From: Phil Hobbs on
Jim Thompson wrote:
> On Thu, 27 May 2010 07:56:08 +1000, David Eather <eather(a)tpg.com.au>
> wrote:
>
>> On 27/05/2010 12:31 AM, George Herold wrote:
>>> On May 26, 8:00 am, David Eather<eat...(a)tpg.com.au> wrote:
>>>> On 26/05/2010 4:10 AM, John Larkin wrote:
>>>>
>>>>
>>>>
>>>>
>>>>
>>>>> On Tue, 25 May 2010 10:22:59 -0700, Tim Wescott<t...(a)seemywebsite.now>
>>>>> wrote:
>>>>>> On 05/25/2010 10:18 AM, rich wrote:
>>>>>>> I need to drive a blue led from 3.3V. Most of the SMD blue leds I
>>>>>>> find have a Vf equal to or greater than 3.3V.
>>>>>>> I am curious how others are dealing with this.
>>>>>> That pretty much demands a voltage boost of some sort. Depending on how
>>>>>> many lights you have, how much power you're willing to waste, how much
>>>>>> design time you want to spend and how expensive you want the final
>>>>>> product to be, your choices sort of boil down to a switcher with
>>>>>> inductors and diodes and all that, or a current pump.
>>>>>> Most of us would solve this problem by looking for a suitable IC.
>>>>>> _Some_ of us would do it with two transistors, an inductor, and a cap,
>>>>>> then brag about only needing one $.001 resistor instead of three.
>>>>> One resistor:
>>>>> ftp://jjlarkin.lmi.net/LED_boost.JPG
>>>>> John
>>>> Hi,
>>>>
>>>> Could you post his circuit onwww.filedropper.comorwww.filefactory.com
>>>> or something similar - I just can connect.- Hide quoted text -
>>>>
>>>> - Show quoted text -
>>>
>>>
>>> +3.3V----+-----------+
>>> | |
>>> |\| V This is diode or R
>>> | \ -
>>> +--+|>--+-CC---+
>>> | | / | |
>>> | |/| | V light comes out here
>>> +------RR--+ -
>>> |
>>> GND
>>>
>>> The IC is a schmitt trigger. (And connected to ground also...
>>> connection not shown)
>>>
>>> George H.
>>>
>>>
>>>
>>>
>>>
>> Thanks.
>
> Theory of "operation" is left as an exercise for the student :-)
>
> ...Jim Thompson

Might need a cap at the input, but otherwise OK, I think. If you make
the resistor big enough, the input capacitance of the inverter should
make it work fine. Nice low parts count.

Cheers

Phil Hobbs

--
Dr Philip C D Hobbs
Principal
ElectroOptical Innovations
55 Orchard Rd
Briarcliff Manor NY 10510
845-480-2058
hobbs at electrooptical dot net
http://electrooptical.net
From: Jim Thompson on
On Wed, 26 May 2010 21:36:02 -0400, Phil Hobbs
<pcdhSpamMeSenseless(a)electrooptical.net> wrote:

>Jim Thompson wrote:
>> On Thu, 27 May 2010 07:56:08 +1000, David Eather <eather(a)tpg.com.au>
>> wrote:
>>
>>> On 27/05/2010 12:31 AM, George Herold wrote:
>>>> On May 26, 8:00 am, David Eather<eat...(a)tpg.com.au> wrote:
>>>>> On 26/05/2010 4:10 AM, John Larkin wrote:
>>>>>
>>>>>
>>>>>
>>>>>
>>>>>
>>>>>> On Tue, 25 May 2010 10:22:59 -0700, Tim Wescott<t...(a)seemywebsite.now>
>>>>>> wrote:
>>>>>>> On 05/25/2010 10:18 AM, rich wrote:
>>>>>>>> I need to drive a blue led from 3.3V. Most of the SMD blue leds I
>>>>>>>> find have a Vf equal to or greater than 3.3V.
>>>>>>>> I am curious how others are dealing with this.
>>>>>>> That pretty much demands a voltage boost of some sort. Depending on how
>>>>>>> many lights you have, how much power you're willing to waste, how much
>>>>>>> design time you want to spend and how expensive you want the final
>>>>>>> product to be, your choices sort of boil down to a switcher with
>>>>>>> inductors and diodes and all that, or a current pump.
>>>>>>> Most of us would solve this problem by looking for a suitable IC.
>>>>>>> _Some_ of us would do it with two transistors, an inductor, and a cap,
>>>>>>> then brag about only needing one $.001 resistor instead of three.
>>>>>> One resistor:
>>>>>> ftp://jjlarkin.lmi.net/LED_boost.JPG
>>>>>> John
>>>>> Hi,
>>>>>
>>>>> Could you post his circuit onwww.filedropper.comorwww.filefactory.com
>>>>> or something similar - I just can connect.- Hide quoted text -
>>>>>
>>>>> - Show quoted text -
>>>>
>>>>
>>>> +3.3V----+-----------+
>>>> | |
>>>> |\| V This is diode or R
>>>> | \ -
>>>> +--+|>--+-CC---+
>>>> | | / | |
>>>> | |/| | V light comes out here
>>>> +------RR--+ -
>>>> |
>>>> GND
>>>>
>>>> The IC is a schmitt trigger. (And connected to ground also...
>>>> connection not shown)
>>>>
>>>> George H.
>>>>
>>>>
>>>>
>>>>
>>>>
>>> Thanks.
>>
>> Theory of "operation" is left as an exercise for the student :-)
>>
>> ...Jim Thompson
>
>Might need a cap at the input, but otherwise OK, I think. If you make
>the resistor big enough, the input capacitance of the inverter should
>make it work fine. Nice low parts count.
>
>Cheers
>
>Phil Hobbs

