Freeware volume calculator for irregularly shaped pool
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From: Smitty Two on 17 Jul 2010 14:05 In article <i1slme$ah4$1(a)speranza.aioe.org>, LM <xxxvte.lisa.meisnerxxx(a)verizon.net> wrote: > What good is calculus if nobody practically uses it. It's reserved for those who are smart enough to not ask such absurd questions.
From: JoeSpareBedroom on 17 Jul 2010 14:11 "LM" <xxxvte.lisa.meisnerxxx(a)verizon.net> wrote in message news:i1slme$ah4$1(a)speranza.aioe.org... > > But since this is a common need of every pool owner of an irregularly > shaped pool,..... (snip) Why do you imagine that every owner of an irregularly shaped pool needs to know how much water it takes to fill the pool?
From: Metspitzer on 17 Jul 2010 14:13 On Sat, 17 Jul 2010 14:11:12 -0400, "JoeSpareBedroom" <newstrash(a)frontiernet.net> wrote: >"LM" <xxxvte.lisa.meisnerxxx(a)verizon.net> wrote in message >news:i1slme$ah4$1(a)speranza.aioe.org... > >> >> But since this is a common need of every pool owner of an irregularly >> shaped pool,..... > >(snip) > >Why do you imagine that every owner of an irregularly shaped pool needs to >know how much water it takes to fill the pool? > Gee......Woudn't that stuff be in the manual?
From: gpsman on 17 Jul 2010 14:19 On Jul 17, 12:55 pm, harry <haroldhr...(a)aol.com> wrote: > > Buy yourself a water meter. Fill the pool through the water meter. > Write the number down. Guaranteed to be exactly correct Depends on the meter. My pool also gets deep fast. I just divided it into thirds, which was close enough to satisfy me. I suspect the "standard" method is considered "close enough" in the pool industry. ----- - gpsman
From: Dan on 17 Jul 2010 16:13
This isn't really a calculus problem. If you have an equation that describes the x-y-z coordinates of the bottom of the pool, then... you can turn it into a calculus problem. What you have to do is your own version of "integration". It sounds like you've done it part way already by measuring the depth at many locations. The only thing you can really do is split the "plan" view of your pool into smaller areas. Then... measure the average depth for each individual area. Volume = Summation of all Area*AvgDepth. If your area calculations are correct and your average depth measurements are exact, your volume calculation will be exact. Otherwise... you merely have an approximation. A lot of pools only vary in depth as you cross from one end of the pool to the other. ie... they don't vary across the other direction of the pool. If this is your situation, merely divide the pool into strips across the pools width. Then apply the above method using each strip as an area. This would yield pretty good results with very little effort. I'm an engineer. I use Calculus for a lot of things and have found it to be EXTREMELY useful. It is used in just about every industry there is. When my wife, who does accounting work, was wondering where one of the formulas she was using came from that is widely used in the finance industry and has square roots and other things in it.... I was able to quickly and simply use basic calculus to show her how to come up with the formula. If you love using your iPhone or any other cell phone, fancy or not..... I'd venture to say that.... you wouldn't have that phone if calculus (or something similar) had never been invented. Heck... calculus is even used to figure out the most efficient way to package items together for shipping. Dan :-) |