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From: eestath on 2 Dec 2009 06:19
IF

1 =[1/2+1/3+1/5+1/7+....] - [1/(2*3)+1/(2*3*5)+1/(2*3*5*7)+....]

Form two series

Call it A and B

A is the series of non twin prime numbers look below:

A=1/2 + 1/23+...-(1/2+1/(2*3*5...*23)+....)

(the series of non twin prime numbers and those that have as a last
factor in the denominator o non twin prime number... the series has
infinite number of terms and probably is irrational number)

an B is the series of twin prime numbers

B=1/3+1/5+1/7+....-[1/(2*3)+1/(2*3*5)+....]

Prove that A is irrational

If A is irrational then B must be irrational because A+B = 1

If B is irrational it has infinite number of terms

Thus there exist infinite twin prime numbers

This might work

Dimitris Stathopoulos
stathopouloscs(a)hotmail.com
From: eestath on 2 Dec 2009 06:35
if you have hard time to understand from where te series cam from read
this :

http://groups.google.com/group/sci.math/browse_thread/thread/cb47f3d26f836895?hl=en#tell
me your opinion!

tell me your opinion i may have good ideas don' t you think!
From: Joshua Cranmer on 2 Dec 2009 02:30
On 12/02/2009 06:19 AM, eestath wrote:
> IF
>
> 1 =[1/2+1/3+1/5+1/7+....] - [1/(2*3)+1/(2*3*5)+1/(2*3*5*7)+....]

The first series diverges
(http://en.wikipedia.org/wiki/Prime_zeta_function). If the second series
converges, the difference can't equal 1, and if the second series
diverges, things get funky in mathland. So really, the answer is "it
doesn't."

--
Beware of bugs in the above code; I have only proved it correct, not
tried it. -- Donald E. Knuth
From: eestath on 2 Dec 2009 07:45
the series is equal to 1!

it can' t de nothing else than 1


From: Joshua Cranmer on 2 Dec 2009 03:03
On 12/02/2009 07:45 AM, eestath wrote:
> the series is equal to 1!

To quote an old TV show, "then prove it!"


--
Beware of bugs in the above code; I have only proved it correct, not
tried it. -- Donald E. Knuth
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