only worry and concern is whether > I > retrieve another Mersenne prime of form (2^p) -1 > > By Math Induction supposed p_N Euclid Number is a Mersenne formed > prime > > All that is needed is to see that p_N+1 Euclid Number is a Mersenned > formed prime > > Looks like I need not worry about whether p_N+1 Euclid Number is prime > for the > method gives me it as necessarily prime, what matters is whether it is > a Mersenne > form. That means it is a exponent of 2. > > That means it is it is from the stock of 2, 4, 8, 16, 32, 64, > 128, . . . > > I do not have to worry about the -1 in (2^p)-1 for the Euclid Number > can achieve that. > > All I have to worry about is that the Euclid Number has a rootstock > from 2^p > > So let me do the Indirect Method on just the first initial Mersenne > Primes to get a feeling > for the flow of how the mechanics works. > > Definition of Prime > Suppose all primes finite with 3 the last and largest Mersenne prime > {2,3} are all the primes that exist yields Euclid Number (2x3)+1 = 7 > Contradiction and formed a new and larger Mersenne prime of 7 > Hence Mersenne primes infinite > > Again to see the flow > Definition of Prime > Suppose all primes finite with 5 the largest prime in set {2,3,5} are > all the primes that exist yields Euclid Number (2x3x5)+1 = 31 > Contradiction and formed a new and larger prime with is Mersenned > prime > Hence set of all primes infinite > > So in the one proof case I can say Mersenne primes infinite but in the > second case I can > only say all primes infinite. > > So, beginning to see some daylight in this: > > In the Supposition step of the Math Induction what I was supposing > true is that > the Euclid Number for p_N as that of (2x3x5x7x. . .xp_N) is of the > form of (2^p) > > So then, all I need show is that the p_N+1 continues with the > 2,4,8,16,32, . . . string. > I usually find that talking something to death achieves my goal. Okay, so I supposed in Math Induction that p_N was true, and so (2x3x5x7x. . .xp_N) was of the form 2^p Now when in p_N+1 I include that into the new Euclid Number as such: (2x3x5x7x. . .xp_N x p_N+1) what I am doing is squaring in the series 2,4,8, 16, 32, 64, 128, . . . So that we can see that 8 x 8 is Archimedes Plutonium http://www.iw.net/~a_plutonium/ whole entire Universe is just one big atom where dots of the electron-dot-cloud are galaxies |