There is no “pull” of gravity, only the PUSH of flowing ether!
in [Physics]
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From: NoEinstein on 12 Feb 2010 15:45 On Feb 10, 8:13 pm, "n...(a)bid.nes" <alien8...(a)gmail.com> wrote: > Dear Mark: Most of the 'bulge' of tides is due to the rotation of the Earth relative to the plane of the Moon's orbit. When that plane aligns with the equator, the bulge gets higher. I don't have data on the relative resistance of water vs. land to ether flow. But it's probably mass proportionalmeaning that ether passes through the oceans with little effect on the level of the water. The total ether flow due to the radiation between the Earth and the Moon doesn't have to occur uniformly across the opposing side of the Earth. Since 75% of Earth's land mass is in the Northern Hemisphere, it's likely that ether losses due to radiation won't be replenished through the oceans (as much) because the oceans act like insulators. The above are some of the principles affecting the tides. Thanks for asking! NoEinstein > > On Feb 10, 3:59 pm, NoEinstein <noeinst...(a)bellsouth.net> wrote: > > > Yesterday, I happened to tune-in for the last half of a TV program > > about the Moon. Time and again, the supposed technical experts who > > were being interviewed referred to the pull of gravity between the > > Earth and the Moon. The effect of that pull was discussed as > > relates to such things as ocean tides > > Please explain ocean tides with push gravity. > > Mark L. Fergerson
From: NoEinstein on 12 Feb 2010 15:54 On Feb 11, 1:24 am, john <vega...(a)accesscomm.ca> wrote: > Dear John: Particles DON'T produce unlimited radiation unless the lost ether gets replenished! Gamma rays, which have mass, must emit photons. But the number of photons is quite small, since the mass is quite small. Gamma rays replenish their lost photons by banging into the ether as they travel. Since the tangential velocity of the IOTAs (smallest energy units of the ether) is 'c', then the gamma rays can keep right on traveling at velocity 'c' for a very long time. NoEinstein > > On Feb 10, 7:13 pm, "n...(a)bid.nes" <alien8...(a)gmail.com> wrote: > > > On Feb 10, 3:59 pm, NoEinstein <noeinst...(a)bellsouth.net> wrote: > > > > Yesterday, I happened to tune-in for the last half of a TV program > > > about the Moon. Time and again, the supposed technical experts who > > > were being interviewed referred to the pull of gravity between the > > > Earth and the Moon. The effect of that pull was discussed as > > > relates to such things as ocean tides > > > Please explain ocean tides with push gravity > > First explain how every particle of the universe > can produce unlimited radiations which travel outward from > said particles while all the while providing inward impetus > to anything with which they interact. > Don't you think that's stretching it just a tad? > ('Course since then there's DM, DE, so really, > suck gravity is hardly outrageous at all compared > to 'intellectuallizing' a whole new class of matter, > sight unseen )('Course, if it's invisible, well, it's > invisible- but we prove it's there by pointing to > the movements of stars that occasioned its creation > in the first place.So it's real yin/yangy, y'know.) > > But the tide thing- really, everything at this scale- > works exactly the same for push as for pull. > Just at larger sizes, where planets > are able to completely shadow push from the other side, > surface gravity will tend towards a limit- therefore ruling out > the whole black hole paradox. > > john
From: PD on 12 Feb 2010 16:17 On Feb 12, 2:54 pm, NoEinstein <noeinst...(a)bellsouth.net> wrote: > On Feb 11, 1:24 am, john <vega...(a)accesscomm.ca> wrote: > > Dear John: Particles DON'T produce unlimited radiation unless the > lost ether gets replenished! Something must be producing all this aether to push with, no? > Gamma rays, which have mass, must emit > photons. Oh, John, John, John. Gamma rays ARE photons. http://www.epa.gov/rpdweb00/understand/gamma.html > But the number of photons is quite small, since the mass is > quite small. Gamma rays replenish their lost photons by banging into > the ether as they travel. Since the tangential velocity of the IOTAs > (smallest energy units of the ether) is 'c', then the gamma rays can > keep right on traveling at velocity 'c' for a very long time. > NoEinstein > > > > > On Feb 10, 7:13 pm, "n...