I think you'd need to tailor the rate to accommodate the source/sink
capability of the inverter (not shown, bubble to be imagined :-)

...Jim Thompson
--
| James E.Thompson, CTO | mens |
| Analog Innovations, Inc. | et |
| Analog/Mixed-Signal ASIC's and Discrete Systems | manus |
| Phoenix, Arizona 85048 Skype: Contacts Only | |
| Voice:(480)460-2350 Fax: Available upon request | Brass Rat |
| E-mail Icon at http://www.analog-innovations.com | 1962 |

The only thing bipartisan in this country is hypocrisy
From: Phil Hobbs on
Jim Thompson wrote:
> On Wed, 26 May 2010 21:36:02 -0400, Phil Hobbs
> <pcdhSpamMeSenseless(a)electrooptical.net> wrote:
>
>> Jim Thompson wrote:
>>> On Thu, 27 May 2010 07:56:08 +1000, David Eather <eather(a)tpg.com.au>
>>> wrote:
>>>
>>>> On 27/05/2010 12:31 AM, George Herold wrote:
>>>>> On May 26, 8:00 am, David Eather<eat...(a)tpg.com.au> wrote:
>>>>>> On 26/05/2010 4:10 AM, John Larkin wrote:
>>>>>>
>>>>>>
>>>>>>
>>>>>>
>>>>>>
>>>>>>> On Tue, 25 May 2010 10:22:59 -0700, Tim Wescott<t...(a)seemywebsite.now>
>>>>>>> wrote:
>>>>>>>> On 05/25/2010 10:18 AM, rich wrote:
>>>>>>>>> I need to drive a blue led from 3.3V. Most of the SMD blue leds I
>>>>>>>>> find have a Vf equal to or greater than 3.3V.
>>>>>>>>> I am curious how others are dealing with this.
>>>>>>>> That pretty much demands a voltage boost of some sort. Depending on how
>>>>>>>> many lights you have, how much power you're willing to waste, how much
>>>>>>>> design time you want to spend and how expensive you want the final
>>>>>>>> product to be, your choices sort of boil down to a switcher with
>>>>>>>> inductors and diodes and all that, or a current pump.
>>>>>>>> Most of us would solve this problem by looking for a suitable IC.
>>>>>>>> _Some_ of us would do it with two transistors, an inductor, and a cap,
>>>>>>>> then brag about only needing one $.001 resistor instead of three.
>>>>>>> One resistor:
>>>>>>> ftp://jjlarkin.lmi.net/LED_boost.JPG
>>>>>>> John
>>>>>> Hi,
>>>>>>
>>>>>> Could you post his circuit onwww.filedropper.comorwww.filefactory.com
>>>>>> or something similar - I just can connect.- Hide quoted text -
>>>>>>
>>>>>> - Show quoted text -
>>>>>
>>>>> +3.3V----+-----------+
>>>>> | |
>>>>> |\| V This is diode or R
>>>>> | \ -
>>>>> +--+|>--+-CC---+
>>>>> | | / | |
>>>>> | |/| | V light comes out here
>>>>> +------RR--+ -
>>>>> |
>>>>> GND
>>>>>
>>>>> The IC is a schmitt trigger. (And connected to ground also...
>>>>> connection not shown)
>>>>>
>>>>> George H.
>>>>>
>>>>>
>>>>>
>>>>>
>>>>>
>>>> Thanks.
>>> Theory of "operation" is left as an exercise for the student :-)
>>>
>>> ...Jim Thompson
>> Might need a cap at the input, but otherwise OK, I think. If you make
>> the resistor big enough, the input capacitance of the inverter should
>> make it work fine. Nice low parts count.
>>
>> Cheers
>>
>> Phil Hobbs
>
> I think you'd need to tailor the rate to accommodate the source/sink
> capability of the inverter (not shown, bubble to be imagined :-)
>
> ...Jim Thompson

Urinating contests aren't my cup of tea. ;)

Cheers

Phil Hobbs

--
Dr Philip C D Hobbs
Principal
ElectroOptical Innovations
55 Orchard Rd
Briarcliff Manor NY 10510
845-480-2058
hobbs at electrooptical dot net
http://electrooptical.net
From: Spehro Pefhany on
On Wed, 26 May 2010 21:36:02 -0400, the renowned Phil Hobbs
<pcdhSpamMeSenseless(a)electrooptical.net> wrote:

>
>Might need a cap at the input, but otherwise OK, I think. If you make
>the resistor big enough, the input capacitance of the inverter should
>make it work fine. Nice low parts count.
>
>Cheers
>
>Phil Hobbs

A typical blue LED won't actually be off with a Si diode in series and
3.3V, even without considering temperature and tolerance on the 3.3V.

