Simultaneity of Relativity
in [Math]
|
Prev: chrouc
Next: Synergetics coordinates and Wikipedia
From: Dono. on 24 Oct 2009 14:10 On Oct 24, 7:34 am, mpc755 <mpc...(a)gmail.com> wrote: > > The MM experiment did not find the aether because it is entrained by > the Earth. > Hammar experiment says that you are an idiot.
From: mpc755 on 24 Oct 2009 14:17 On Oct 24, 2:10 pm, "Dono." <sa...(a)comcast.net> wrote: > On Oct 24, 7:34 am, mpc755 <mpc...(a)gmail.com> wrote: > > > The MM experiment did not find the aether because it is entrained by > > the Earth. > > Hammar experiment says that you are an idiot. Great, instead of filling a telescope with water you place lead blocks near the interferometer. http://en.wikipedia.org/wiki/Hammar_experiment "The study of stellar aberration provides a less ambiguous test of Aether drag and is the most widely accepted evidence against the hypothesis." So, filling a telescope with water because aether 'sticks' to water and not to air is a better test than the Hammar experiment. You're heading in the wrong direction idiot.
From: Greg Neill on 24 Oct 2009 15:38 mpc755 wrote: > On Oct 24, 1:13 pm, "Greg Neill" <gneil...(a)MOVEsympatico.ca> wrote: >> >> Nonsense. The difference is relative velocity between >> entrained and unentrained would be equal to (at least) >> the orbital speed of the Earth, and would occur over a >> relatively short distance (on the order of an Earth radius). >> >> This would produce obvious aberration effects. >> > > Nonsense. The light 'bullet' cuts through the hurricane winds. How do > you detect aberration effects on the light 'bullet' if you are in the > eye of the hurricane? So is light a disturbance in the aether or not? Make up your mind. If it's a particle that 'cuts through' the aether, what's the aether for? If it's a motion of the aether, then anything that results in relative motion of different volumes of the aether must cause obvious aberration effects. > >> As for the Sun, if it's taken to be essentially at rest >> in the center of the solar system then there could be >> no aberration or deflection effect. If it's taken to >> be in motion about the center of the galaxy then it the >> aberration should be nonuniform -- stretched out along >> the diection of motion. Neither of these situations are >> observed. >> > > The Sun entrains the aether to Uranus. The Pioneer effect is due to > the Pioneer satellites 'falling out of' the Sun's entrained aether. > The effect of light waves within the Sun's entrained aether is going > to be uniform and not stretched. Well, that's just crazy talk. Goombye. [rest of lunacy ignored and snipped]
From: kenseto on 24 Oct 2009 16:35 On Oct 24, 11:45 am, mpc755 <mpc...(a)gmail.com> wrote: > On Oct 24, 11:18 am, kenseto <kens...(a)erinet.com> wrote: > > > On Oct 23, 11:32 pm, mpc755 <mpc...(a)gmail.com> wrote: > > > > I didn't say you said the observer is at rest in the aether. I said > > > you said no observer is at rest in the aether. No observer at rest in > > > the aether but the aether being at rest in all frames of reference is > > > physically impossible. > > > In didn't say that the aether is at rest in all inertial frames. I > > said that all objects are in a state of absolute motion in the aether. > > If the object is at rest in its frame of reference and the aether is > at rest in the frame of reference, then the object is at rest in the > aether. Sigh....no object is at rest in the aether. > > If the aether is in motion relative to the frames of reference, then > the marks made by the lightning strike at A/A' and B/B' are irrelevant > in terms of where the light travels from without knowing how the > aether is in motion relative to the train frame of reference and the > embankment frame of reference. The speed of light is isotropic in all inertial frames. As long as the observer is at equal distance from the strikes when they happened simultaneously then the observer will see the light fronts from the strikes arrive at him simultaneously. M and M' meet these conditions and thus they will see the strikes arrive at each of them simultaneously. The position of M' relative to M is irrelevant after the strikes happened will have no effect on the simultaneity of arrival of the light fronts from the strikes. Ken Seto > > Light propagates outward at 'c' similar to dropping a pebble into a > pool of water. If the pool of water is on the train, then the wave > will ripple outward from the point on the train. If the pool of water > is stationary relative to the embankment, the wave will ripple outward > relative to the point in three dimensional space in the embankment > frame of reference. > > I realize you are going to keep having it both ways, where the aether > is in motion relative to the frame of reference without impacting the > propagation of light, but that is what I am saying is incorrect. > > Light travels at 'c' relative to the aether, not a frame of reference.
