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From: kenseto on 4 Aug 2010 13:48 On Aug 4, 11:33 am, Tony M <marc...(a)gmail.com> wrote: > On Aug 4, 9:57 am, kenseto <kens...(a)erinet.com> wrote: > > > So every observer > > does not know if the observed clock is running slow or fast compared > > to his clock. This means that he must include both possibilities when > > predicting the rate of an observed clock as follows: > > Observed clcok runs slow: > > Delta(t')=gamma*Delta(t) > > Observed clock runs fast: > > Delta(t')=Delta(t)/gamma > > Ken, why not Delta(t)/gamma <= Delta(t') <= gamma*Delta(t)? Think > about it! No....Delta(t')=gamma*Delta(t) means that the passage of Delta(t') on the t' clock is equal to the passage of gamma*Delta(t) on the t clock....that means that the t' clock is running slower than the t clock. Similarly...Delta(t')=Delta(t)/gamma means that the passage of Delta(t') on the t' clock is equal to the passage of Delta(t)/gamma on the t clock....that means that the t' clock is running faster than the t clock.
From: Sam Wormley on 4 Aug 2010 15:02 On 8/4/10 1:03 PM, kenseto wrote: > Doppler effect got nothing to do with my proposed experiment. The TV > clock is compared to the observer's clock to get a ratio for a specfic > interval on the observer's clcok, such as 84000 seconds, to give a > ratio of (TV clock time interval)/observer's clock time interval) > > The rest of your ranting is due to your misunderstanding of the > experiment. > > Ken Seto Seto the data will be Doppler shifted. Do some self education! http://en.wikipedia.org/wiki/Doppler_effect http://en.wikipedia.org/wiki/Relativistic_Doppler_effect
From: kenseto on 4 Aug 2010 15:17 On Aug 4, 3:02 pm, Sam Wormley <sworml...(a)gmail.com> wrote: > On 8/4/10 1:03 PM, kenseto wrote: > > > Doppler effect got nothing to do with my proposed experiment. The TV > > clock is compared to the observer's clock to get a ratio for a specfic > > interval on the observer's clcok, such as 84000 seconds, to give a > > ratio of (TV clock time interval)/observer's clock time interval) > > > The rest of your ranting is due to your misunderstanding of the > > experiment. > > > Ken Seto > > Seto the data will be Doppler shifted. Do some self education! > http://en.wikipedia.org/wiki/Doppler_effect > http://en.wikipedia.org/wiki/Relativistic_Doppler_effect Hey idiot....the rate of the TV clock will not change whether it is approaching you or receding away from you. Satellite TV works because Doppler effect does not change the reception rate of the picture. Ken Seto
From: Sam Wormley on 4 Aug 2010 15:40 On 8/4/10 2:17 PM, kenseto wrote: > On Aug 4, 3:02 pm, Sam Wormley<sworml...(a)gmail.com> wrote: >> On 8/4/10 1:03 PM, kenseto wrote: >> >>> Doppler effect got nothing to do with my proposed experiment. The TV >>> clock is compared to the observer's clock to get a ratio for a specfic >>> interval on the observer's clcok, such as 84000 seconds, to give a >>> ratio of (TV clock time interval)/observer's clock time interval) >> >>> The rest of your ranting is due to your misunderstanding of the >>> experiment. >> >>> Ken Seto >> >> Seto the data will be Doppler shifted. Do some self education! >> http://en.wikipedia.org/wiki/Doppler_effect >> http://en.wikipedia.org/wiki/Relativistic_Doppler_effect > > Hey idiot....the rate of the TV clock will not change whether it is > approaching you or receding away from you. Satellite TV works because > Doppler effect does not change the reception rate of the picture. > > Ken Seto Betcha didn't know that TV satellites are in stationary orbits with respect to ground receivers. Got egg on your face, Seto?
From: Sam Wormley on 4 Aug 2010 15:40
On 8/4/10 2:16 PM, kenseto wrote: > Hey idiot....the rate of the TV clock will not change whether it is > approaching you or receding away from you. Satellite TV works because > Doppler effect does not change the reception rate of the picture. > > Ken Seto Betcha didn't know that TV satellites are in stationary orbits with respect to ground receivers. Got egg on your face, Seto? |