From: Lester Zick on
On Tue, 24 Apr 2007 19:17:01 -0400, Tony Orlow <tony(a)lightlink.com>
wrote:

>Lester Zick wrote:
>> On Tue, 24 Apr 2007 09:27:05 -0400, Tony Orlow <tony(a)lightlink.com>
>> wrote:
>>
>>>> And here the matter has rested for mathematics and science in general
>>>> ever since. Empiricism benefitted from perceptual appearances of truth
>>>> in their experimental results but the moment empirics went beyond them
>>>> to explain results in terms of one another they were hoist with the
>>>> Aristotelian petard of being unable to demonstrate what was actually
>>>> true and what not. The most mathematicians and scientists were able to
>>>> say at the post perceptual conceptual level was that "If A then B then
>>>> C . . ." etc. or "If our axiomatic assumptions of truth actually prove
>>>> to be true then our theorems, inferences, and so forth are true". But
>>>> there could never be any guarantee that in itself was true.
>>
>>> Well, if the axiom systems we develop produce the results we expect
>>> mathematically, then we can be satisfied with them as starting
>>> assumptions upon which to build. My issue with transfinite set theory is
>>> that it produces a notion of infinite "size" which I find
>>> unsatisfactory. I accept that bijection alone can define equivalence
>>> classes of sets, but I do not accept that this is anything like an
>>> infinite "number". So, that's why I question the axioms of set theory.
>>> Of course, one cannot do "experiments" on infinite set sizes. In math,
>>> one can only judge the results based on intuition.
>>
>> I was discussing Aristotelian syllogistic inference and truisms here,
>> Tony. So I don't know why you're talking transfinite sets and so on.
>>
>> ~v~~
>
>You're talking about logical deduction and starting assumptions, right?

Well actually I was talking about the logic of deduction and the
deductive demonstration of the truth of starting assumptions.

>I am responding with measuring starting assumptions by the conclusions
>that can be deduced from them.

Which is known as empiricism. Postulate a set of starting assumptions
and validate those assumptions based on the apparent utility of their
predictions.

> Perhaps you are questioning the nature of
>logical implication itself. If so, how do you propose to derive logical
>implication?

Just the way I have: by regressing the nature of truth in general to
alternatives to self contradiction in universal terms and application
of the principle compounded in terms of itself to boolean conjunctions
and mathematics as well as science of all kinds.

~v~~
From: Lester Zick on
On Tue, 24 Apr 2007 19:21:19 -0400, Tony Orlow <tony(a)lightlink.com>
wrote:

>Lester Zick wrote:
>> On Tue, 24 Apr 2007 09:27:05 -0400, Tony Orlow <tony(a)lightlink.com>
>> wrote:
>>
>>>>> If I say 3x+3=3(x+1) is that true?
>>>>> Yes, it's true for all x.
>>>> How about for x=3/0?
>>>>
>>> Division by pure 0 is proscribed because it produces an unmeasurable oo.
>>> If x is any specific real, or hyperreal, or infinitesimal, then that
>>> statement is true for all x. 3/0 is not a specific number.
>>
>> In other words the statement isn't true for all x.
>>
>> ~v~~
>
>It's true for all x in R, all real numbers. I kind of thought that was
>understood. I suppose if you want to say x is a chicken, or a tissue, or
>a 3/0, then in a sense it's still true, but I meant it as an arithmetic
>expression, with x as a real number.

Trick question, Tony. Not really an issue.

~v~~
From: Lester Zick on
On Wed, 25 Apr 2007 01:36:01 +0100, Ben newsam
<ben.newsam.remove.this(a)gmail.com> wrote:

>On Tue, 24 Apr 2007 15:12:19 -0700, Lester Zick
><dontbother(a)nowhere.net> wrote:
>
>>On Tue, 24 Apr 2007 09:27:05 -0400, Tony Orlow <tony(a)lightlink.com>
>>wrote:
>>
>>>>> If I say 3x+3=3(x+1) is that true?
>>>>> Yes, it's true for all x.
>>>>
>>>> How about for x=3/0?
>>>>
>>>
>>>Division by pure 0 is proscribed because it produces an unmeasurable oo.
>>>If x is any specific real, or hyperreal, or infinitesimal, then that
>>>statement is true for all x. 3/0 is not a specific number.
>>
>>In other words the statement isn't true for all x.
>
><Sigh> Tap * Dance = Porridge

What is this preoccupation you seem to have with oatmeal, Ben?

