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From: Newberry on 28 Mar 2010 00:46 On Mar 27, 4:59 am, stevendaryl3...(a)yahoo.com (Daryl McCullough) wrote: > Newberry says... > > > > >On Mar 26, 3:49=A0am, stevendaryl3...(a)yahoo.com (Daryl McCullough) > >wrote: > >> The Liar sentence is not *expressible* in any standard mathematical > >> theory (PA or ZFC). So you don't have to do anything to keep the Liar > >> from spoiling the consistency of those languages. > > >Why you think you have to tell me that I do not know. If you lool a > >few lines above you will see that I was talking about the Liar paradox > >in the natural language. > > So your theory of truth gaps is only for natural language? No. > So you > agree that formal languages such as arithmetic don't require any > truth gaps? No. > > -- > Daryl McCullough > Ithaca, NY
From: Newberry on 28 Mar 2010 00:49 On Mar 27, 6:26 am, "Jesse F. Hughes" <je...(a)phiwumbda.org> wrote: > Newberry <newberr...(a)gmail.com> writes: > > On Mar 26, 3:50 am, "Jesse F. Hughes" <je...(a)phiwumbda.org> wrote: > >> Newberry <newberr...(a)gmail.com> writes: > >> > On Mar 25, 3:49 am, stevendaryl3...(a)yahoo.com (Daryl McCullough) > >> > wrote: > >> >> Newberry says... > > >> >> >Tarski's theorem does not apply to formal systems with gaps. I think > >> >> >it is preferable. > > >> >> If you the way you express Tarski's theorem is like this, then truth > >> >> gaps don't change anything: > > >> >> There is no formula T(x) such that if x is a Godel code of a true > >> >> sentence, then T(x) is true, and otherwise, ~T(x) is true. > > >> >> Anyway, *why* is it preferable to have a formal system for which Tarki's > >> >> theorem does not apply? Preferable for what purpose? > > >> > If truth is expressible then truth can be equivalent to provabilty. > > >> So, you'd like to redefine truth (so that vacuously *true* statements > >> aren't true) and also redefine provability (so trivially provable > >> statements aren't provable) in such a way that truth is equivalent to > >> provability. > > >> Then what have you accomplished? Hell, I can do that simply by > >> requiring that nothing is true and nothing is provable. My "fix" is > >> better than yours, insofar as we can see that it actually "works". > > > My theory has some significant advantages over yours. I can go to a > > grocery store and count how many tomatoes and bananas I have picked. > > If I have picked 2 small tomatoes and three large tomatoes my theory > > can prove that I have 5 tomatoes. Also at the checkout counter I can > > calculate the total price. Can your theory do that? > > No. You're right. The classical theory of arithmetic I thought that we were talking about your theory where "nothing is true and nothing is provable." > is incapable of > proving that 2 + 3 = 5. > > I see now that your theory is superior and will alter my brain > accordingly. > > (Honestly, I have no idea what you're talking about. You seem to see > a disadvantage in classical arithmetic that I simply don't see. Why > not explain your point?) > > -- > Jesse F. Hughes > > "I post for many reasons [...] and there's no reason to think that > I'll stop." -- James S. Harris- Hide quoted text - > > - Show quoted text -
From: Newberry on 28 Mar 2010 00:57 On Mar 27, 4:56 am, stevendaryl3...(a)yahoo.com (Daryl McCullough) wrote: > Newberry says... > > >L: ~T(L) > > >If v(L) = ~(T v F) then there is no contradiction. L is not true. > > But *if* T is a truth predicate, then "L is not true" is formalized > by the statement ~T(L). > > >The argument usually goes "but that is what L says." But L does not > >say anything. > > It says "L is not true". > > So your proposed resolution is complete nonsense. It contains the string "L is not true", but it does not "say" that L is not true because it is meaningless. Some prefer to say that it does not express any proposition. Here is some reading for you. http://www.columbia.edu/~hg17/gaifman6.pdf
From: Newberry on 28 Mar 2010 01:16 On Mar 27, 11:10 am, Alan Smaill <sma...(a)SPAMinf.ed.ac.uk> wrote: > Nam Nguyen <namducngu...(a)shaw.ca> writes: > > Daryl McCullough wrote: > >> Nam Nguyen says... > >>> Daryl McCullough wrote: > > >>>> [G(PA)] is a *relative* truth. It's true in the standard interpretation > >>>> of the language of PA. > >>> So you've agreed "G(PA) can be arithmetically false"? > > >> It is false in nonstandard models of PA. > > > Why don't we make it more precise. When we say F, a formula written > > in the language of arithmetic, is true or false _by default_ we > > mean it's being arithmetically true or false: i.e. true or false > > in the natural numbers. So we're *not* talking about F is being > > true/false in any general kind of models here. > > You haven't (and can't) give me an effective way to use > this definition to decide truth or falsity in the natural numbers. But I can. In a system with gaps Tarski's theorem does not apply. We can then simply equate truth with provability. > > The point is Alan said he wouldn't know what an absolute truth > > of G(PA) would mean > > and I've implicitly defined it for him, and > > here is the explicit version: > > > There's _no other_ context in which the meta statement > > "G(PA) is arithmetically true in the natural number" would > > be false. > > I'm not obliged to accept any particular definition of yours. > > FWIW you can look at Bourbaki's account of Goedel's incompleteness > theorem to note that they studiously avoid saying that the goedel > sentence is true (arithaally, absolutely, or in any other way). > > > The question I was hoping you'd answer one way or another is > > whether or not there's a context in which the meta statement: > > > "G(PA) is arithmetically true in the natural number" > > > would be _false_ ? > > > If your answer is "yes", then the [arithmetically-in-the-natural- > > number] truth of G(PA) is a relative notion. Otherwise it's an > > absolute notion. > > Why should I believe the only answers are no or yes? > Your realist assumptions are showing. > > > Which answer would you have? And perhaps why? > > you need a bit more Zen. > > -- > Alan Smaill- Hide quoted text - > > - Show quoted text -
From: Daryl McCullough on 28 Mar 2010 07:37 Newberry says... > >On Mar 27, 4:56=A0am, stevendaryl3...(a)yahoo.com (Daryl McCullough) >wrote: >> Newberry says... >> >> >L: ~T(L) >> >> >If v(L) =3D ~(T v F) then there is no contradiction. L is not true. >> >> But *if* T is a truth predicate, then "L is not true" is formalized >> by the statement ~T(L). >> >> >The argument usually goes "but that is what L says." But L does not >> >say anything. >> >> It says "L is not true". >> >> So your proposed resolution is complete nonsense. > >It contains the string "L is not true", but it does not "say" that L >is not true That's completely silly. -- Daryl McCullough Ithaca, NY
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Pages: 106 107 108 109 110 111 112 113 114 115 116 117 118 119 120 121 122 123 124 125 126 Prev: geometry precisely defining ellipsis and how infinity is in the midsection #427 Correcting Math Next: Accounting for Governmental and Nonprofit Entities, 15th Edition Earl Wilson McGraw Hill Test bank is available at affordable prices. Email me at allsolutionmanuals11[at]gmail.com if you need to buy this. All emails will be answered ASAP. |