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From: John Larkin on 6 Jul 2010 00:41 On Mon, 5 Jul 2010 17:48:35 -0500, "Tim Williams" <tmoranwms(a)charter.net> wrote: >"Fred Abse" <excretatauris(a)invalid.invalid> wrote in message news:pan.2010.07.05.19.11.23.376684(a)invalid.invalid... >> It still implies that reducing V by increasing C involves a loss of >> energy. > >So a flying capacitor converter is always 50% efficient? :-) > >Cap charging (in terms of conserved charge) is an irreversible process. But just like irreversible thermodynamic processes, if you make the steps small enough, it starts looking reversible. You can have two caps, C1 charged and C2 not, and transfer all the charge from C1 to C2, without loss. In fact, you can slosh the charge between them, back and forth, forever. Just don't use resistors. John
From: whit3rd on 6 Jul 2010 01:28 On Jul 5, 9:41 pm, John Larkin <jjlar...(a)highNOTlandTHIStechnologyPART.com> wrote: > You can have two caps, C1 charged and C2 not, and transfer all the > charge from C1 to C2, without loss. In fact, you can slosh the charge > between them, back and forth, forever. Just don't use resistors. It has to be identical size capacitors, otherwise 'all the charge' can't be transferred without adding/losing energy... With switches and moving parts, you can make all KINDS of electrostatic charge-moving gizmos. The earlier "reverse van de Graaff machine" suggestion is just one of a large family of electrostatic motors. A favorite example of high voltage motor is the Oxford bell <http://en.wikipedia.org/wiki/Oxford_Electric_Bell >
From: Tim Williams on 6 Jul 2010 05:09 "John Larkin" <jjlarkin(a)highNOTlandTHIStechnologyPART.com> wrote in message news:noc536dna78u2claiqu2nqockk4k3liu7h(a)4ax.com... > You can have two caps, C1 charged and C2 not, and transfer all the > charge from C1 to C2, without loss. In fact, you can slosh the charge > between them, back and forth, forever. Just don't use resistors. What if you want equal charges on both? Tim -- Deep Friar: a very philosophical monk. Website: http://webpages.charter.net/dawill/tmoranwms
From: John Larkin on 6 Jul 2010 09:53 On Mon, 5 Jul 2010 22:28:44 -0700 (PDT), whit3rd <whit3rd(a)gmail.com> wrote: >On Jul 5, 9:41�pm, John Larkin ><jjlar...(a)highNOTlandTHIStechnologyPART.com> wrote: > >> You can have two caps, C1 charged and C2 not, and transfer all the >> charge from C1 to C2, without loss. In fact, you can slosh the charge >> between them, back and forth, forever. Just don't use resistors. > >It has to be identical size capacitors, otherwise 'all the charge' >can't be transferred without adding/losing energy... Not so. John
From: John Larkin on 6 Jul 2010 09:54
On Tue, 6 Jul 2010 04:09:30 -0500, "Tim Williams" <tmoranwms(a)charter.net> wrote: >"John Larkin" <jjlarkin(a)highNOTlandTHIStechnologyPART.com> wrote in message news:noc536dna78u2claiqu2nqockk4k3liu7h(a)4ax.com... >> You can have two caps, C1 charged and C2 not, and transfer all the >> charge from C1 to C2, without loss. In fact, you can slosh the charge >> between them, back and forth, forever. Just don't use resistors. > >What if you want equal charges on both? > Easy. John |