~v~~
From: Lester Zick on
On Tue, 24 Apr 2007 19:25:44 -0400, Tony Orlow <tony(a)lightlink.com>
wrote:

>Lester Zick wrote:
>> On Tue, 24 Apr 2007 09:27:05 -0400, Tony Orlow <tony(a)lightlink.com>
>> wrote:
>>
>>>>> If I say a or not a, that's true for all a. a and b are
>>>>> variables, which may each assume the value true or false.
>>>> Except you don't assign them the value true or false; you assign them
>>>> the value 1 or 0 and don't bother to demonstrate the "truth" of either
>>>> 1 or 0.
>>>>
>>> 1 is true, 0 is false. If a is 0 or 1, then we have "0 or 1", or "1 or
>>> 0", respectively. Since or(a,b) is true whenever a is true or b is true,
>>> or both, or(1,0) and or(0,1), the only possible values for the
>>> statement, are both true. So, or(a,not(a)) is always true, in boolean
>>> logic, or probability.
>>>
>>> Intuitively, if a is a subset of the universe, and not(a) is everything
>>> else, then the sum of a and not(a) is very simply the universe, which is
>>> true.
>>
>> Yeah but you still haven't proven that 1 is true and 0 false or what
>> either of these terms has to mean in mechanically exhaustive terms.
>>
>> ~v~~
>
>I declare that logical statements have values of 0 or 1, or perhaps in
>between those two. "False" and "True" are just names for 0 and 1. I
>showed how they define each other using not(x), and how not(x) is the
>only 1-place operator. What's left?

What's left is that "true" and "false" are only your names for 1 and
0, Tony. I don't care what names you use you're still talking 1 and 0
and that's not the same as true and false. If you developed the ideas
of true and false independently and demonstrated their truth in
mechanically reduced exhaustive terms then you could name them
anything you want and they would still mean true and false. But
developing the idea of TvN binary 1 and 0 mathematically doesn't mean
they're true and false regardless of the names you give them.

~v~~
From: Lester Zick on
On Wed, 25 Apr 2007 01:39:21 +0100, Ben newsam
<ben.newsam.remove.this(a)gmail.com> wrote:

>On Tue, 24 Apr 2007 15:15:45 -0700, Lester Zick
><dontbother(a)nowhere.net> wrote:
>
>>On Tue, 24 Apr 2007 09:27:05 -0400, Tony Orlow <tony(a)lightlink.com>
>>wrote:
>>
>>>>> If I say a or not a, that's true for all a. a and b are
>>>>> variables, which may each assume the value true or false.
>>>>
>>>> Except you don't assign them the value true or false; you assign them
>>>> the value 1 or 0 and don't bother to demonstrate the "truth" of either
>>>> 1 or 0.
>>>>
>>>
>>>1 is true, 0 is false. If a is 0 or 1, then we have "0 or 1", or "1 or
>>>0", respectively. Since or(a,b) is true whenever a is true or b is true,
>>>or both, or(1,0) and or(0,1), the only possible values for the
>>>statement, are both true. So, or(a,not(a)) is always true, in boolean
>>>logic, or probability.
>>>
>>>Intuitively, if a is a subset of the universe, and not(a) is everything
>>>else, then the sum of a and not(a) is very simply the universe, which is
>>>true.
>>
>>Yeah but you still haven't proven that 1 is true and 0 false or what
>>either of these terms has to mean in mechanically exhaustive terms.
>
>Try this: "1" is everything or anything. "0" is whatever "1" is not.
>You may assign the terms "true" and "false" if you wish. Or vice
>versa.

Yeah and when you do, Ben, all you'll have are TvN binary 1 and 0 and
not "true" and "false". A rose by any other name would still be binary
1 and 0 because all you've done is develop 1 and 0 mathematically and
not in terms of what true and false really mean and necessarily have
to mean in mechanically reduced exhaustive universal terms.

~v~~