(a)bid.nes" <alien8...(a)gmail.com> wrote: > > > > On Feb 10, 3:59 pm, NoEinstein <noeinst...(a)bellsouth.net> wrote: > > > > > Yesterday, I happened to tune-in for the last half of a TV program > > > > about the Moon. Time and again, the supposed technical experts who > > > > were being interviewed referred to the pull of gravity between the > > > > Earth and the Moon. The effect of that pull was discussed as > > > > relates to such things as ocean tides > > > > Please explain ocean tides with push gravity > > > First explain how every particle of the universe > > can produce unlimited radiations which travel outward from > > said particles while all the while providing inward impetus > > to anything with which they interact. > > Don't you think that's stretching it just a tad? > > ('Course since then there's DM, DE, so really, > > suck gravity is hardly outrageous at all compared > > to 'intellectuallizing' a whole new class of matter, > > sight unseen )('Course, if it's invisible, well, it's > > invisible- but we prove it's there by pointing to > > the movements of stars that occasioned its creation > > in the first place.So it's real yin/yangy, y'know.) > > > But the tide thing- really, everything at this scale- > > works exactly the same for push as for pull. > > Just at larger sizes, where planets > > are able to completely shadow push from the other side, > > surface gravity will tend towards a limit- therefore ruling out > > the whole black hole paradox. > > > john
From: NoEinstein on 12 Feb 2010 16:17 On Feb 11, 11:24 pm, "n...(a)bid.nes" <alien8...(a)gmail.com> wrote: > Dear Mark: My original post wasn't intended to be 'just' about tides. For years I heard about there being a supposed particle of exchange called a... GRAVITRON. When I realized that gravity is downward flowing ether, it wasn't hard to reason that the downward flow of anything can't long continue without having the ether be replinished. Photons go upward from massive objects like machine gun bullets through falling snow. The only difference between the snow and the bullets is the velocity. Photon are like a conveyor belt to carry ether away from the masswhere such becomes available to flow downward, again. NoEinstein > > On Feb 10, 10:24 pm, john <vega...(a)accesscomm.ca> wrote: > > > On Feb 10, 7:13 pm, "n...(a)bid.nes" <alien8...(a)gmail.com> wrote: > > > > On Feb 10, 3:59 pm, NoEinstein <noeinst...(a)bellsouth.net> wrote: > > > > > Yesterday, I happened to tune-in for the last half of a TV program > > > > about the Moon. Time and again, the supposed technical experts who > > > > were being interviewed referred to the pull of gravity between the > > > > Earth and the Moon. The effect of that pull was discussed as > > > > relates to such things as ocean tides > > > > Please explain ocean tides with push gravity > > (snip whining) > > > really, everything at this scale- > > works exactly the same for push as for pull. > > Nonsense. Push gravity claims the moon shadows the gravitation from > the rest of the universe on the surface of the Earth directly under > the moon, which raises the tides on the ocean under the moon. > > What about the equally raised tide on the side of the Earth exactly > opposite the Moon? > > Mark L. Fergerson
From: nuny on 12 Feb 2010 20:33
On Feb 12, 1:17 pm, NoEinstein <noeinst...(a)bellsouth.net> wrote: > On Feb 11, 11:24 pm, "n...(a)bid.nes" <alien8...(a)gmail.com> wrote: > > Dear Mark: My original post wasn't intended to be 'just' about > tides. It's obvious that push gravity can explain the immediate sublunar tide easily; the ocean shadowed by the moon from the incoming aether is free to expand under the lateral pressure of the rest of the ocean which *is* subject to the pressure of the incoming aether. But the tide has *two* lobes; one directly under the moon and one at the antipodal point. Please explain these diagrams using push gravity: http://curious.astro.cornell.edu/images/tides.jpg Specifically, please explain the rising water on the side of the planet *away from* the Sun and Moon. Note the height of the rise on both sides of the planet is about equal. Ordinary "pull" gravity explains this effect nicely along with many other observed effects. After you've done this we can discuss orbits. Mark L. Fergerson |