From: Ashish Uthama on
n Fri, 19 Feb 2010 15:13:04 -0500, jenya polyakova <jenya56(a)yahoo.com>
wrote:

> "Ashish Uthama" <first.last(a)mathworks.com> wrote in message
> <op.u8d4wawsa5ziv5(a)uthamaa.dhcp.mathworks.com>...
>> On Fri, 19 Feb 2010 14:56:04 -0500, jenya polyakova
>> <jenya56(a)yahoo.com> wrote:
>> > "Ashish Uthama" <first.last(a)mathworks.com> wrote in message >
>> <op.u8d2p0yda5ziv5(a)uthamaa.dhcp.mathworks.com>...
>> >> On Fri, 19 Feb 2010 12:27:04 -0500, jenya polyakova >>
>> <jenya56(a)yahoo.com> wrote:
>> >> > a matlab function? I have a vector of data DATA and also
>> respective >> X > and Y coordinate vectors of the same length as
>> data. I need to >> divide my > area into rectangular boxes and then
>> calculate the mean >> (based on my > DATA) for each of these box. Is
>> there a function like >> that in Matlab? > Thanks
>> >> Ok, I missed the part about having x/y coordinates.
>> >> I guess you meant fractional blocks defined on the coordinate system.
>> >> I would interpolate the data to convert fractional coordinates
>> into >> full size blocks.
>> >> %Sample existing data
>> >> [x y]=meshgrid(5:8,3:6)
>> >> d=rand(4,4)
>> >> %Interpolate on a finer grid
>> >> [xi yi]=meshgrid(5:.5:8,3:.5:6)
>> >> di=interp2(x,y,d,xi,yi)
>> >> follow with the filtering steps on di to get the mean.
>> >>
>> > I am not sure...here by interp you essentially create more data. I
>> do > not want to do it. What I want to do it to place a box of certain
>> size > (say 2.5x2.5) in the, say, lower, left corner. Then I would
>> look how > many data points fall within that block. Let's say four
>> point were > there. I would then assign the weight of (1/4) to each of
>> the data. Then > I will move block to next position (non-overlapping).
>> Perform the same > thing of assigning weights. Thing I worry about is
>> boarder effect and > also point falling into the side of the box. It
>> is easy code. But I was > wondering if it could be done by matlab
>> stand alone functions. Thanks
>> If its non-overlapping, why do you expect the output to be the same
>> size as the input data?
>> Anyway, I dont think there is a MATLAB function to do this.
>> Hand coding is probably the best approach.
> because we are not adding more data, nor do we delete data. We just
> multiply our data by weights that are defined by the "size" (size in
> this case is number of data points falling into the box).

I guess I now understand what you are trying to do, I cant think of
leveraging any MATLAB function to do this.
If you have trouble hand coding, post back with sample data and the code
you have created.