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From: HardySpicer on 5 May 2010 06:51 On May 5, 8:57 pm, Torsten Hennig <Torsten.Hen...(a)umsicht.fhg.de> wrote: > > On May 5, 6:38 pm, Torsten Hennig > > <Torsten.Hen...(a)umsicht.fhg.de> > > wrote: > > > > What is the limit of this summation when > > > > k-->infinity. Here 'a' is a > > > > scalar > > > > k-1 > > > > p(a)=a sum (1-a)^(k-j-1) > > > > j=0 > > > > > if mag(1-a)<1 > > > > > Thanks > > > > > Hardy. > > > > Do you know > > > sum_{j=0}^{k-1} q^j > > > (geometric series) ? > > > > Best wishes > > > Torsten. > > > What is q^j? I know what a geometric series is..Do I > > define say c=(1- > > a) and then split c^(k-j-1) into c^(k-1) X c^-j ? > > > Hardy > > sum_{j=0}^{k-1} q^j = sum_{j=0}^{k-1} q^{k-j-1} > > Best wishes > Torsten. So the sum to infinity must be 1/(1-q) - is that right? Hardy |