From: Phil Bouchard on 15 Dec 2009 20:12 Bill Snyder wrote: > > I may be lazy, but there's nothing to deny or fear. I asked you > for evidence; all you had was BS. Given I have proven multiple times GR is wrong then wormholes and an infinite number of Universes must also be wrong. Regardless FR proved its experimental evidence with the bending of light and consequently GR can be silently dismissed.
From: Nightcrawler on 15 Dec 2009 20:35 On 12/15/2009 7:12 PM, Phil Bouchard wrote: > Given I have proven multiple times GR is wrong then wormholes and an > infinite number of Universes must also be wrong. The only thing you have proven is that, when shewed, you hump the leg harder. ^^ shooed (both words are interchangeable in this context)
From: Sam Wormley on 15 Dec 2009 20:50 On 12/15/09 6:51 PM, Phil Bouchard wrote: > Greg Neill wrote: >> >> Okay, a square has side length 1. What is the length of the >> diagonal. Use spherical coordinates if you wish. Show >> us the answer and how you calculated it. > > If the input is: > rho = sqrt(1^2 + 1^2 + 1^2) > rho = 1.73 Phil confuses squares and cubes.... are we surprised? > > phi = acos(z / rho) > phi = 54.74 > > theta = atan2(1, 1) > theta = 0.79 > > Then the length of the diagonal will be: > 1.73
From: Greg Neill on 15 Dec 2009 20:55 Phil Bouchard wrote: > Greg Neill wrote: >> >> Okay, a square has side length 1. What is the length of the >> diagonal. Use spherical coordinates if you wish. Show >> us the answer and how you calculated it. > > If the input is: > rho = sqrt(1^2 + 1^2 + 1^2) > rho = 1.73 Why is that the input? Input to what? That's not input, it's operations. You haven't explained what you're doing here. Are the 1's supposed to represent something? Looks like the Cartesian coordinates of a vertex of a cube, not a square, but its hard to tell without you explicitly saying what you're doing. > > phi = acos(z / rho) > phi = 54.74 > > theta = atan2(1, 1) > theta = 0.79 > > Then the length of the diagonal will be: > 1.73 Sorry, you used a square root so it can't be right, can it Phil? Not according to your theory of the world. Also, if you thought that irrational numbers were scary, using trig functions lands you right smack in the land of transcendental numbers... Also, since when is the diagonal of a square of side length 1 not sqrt(2) ~~ 1.414 ? Wrong, wrong, wrong, in so very many ways.
From: Phil Bouchard on 15 Dec 2009 20:56
Sam Wormley wrote: > On 12/15/09 6:51 PM, Phil Bouchard wrote: >> >> If the input is: >> rho = sqrt(1^2 + 1^2 + 1^2) >> rho = 1.73 > > Phil confuses squares and cubes.... are we surprised? Those are the inputs Sam, not the function itself. |