From: Dan on
I am stuck on a problem where i need to combine newton’s method and the composite trapezoid rule. I’m not the best at matlab and can’t figure this thing out.

Integral 0 to x of (1/(sqrt(2*pi)))*(exp((-t^2)/2)) dt = 0.45

The question: Find a solution x to within 10^-5 by combining newton’s method (with po = 0.5) and the composite trapezoid rule.

Any ideas on how to even start this would be much appreciated. Thanks
From: TideMan on
On Dec 1, 1:48 pm, "Dan " <dscottz...(a)aol.com> wrote:
> I am stuck on a problem where i need to combine newton&#8217;s method and the composite trapezoid rule. I&#8217;m not the best at matlab and can&#8217;t figure this thing out.
>
> Integral 0 to x of  (1/(sqrt(2*pi)))*(exp((-t^2)/2)) dt = 0.45
>
> The question: Find a solution x to within 10^-5 by combining newton&#8217;s method (with po = 0.5) and the composite trapezoid rule.
>
> Any ideas on how to even start this would be much appreciated. Thanks

Step 1. Sit down and read your lecture notes and the appropriate text
book.
Step 2. Write down the algorithm
Step 3. Code it up in Matlab
Step 4. If you have problems with making the Matlab code work, ask
here. But not until you have carried out Steps 1 to 3.


From: Torsten Hennig on
> I am stuck on a problem where i need to combine
> newton's method and the composite trapezoid
> rule. I'm not the best at matlab and
> can't figure this thing out.
>
> Integral 0 to x of (1/(sqrt(2*pi)))*(exp((-t^2)/2))
> dt = 0.45
>
> The question: Find a solution x to within 10^-5 by
> combining newton's method (with po = 0.5) and
> the composite trapezoid rule.
>
> Any ideas on how to even start this would be much
> appreciated. Thanks

Find the zero of
f(x) = Integral 0 to x of (1/(sqrt(2*pi)))*(exp((-t^2)/2)) dt - 0.45
by applying Newton's method :
x_(n+1)-x_n = -f(x_n)/f'(x_n)

Calculation of f'(x_n) is easy ; to evaluate f(x_n),
you will have to use a numerical approximation
method for
Integral 0 to x_n of (1/(sqrt(2*pi)))*(exp((-t^2)/2)) dt
(e.g. the composite trapezoid rule).

Best wishes
Torsten.