The proof of mass vector.
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From: Phineas T Puddleduck on 30 Apr 2007 20:39 In article <1177979661.867169.127340(a)y80g2000hsf.googlegroups.com>, Ka-In Yen <yenkain(a)yahoo.com.tw> wrote: > On May 1, 8:23 am, Phineas T Puddleduck <phineaspuddled...(a)gmail.com> > wrote: > > In article <1177978829.894994.272...(a)n76g2000hsh.googlegroups.com>, > > Ka-In Yen <yenk...(a)yahoo.com.tw> wrote: > > > > > On Apr 28, 9:19 am, Bob Kolker <nowh...(a)nowhere.com> wrote: > > > > Ka-In Yen wrote: > > > > > > > This is a question for high school student. You should > > > > > ask your high school teacher. > > > > > > I am asking YOU. What is the direction of an area? > > > > > Dear Dr. David Kirkby, > > > > > I am not responsible for your high school eduation and > > > there is no free e-tutoring any more. > > > > So you can't answer the question then. Considering YOU are the one > > espousing > > new information, the onus is on YOU to answer questions, or are you afraid > > that > > your ignorance has already been roundly shown to one and all? > > I will not be afraid to answer his question, if you pay > me US$1,000. BWAHAHAHAHHAHHAHAHAHHAHAHAHHAHAHHAHAHHAHAHHAHAHAHHAHAHHAHHAHAHA -- Sacred keeper of the Hollow Sphere, and the space within the Coffee Boy singularity. COOSN-174-07-82116: alt.astronomy's favourite poster (from a survey taken of the saucerhead high command).
From: Eric Gisse on 30 Apr 2007 22:22 On Apr 30, 4:34 pm, Ka-In Yen <yenk...(a)yahoo.com.tw> wrote: > On May 1, 8:23 am, Phineas T Puddleduck <phineaspuddled...(a)gmail.com> > wrote: > > > > > In article <1177978829.894994.272...(a)n76g2000hsh.googlegroups.com>, > > Ka-In Yen <yenk...(a)yahoo.com.tw> wrote: > > > > On Apr 28, 9:19 am, Bob Kolker <nowh...(a)nowhere.com> wrote: > > > > Ka-In Yen wrote: > > > > > > This is a question for high school student. You should > > > > > ask your high school teacher. > > > > > I am asking YOU. What is the direction of an area? > > > > Dear Dr. David Kirkby, > > > > I am not responsible for your high school eduation and > > > there is no free e-tutoring any more. > > > So you can't answer the question then. Considering YOU are the one espousing > > new information, the onus is on YOU to answer questions, or are you afraid that > > your ignorance has already been roundly shown to one and all? > > I will not be afraid to answer his question, if you pay > me US$1,000. I think you are overestimating your worth. By about 1000$ USD.
From: Ka-In Yen on 5 May 2007 20:55 Mathematically, I proved that Einstein was ill-trained in 3D vector algebra; STR was based on incomplete physical mathematics. Logically, STR is totally nonsense. The proof of mass vector. Ka-In Yen http://www.geocities.com/redlorikee Introduction: In this paper, we will prove that linear mass density and surface mass density are vector, and the application of mass vector is presented. 1. The unit of vector. In physics, The unit of three-dimensional cartesian coordinate systems is meter. In this paper, a point of 3-D coordinate system is written as (p1,p2,p3) m, or (p:3) m and a vector is written as <a,b,c> m, or <a:3> m or l m<i,j,k> = <a,b,c> m where l=abs(sqrt(a^2+b^2+c^2)) is the magnitude of the vector, and <i,j,k> is a unit vector which gives the direction of the vector. For three reasons, a magnitude of a vector can not add to a scalar: i) The magnitude belongs to the set of vector; it's a portion of a vector. Scalar belongs to a field. ii) The magnitude is real non-negative number, but scalar is real number. iii) The unit of magnitude is meter, but scalar has no unit. This is a major difference between physics and mathematics. 5m+3 is meaningless. 