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From: HardySpicer on 5 May 2010 01:26 What is the limit of this summation when k-->infinity. Here 'a' is a scalar k-1 p(a)=a sum (1-a)^(k-j-1) j=0 if mag(1-a)<1 Thanks Hardy.
From: Torsten Hennig on 4 May 2010 22:38 > What is the limit of this summation when > k-->infinity. Here 'a' is a > scalar > k-1 > p(a)=a sum (1-a)^(k-j-1) > j=0 > > if mag(1-a)<1 > > Thanks > > > Hardy. Do you know sum_{j=0}^{k-1} q^j (geometric series) ? Best wishes Torsten.
From: HardySpicer on 5 May 2010 04:48 On May 5, 6:38 pm, Torsten Hennig <Torsten.Hen...(a)umsicht.fhg.de> wrote: > > What is the limit of this summation when > > k-->infinity. Here 'a' is a > > scalar > > k-1 > > p(a)=a sum (1-a)^(k-j-1) > > j=0 > > > if mag(1-a)<1 > > > Thanks > > > Hardy. > > Do you know > sum_{j=0}^{k-1} q^j > (geometric series) ? > > Best wishes > Torsten. What is q^j? I know what a geometric series is..Do I define say c=(1- a) and then split c^(k-j-1) into c^(k-1) X c^-j ? Hardy
From: Torsten Hennig on 5 May 2010 00:57 > On May 5, 6:38 pm, Torsten Hennig > <Torsten.Hen...(a)umsicht.fhg.de> > wrote: > > > What is the limit of this summation when > > > k-->infinity. Here 'a' is a > > > scalar > > > k-1 > > > p(a)=a sum (1-a)^(k-j-1) > > > j=0 > > > > > if mag(1-a)<1 > > > > > Thanks > > > > > Hardy. > > > > Do you know > > sum_{j=0}^{k-1} q^j > > (geometric series) ? > > > > Best wishes > > Torsten. > > What is q^j? I know what a geometric series is..Do I > define say c=(1- > a) and then split c^(k-j-1) into c^(k-1) X c^-j ? > > > Hardy sum_{j=0}^{k-1} q^j = sum_{j=0}^{k-1} q^{k-j-1} Best wishes Torsten.
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