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From: eestath on 2 Dec 2009 08:11
I ask an i might didn' get a correct answer :

http://groups.google.com/group/sci.math/browse_thread/thread/cb47f3d26f836895/c3ecb6cad88238e0?hl=en#c3ecb6cad88238e0
From: Joshua Cranmer on 2 Dec 2009 03:12
On 12/02/2009 07:55 AM, eestath wrote:
> The second part is strcly<1 because:
>
> [1/(2*3)+1/(2*3*5)+1/(2*3*5*7)+....]< 1/(2^1)+1/(2^3)+...

oo - x (where x < 1) = oo.

Remember, your first series diverged.

--
Beware of bugs in the above code; I have only proved it correct, not
tried it. -- Donald E. Knuth
From: eestath on 2 Dec 2009 08:33
How can anyone can model Erratosthenes sieve??

first you exclude the prime numbers that have as factor 2 (1/2 of
them) 1-1/2
then you exclude one third of them but half of them have factor 2 so
you actually exclude 1/3 - 1/(2*3)
then you exclude one fith of them but 1 in 2 has as its factor 2 and 1
in 3 have factor 3 so you exlude 1/5 - 1/(2*3*5)
.....

please it seems it is basic common logic but i do not know if it is
correct!

So the series might look like

1+1/3+1/5+1/7+....-{1/2+1/(2*3)+1/(2*3*5)+...} or

[1/2+1/3+1/5+1/7+....] - [1/(2*3)+1/(2*3*5)+1/(2*3*5*7)+....]
From: eestath on 2 Dec 2009 09:20

> then you exclude one third of them but half of them have factor 2 so
> you actually exclude 1/3 - 1/(2*3)
> then you exclude one fith of them but 1 in 2 has as its factor 2 and 1
> in 3 have factor 3 so you exlude

1/5 - 1/(2*5)-1/(3*5)

Is the correct answer ...and many simply failed to understand!!!!!!!
From: Jim Ferry on 2 Dec 2009 10:41


eestath wrote:
> if you have hard time to understand from where te series cam from read
> this :
>
> http://groups.google.com/group/sci.math/browse_thread/thread/cb47f3d26f836895?hl=en#tell
> me your opinion!
>
> tell me your opinion i may have good ideas don' t you think!

Your posts indicate that you're a better mathematician than Musatov,
but significantly worse than James Harris.
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