2. Linear mass density is a vector. The mass of a string is M kg, and the length of the string is l m<i:3>. Where l m is the magnitude of the length, and <i:3> is a 3-D unit vector which gives the direction of the string. Then the linear mass density of the string is: M/(l<i:3>)=(M/l) (kg/m)<i:3> The direction, <i:3>, is not changed by "division", so we can move <i:3> from denominator to numerator. A direction is changed by -1 only. A proof is found in Clifford algebras: [Proof] k/<a,b,c>=[k<a,b,c>]/[<a,b,c>^2] =(k/l) <i,j,k> where l is the magnitude of <a,b,c>, and <i,j,k> is the unit vector of <a,b,c>. [Proof] 3. Surface mass density is a vector. A parallelogram has two vectors: l m<i:3> and h m<j:3>. <i:3> and <j:3> are unit vectors. The area vector of the parallelogram is the cross product of these two vectors. l m<i:3> X h m<j:3>= lh (m^2 )<i:3>X<j:3> = lh abs(sin(theta)) (m^2)<k:3> Where theta is the angle between <i:3> and <j:3>. <k:3> is a unit vector which is perpendicular to <i:3> and <j:3>. For AXB=-BXA, an area has two directions. We can divide the area vector by the length vector. lh*abs(sin(theta))<k:3>/[l<i:3>] =h<i:3>X<j:3>/<i:3> =h(<i:3>X<j:3>)X<i:3> (The direction, <i:3>, is not changed by "division", and the division is replaced by a cross product.) =-h<i:3>X(<i:3>X<j:3>) =-h[<i:3>(<i:3>o<j:3>)-<j:3>(<i:3>o<i:3>)] (where o is dot product.) =-h(cos(theta)<i:3>-<j:3>) =h(<j:3>-cos(theta)<i:3>) m The result is a rectangle, not the original parallelogram. We can test the result. h(<j:3>-cos(theta)<i:3>)Xl<i:3>=lh m^2<j:3>X<i:3> The magnitude of the area vector is conserved, but the direction is opposite. The mass of a round plate is M kg, and the area vector is A m^2<i:3>; then the surface mass density is M kg/(A m^2<i:3>)=M/A (kg/m^2)<i:3> 4. Mass vector in physics. Mass vector has been found in two equations: 1) the velocity equation of string. 2) Bernoulli's equation. i) For waves on a string, we have the velocity equation: v=sqrt(tau/mu). v is velocity of wave, tau is tension applying to string, and mu is linear mass density of string. We can rewrite the equation: mu=tau/v^2. In the above equation, the mu is parallel to tau, and both of them are vector. ii) Bernoulli's equation is: P + k*v^2/2=C (P is pressure, k is volume density, and v is velocity. Here we neglect the gravitational term.) Multiplying cross area vector A m^2<i:3> of a string to Bernoulli's equation(where <i:3> is a unit vector), P*A<i:3> + k*A<i:3>*v^2/2=C*A<i:3> F<i:3> + L<i:3>*v^2/2=C*A<i:3> (where F is the magnitude of force, and L is the magnitude of linear mass density.) These two equations are well used in the theory "Magnetic force: Combining Drag force and Bernoulli force of ether dynamics." For detail, please refer to my site: http://www.geocities.com/redlorikee
From: Phineas T Puddleduck on 5 May 2007 21:17 In article <1178412906.381285.115270(a)u30g2000hsc.googlegroups.com>, Ka-In Yen <yenkain(a)yahoo.com.tw> wrote: > Mathematically, I proved that Einstein was > ill-trained in 3D vector algebra; STR was based > on incomplete physical mathematics. Logically, > STR is totally nonsense. You have only proved that you are an idiot. -- Sacred keeper of the Hollow Sphere, and the space within the Coffee Boy singularity. COOSN-174-07-82116: alt.astronomy's favourite poster (from a survey taken of the saucerhead high command).
From: Ka-In Yen on 6 May 2007 20:26
On May 6, 9:17 am, Phineas T Puddleduck <phineaspuddled...(a)gmail.com> wrote: > In article <1178412906.381285.115...(a)u30g2000hsc.googlegroups.com>, > Ka-In Yen <yenk...(a)yahoo.com.tw> wrote: > > > Mathematically, I proved that Einstein was > > ill-trained in 3D vector algebra; STR was based > > on incomplete physical mathematics. Logically, > > STR is totally nonsense. > > You have only proved that you are an idiot. Go play your video game; NG is for college students who study very hard. |