From: HardySpicer on
What is the limit of this summation when k-->infinity. Here 'a' is a
scalar
k-1
p(a)=a sum (1-a)^(k-j-1)
j=0

if mag(1-a)<1

Thanks


Hardy.
From: Torsten Hennig on
> What is the limit of this summation when
> k-->infinity. Here 'a' is a
> scalar
> k-1
> p(a)=a sum (1-a)^(k-j-1)
> j=0
>
> if mag(1-a)<1
>
> Thanks
>
>
> Hardy.

Do you know
sum_{j=0}^{k-1} q^j
(geometric series) ?

Best wishes
Torsten.
From: HardySpicer on
On May 5, 6:38 pm, Torsten Hennig <Torsten.Hen...(a)umsicht.fhg.de>
wrote:
> > What is the limit of this summation when
> > k-->infinity. Here 'a' is a
> > scalar
> >              k-1
> > p(a)=a sum  (1-a)^(k-j-1)
> >              j=0
>
> > if mag(1-a)<1
>
> > Thanks
>
> > Hardy.
>
> Do you know
> sum_{j=0}^{k-1} q^j
> (geometric series) ?
>
> Best wishes
> Torsten.

What is q^j? I know what a geometric series is..Do I define say c=(1-
a) and then split c^(k-j-1) into c^(k-1) X c^-j ?


Hardy
From: Torsten Hennig on
> On May 5, 6:38 pm, Torsten Hennig
> <Torsten.Hen...(a)umsicht.fhg.de>
> wrote:
> > > What is the limit of this summation when
> > > k-->infinity. Here 'a' is a
> > > scalar
> > >              k-1
> > > p(a)=a sum  (1-a)^(k-j-1)
> > >              j=0
> >
> > > if mag(1-a)<1
> >
> > > Thanks
> >
> > > Hardy.
> >
> > Do you know
> > sum_{j=0}^{k-1} q^j
> > (geometric series) ?
> >
> > Best wishes
> > Torsten.
>
> What is q^j? I know what a geometric series is..Do I
> define say c=(1-
> a) and then split c^(k-j-1) into c^(k-1) X c^-j ?
>
>
> Hardy

sum_{j=0}^{k-1} q^j = sum_{j=0}^{k-1} q^{k-j-1}

Best wishes
Torsten.
From: Nams fulky on
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