From: mpc755 on 24 Oct 2009 16:42
On Oct 24, 3:38 pm, "Greg Neill" <gneil...(a)MOVEsympatico.ca> wrote: > mpc755 wrote: > > On Oct 24, 1:13 pm, "Greg Neill" <gneil...(a)MOVEsympatico.ca> wrote: > > >> Nonsense. The difference is relative velocity between > >> entrained and unentrained would be equal to (at least) > >> the orbital speed of the Earth, and would occur over a > >> relatively short distance (on the order of an Earth radius). > > >> This would produce obvious aberration effects. > > > Nonsense. The light 'bullet' cuts through the hurricane winds. How do > > you detect aberration effects on the light 'bullet' if you are in the > > eye of the hurricane? > > So is light a disturbance in the aether or not? Make > up your mind. If it's a particle that 'cuts through' > the aether, what's the aether for? If it's a motion > of the aether, then anything that results in relative > motion of different volumes of the aether must cause > obvious aberration effects. > It can't be known is a wave in the aether that when it collapses behaves as a particle or a photon is a particle of aether creating a wave in the aether. If it's a particle of aether it is creating an aether displacement wave in the aether just like any particle would. How do you detect the 'obvious' aberration effects and why must they be 'obvious'. In a binary star system the light wave of one star is under the influence of the entrained aether of the star it was emitted from and then the light wave is under the influence of the entrained aether of both stars. When to photon is detected on Earth, how are we to detect the changes the light wave underwent as it transitioned from the entrained aether of the star to the entrained aether of both stars? If we go back to the pebble being dropped into a whirlpool within a whirlpool analogy, if all we detect from the ripple the pebbles makes in the whirlpool is a 'particle' of the ripple when it reaches the Earth, how are we ever going to be able to detect the changes the ripple underwent as it transitioned from the local whirlpool it originated in to the whirlpool it transitioned into? > > > >> As for the Sun, if it's taken to be essentially at rest > >> in the center of the solar system then there could be > >> no aberration or deflection effect. If it's taken to > >> be in motion about the center of the galaxy then it the > >> aberration should be nonuniform -- stretched out along > >> the diection of motion. Neither of these situations are > >> observed. > > > The Sun entrains the aether to Uranus. The Pioneer effect is due to > > the Pioneer satellites 'falling out of' the Sun's entrained aether. > > The effect of light waves within the Sun's entrained aether is going > > to be uniform and not stretched. > > Well, that's just crazy talk. Goombye. > Once the Pioneer satellites pass Uranus, the rate of departure from the solar system unexpectedly slows down. Some refer to this as an acceleration back towards the Sun. What occurs is the entrained aether of the Sun ends just past Uranus and that is why Uranus rotates on its side relative to the plane of the solar system but the magnetic field is still at 60 degrees to the plane of the solar system. It is most likely all of the planets formed and their rotations and magnetic fields were one in the same at the time of their formations. One guess as to why Uranus rotates on its side is the aether wave associated with a body knocked Uranus' matter on its side where its interaction with the Sun's entrained aether rotate Uranus to its present state. Since Uranus' magnetic field is a vortex in the aether, the interaction with the aether wave of the body did interacted with the magnetic field but the interaction was similar to the interaction of two waves, where once the interaction has passed, both waves return to their previous form, keeping Uranus' magnetic field at 60 degrees from the plane of the universe. |