Proposed and Past Experiments Detecting Absolute Motion.
in [Relativity]
|
Prev: Imagine the pressure you'd feel at the bottom of the Mariana Trench.
Next: The REAL reason they hate Einstein.
From: kenseto on 6 Nov 2009 15:46 On Nov 6, 2:05 pm, Sam Wormley <sworml...(a)mchsi.com> wrote: > kens...(a)erinet.com wrote: > > On Nov 5, 12:57 am, Sam Wormley <sworml...(a)mchsi.com> wrote: > >>   Notice what happens to A and B, Ken! > >>    http://xkcd.com/265/ > > > Wormy you are loosing it I urge that you go see a doctor immediately. > > There is no mutual time dilation. When comparing two clocks: if A's > > clock is running fast compared to B's clock then B's clock is running > > slow compared to A's clock. > > > Ken Seto > >   I've tried to clarify the language below for you, Seto, so that >   you will see neither A or B is preferred or special in any way. That's because every SR observer make the same assumption: that he is at rest in the preferred ether frame and that's why his clock is the fastest running clock in the universe. > >   Assume that A and B have identical atomic clocks. That means they >   tick at the same rate. Now let us suppose that A and B have relative >   motion, such that their velocity with respect to each other, v > 0, >   and that dv/dt = 0 . Here's your problem: A's clock ticks at different rate than B's clcok when they are in relative motion and thus they don't measure the same v between them. > >   Disregarding any Doppler shift, A measures B's time dilation as >    ât_B' = γ ât_B We went through this before....According to SR A predicts B's time dilation as follows: Delta(t_B') = Delta(t_A)/gamma_A Ken Seto > >   and B measures A's time dilation as >    ât_A' = γ ât_A > >   where ât represent a time interval, v is the relative velocity >   between A and B, and γ = 1/â(1-v^2/c^2) .
From: BURT on 6 Nov 2009 15:49
On Nov 6, 12:46 pm, kenseto <kens...(a)erinet.com> wrote: > On Nov 6, 2:05 pm, Sam Wormley <sworml...(a)mchsi.com> wrote: > > > kens...(a)erinet.com wrote: > > > On Nov 5, 12:57 am, Sam Wormley <sworml...(a)mchsi.com> wrote: > > >>   Notice what happens to A and B, Ken! > > >>    http://xkcd.com/265/ > > > > Wormy you are loosing it I urge that you go see a doctor immediately. > > > There is no mutual time dilation. When comparing two clocks: if A's > > > clock is running fast compared to B's clock then B's clock is running > > > slow compared to A's clock. > > > > Ken Seto > > >   I've tried to clarify the language below for you, Seto, so that > >   you will see neither A or B is preferred or special in any way. > > That's because every SR observer make the same assumption: that he is > at rest in the preferred ether frame and that's why his clock is the > fastest running clock in the universe. > > > > >   Assume that A and B have identical atomic clocks. That means they > >   tick at the same rate. Now let us suppose that A and B have relative > >   motion, such that their velocity with respect to each other, v > 0, > >   and that dv/dt = 0 . > > Here's your problem: A's clock ticks at different rate than B's clcok > when they are in relative motion and thus they don't measure the same > v between them. > > > > >   Disregarding any Doppler shift, A measures B's time dilation as > >    ât_B' = γ ât_B > > We  went through this before....According to SR A predicts B's time > dilation as follows: > Delta(t_B') = Delta(t_A)/gamma_A > > Ken Seto > > > > > > >   and B measures A's time dilation as > >    ât_A' = γ ât_A > > >   where ât represent a time interval, v is the relative velocity > >   between A and B, and γ = 1/â(1-v^2/c^2) .- Hide quoted text - > > - Show quoted text - WEight gives detectability to motion in the universe by allowing the measerment new motion. Mitch Raemsch |