Can be fixed with two Si diodes in series the way I drew it (but even
that might be a bit marginal) or use a red LED for the diode.


Best regards,
Spehro Pefhany
--
"it's the network..." "The Journey is the reward"
speff(a)interlog.com Info for manufacturers: http://www.trexon.com
Embedded software/hardware/analog Info for designers: http://www.speff.com
From: Jim Thompson on
On Wed, 26 May 2010 21:55:56 -0400, Phil Hobbs
<pcdhSpamMeSenseless(a)electrooptical.net> wrote:

>Jim Thompson wrote:
>> On Wed, 26 May 2010 21:36:02 -0400, Phil Hobbs
>> <pcdhSpamMeSenseless(a)electrooptical.net> wrote:
>>
>>> Jim Thompson wrote:
>>>> On Thu, 27 May 2010 07:56:08 +1000, David Eather <eather(a)tpg.com.au>
>>>> wrote:
>>>>
>>>>> On 27/05/2010 12:31 AM, George Herold wrote:
>>>>>> On May 26, 8:00 am, David Eather<eat...(a)tpg.com.au> wrote:
>>>>>>> On 26/05/2010 4:10 AM, John Larkin wrote:
>>>>>>>
>>>>>>>
>>>>>>>
>>>>>>>
>>>>>>>
>>>>>>>> On Tue, 25 May 2010 10:22:59 -0700, Tim Wescott<t...(a)seemywebsite.now>
>>>>>>>> wrote:
>>>>>>>>> On 05/25/2010 10:18 AM, rich wrote:
>>>>>>>>>> I need to drive a blue led from 3.3V. Most of the SMD blue leds I
>>>>>>>>>> find have a Vf equal to or greater than 3.3V.
>>>>>>>>>> I am curious how others are dealing with this.
>>>>>>>>> That pretty much demands a voltage boost of some sort. Depending on how
>>>>>>>>> many lights you have, how much power you're willing to waste, how much
>>>>>>>>> design time you want to spend and how expensive you want the final
>>>>>>>>> product to be, your choices sort of boil down to a switcher with
>>>>>>>>> inductors and diodes and all that, or a current pump.
>>>>>>>>> Most of us would solve this problem by looking for a suitable IC.
>>>>>>>>> _Some_ of us would do it with two transistors, an inductor, and a cap,
>>>>>>>>> then brag about only needing one $.001 resistor instead of three.
>>>>>>>> One resistor:
>>>>>>>> ftp://jjlarkin.lmi.net/LED_boost.JPG
>>>>>>>> John
>>>>>>> Hi,
>>>>>>>
>>>>>>> Could you post his circuit onwww.filedropper.comorwww.filefactory.com
>>>>>>> or something similar - I just can connect.- Hide quoted text -
>>>>>>>
>>>>>>> - Show quoted text -
>>>>>>
>>>>>> +3.3V----+-----------+
>>>>>> | |
>>>>>> |\| V This is diode or R
>>>>>> | \ -
>>>>>> +--+|>--+-CC---+
>>>>>> | | / | |
>>>>>> | |/| | V light comes out here
>>>>>> +------RR--+ -
>>>>>> |
>>>>>> GND
>>>>>>
>>>>>> The IC is a schmitt trigger. (And connected to ground also...
>>>>>> connection not shown)
>>>>>>
>>>>>> George H.
>>>>>>
>>>>>>
>>>>>>
>>>>>>
>>>>>>
>>>>> Thanks.
>>>> Theory of "operation" is left as an exercise for the student :-)
>>>>
>>>> ...Jim Thompson
>>> Might need a cap at the input, but otherwise OK, I think. If you make
>>> the resistor big enough, the input capacitance of the inverter should
>>> make it work fine. Nice low parts count.
>>>
>>> Cheers
>>>
>>> Phil Hobbs
>>
>> I think you'd need to tailor the rate to accommodate the source/sink
>> capability of the inverter (not shown, bubble to be imagined :-)
>>
>> ...Jim Thompson
>
>Urinating contests aren't my cup of tea. ;)
>
>Cheers
>
>Phil Hobbs

But John "I left out the bubble" Larkin makes it so-o-o-o easy ;-)

I think he's the one going senile. He claims it's me, but I feel (and
think) like an 18 year old :-)

...Jim Thompson
--
| James E.Thompson, CTO | mens |
| Analog Innovations, Inc. | et |
| Analog/Mixed-Signal ASIC's and Discrete Systems | manus |
| Phoenix, Arizona 85048 Skype: Contacts Only | |
| Voice:(480)460-2350 Fax: Available upon request | Brass Rat |
| E-mail Icon at http://www.analog-innovations.com | 1962 |

The only thing bipartisan in this country is hypocrisy
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