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From: Archimedes Plutonium on 14 Jul 2010 20:57 Archimedes Plutonium wrote: > Alright, I am in no sort of rush. The proof of the Infinitude of > Perfect Numbers has > been waiting since Pythagoras of 3,000 years old, so what is 3 weeks > more. > > When a new technique is found in mathematics that clears out a > problem-- infinitude > of Twin Primes and Polignac Conjecture, you can usually bet that the > new technique > does alot more, that it can clear out a whole class of unsolved > problems. The new > technique I speak of is the fact that in Euclid's Infinitude of Primes > proof when in Indirect > delivers two new necessarily primes as Euclid's Numbers. It was a > mistake found > in the Logical setup of Indirect Method that ekes out two new > necessarily primes and > with this found mistake one easily proves infinitude of Twin Primes > and Polignac conjecture. > But can this new technique be marshalled to conquer Infinitude of > Perfect Numbers and a > entire gigantic list of primes of specific form? That is what I am > trying to resolve. > > Whether I can extend the new technique to conquer most conjectures of > prime form, begging > for a proof of infinity. > > With Twin Primes and Polignac conjecture they are easily fit into the W > +1, W-1, then into > W+2, W-2 then into W+3, W-3, etc etc. > > But what about when Mersenne primes of form (2^p)-1 pop up on the > radar? I believe the new > technique is powerful enough for it delivers two new necessarily > primes. The problem is to > finagle the form (2^p)-1 into Euclid Numbers. If I can finagle them > into being Euclid Numbers > then the proof of Mersenne primes and Infinitude of Perfect Numbers > falls out. > > So here I have a new technique-- Indirect Method yields two new > primes. Now I attach > another tool, that of Mathematical Induction. I do this so that I can > finagle the Euclid Numbers > to be of form (2^p)-1. > > Now I am rusty on Mathematical Induction but let me just spearhead a > attack. > > Indirect Method > (1) definition of prime > (2) hypothetical assumption step; suppose .. where last number in list > is largest prime > (3) form Euclid's Number/s > (4) Euclid's Number/s are necessarily prime > (5) contradiction to largest prime of list > (6) set infinite > > So the above worked splendidly for Twin Primes and the Polignac > Conjecture of all prime > pairs of form P, P+2k. > > But now we tackle primes of more complicated form such as Mersenne > primes (2^p)-1 > > The first few Mersenne primes are 3,7,31, 127 > > So the initial case of a Math Induction works for Euclid's Number as W > +1 > > {2,3} are all the primes that exist yields Euclid Number (2x3)+1 = 7 > {2,3,5} are all the primes that exist yields Euclid Number (2x3x5)+1 = > 31 > > So I have the initial case of a Mathematical Induction on Mersenne > Primes > > Now I suppose true for case N on Mersenne Primes: > > {2,3,5,7,11, . . . , p_N} yields (2x3x5x7x11x . . . x p_N) + 1 is a > prime of form (2^p)-1 > > Now I have to show that {2,3,5,7,11, . . . , p_N, p_N+1} is also a > prime of form (2^p)-1 > > Now pardon me, and hope you do not mind this next trick up my sleeve, > but it looks > to me as though there is a repeat of the Twin Primes proof here where > I look upon > p_N as that of W-1 and look upon p_N+1 as W+1 > > And thus achieve the infinitude of Mersenne Primes which thus achieves > Infinitude > of Perfect Numbers. > So I have no worries, none whatsoever that the Euclid Number is prime for the method guarantees it prime. My only worry and concern is whether I retrieve another Mersenne prime of form (2^p) -1 By Math Induction supposed p_N Euclid Number is a Mersenne formed prime All that is needed is to see that p_N+1 Euclid Number is a Mersenned formed prime Looks like I need not worry about whether p_N+1 Euclid Number is prime for the method gives me it as necessarily prime, what matters is whether it is a Mersenne form. That means it is a exponent of 2. That means it is it is from the stock of 2, 4, 8, 16, 32, 64, 128, . . . I do not have to worry about the -1 in (2^p)-1 for the Euclid Number can achieve that. All I have to worry about is that the Euclid Number has a rootstock from 2^p So let me do the Indirect Method on just the first initial Mersenne Primes to get a feeling for the flow of how the mechanics works. Definition of Prime Suppose all primes finite with 3 the last and largest Mersenne prime {2,3} are all the primes that exist yields Euclid Number (2x3)+1 = 7 Contradiction and formed a new and larger Mersenne prime of 7 Hence Mersenne primes infinite Again to see the flow Definition of Prime Suppose all primes finite with 5 the largest prime in set {2,3,5} are all the primes that exist yields Euclid Number (2x3x5)+1 = 31 Contradiction and formed a new and larger prime with is Mersenned prime Hence set of all primes infinite So in the one proof case I can say Mersenne primes infinite but in the second case I can only say all primes infinite. So, beginning to see some daylight in this: In the Supposition step of the Math Induction what I was supposing true is that the Euclid Number for p_N as that of (2x3x5x7x. . .xp_N) is of the form of (2^p) So then, all I need show is that the p_N+1 continues with the 2,4,8,16,32, . . . string. Archimedes Plutonium http://www.iw.net/~a_plutonium/ whole entire Universe is just one big atom where dots of the electron-dot-cloud are galaxies |