From: mpc755 on
On Apr 6, 10:29 am, Tom Roberts <tjroberts...(a)sbcglobal.net> wrote:
> Tony M wrote:
> > Sue's example of electron-positron "annihilation" can be a bit
> > misleading, making one believe that mass gets converted to energy,
> > when that's not the case.
>
> Again this depends on the meanings of your words, including nuances. With
> standard meanings we do say "mass is converted into kinetic energy". See below.
>
> > The isolated system consisting of the
> > electron and positron has the same total energy and corresponding mass
> > before and after the "annihilation", except now instead of electron
> > and positron we have gamma photons (and maybe some other particles).
>
>         e+ e- annihilate from rest into 2 gammas >99% of the time; the
>         other final states consist of 4,6,8,... gammas, or (very rarely)
>         neutrino anti-neutrino pairs. For simplicity, I'll only discuss
>         annihilation at rest into gammas.
>
> Normally we apply the word "mass" to OBJECTS, not to collections of unbound
> objects. In the initial state the electron and the positron EACH have a mass,
> and the total mass is 1.022 MeV/c^2. In the final state the gammas each have
> zero mass, and the total mass is 0. The total energies of the initial and final
> states are the same. The total kinetic energy of the initial state is 0, but the
> total kinetic energy of the final state is 1.022 MeV. These units have c=1, and
> it is obvious that mass was indeed converted to kinetic energy.
>

Stating the 'total mass is 0' is misleading. The mass still exists. It
is in a different state. The mass associated with the electron and
positron has transitioned to aether.
From: Tom Roberts on
mpc755 wrote:
> On Apr 6, 10:29 am, Tom Roberts <tjroberts...(a)sbcglobal.net> wrote:
>> Normally we apply the word "mass" to OBJECTS, not to collections of unbound
>> objects. In the initial state the electron and the positron EACH have a mass,
>> and the total mass is 1.022 MeV/c^2. In the final state the gammas each have
>> zero mass, and the total mass is 0. The total energies of the initial and final
>> states are the same. The total kinetic energy of the initial state is 0, but the
>> total kinetic energy of the final state is 1.022 MeV. These units have c=1, and
>> it is obvious that mass was indeed converted to kinetic energy.
>>
>
> Stating the 'total mass is 0' is misleading. The mass still exists.

No. I am using these words with their standard meanings in modern physics. There
is no mass in that final state.


> [... attempt to invoke undefined concepts to "explain" this]


Tom Roberts
From: PD on
On Apr 6, 11:47 am, Tom Roberts <tjroberts...(a)sbcglobal.net> wrote:
> mpc755 wrote:
> > On Apr 6, 10:29 am, Tom Roberts <tjroberts...(a)sbcglobal.net> wrote:
> >> Normally we apply the word "mass" to OBJECTS, not to collections of unbound
> >> objects. In the initial state the electron and the positron EACH have a mass,
> >> and the total mass is 1.022 MeV/c^2. In the final state the gammas each have
> >> zero mass, and the total mass is 0. The total energies of the initial and final
> >> states are the same. The total kinetic energy of the initial state is 0, but the
> >> total kinetic energy of the final state is 1.022 MeV. These units have c=1, and
> >> it is obvious that mass was indeed converted to kinetic energy.
>
> > Stating the 'total mass is 0' is misleading. The mass still exists.
>
> No. I am using these words with their standard meanings in modern physics.. There
> is no mass in that final state.
>
>  > [... attempt to invoke undefined concepts to "explain" this]
>
> Tom Roberts

MPC says mass is conserved because he says so.
He also says the mass becomes invisible as mass and appears in some
other supposed substance. This occurrence is evidence, for him, of the
existence of the supposed substance.
MPC is a little tetched in the head, perhaps.
From: mpc755 on
On Apr 6, 12:47 pm, Tom Roberts <tjroberts...(a)sbcglobal.net> wrote:
> mpc755 wrote:
> > On Apr 6, 10:29 am, Tom Roberts <tjroberts...(a)sbcglobal.net> wrote:
> >> Normally we apply the word "mass" to OBJECTS, not to collections of unbound
> >> objects. In the initial state the electron and the positron EACH have a mass,
> >> and the total mass is 1.022 MeV/c^2. In the final state the gammas each have
> >> zero mass, and the total mass is 0. The total energies of the initial and final
> >> states are the same. The total kinetic energy of the initial state is 0, but the
> >> total kinetic energy of the final state is 1.022 MeV. These units have c=1, and
> >> it is obvious that mass was indeed converted to kinetic energy.
>
> > Stating the 'total mass is 0' is misleading. The mass still exists.
>
> No. I am using these words with their standard meanings in modern physics.. There
> is no mass in that final state.
>

Of course there is still the same amount of mass in that final state.
It doesn't disappear. It doesn't vanish. Saying "it is obvious that
mass was indeed converted to kinetic energy", is completely not
understanding the physics of nature. Mass does not convert to energy.
Matter transitions to aether. Matter expands in three dimensional
space as it transitions to aether. Matter increases in volume as it
transitions to aether. The physical effect this transition has on the
neighboring aether and matter is energy.

Aether and matter are different states of the same material.

Matter is compressed aether and aether is uncompressed matter.

'DOES THE INERTIA OF A BODY DEPEND UPON ITS ENERGY-CONTENT? By A.
EINSTEIN'
http://www.fourmilab.ch/etexts/einstein/E_mc2/e_mc2.pdf

"If a body gives off the energy L in the form of radiation, its mass
diminishes by L/c2."

The mass of the body does diminish, but the matter which no longer
exists as part of the body has not vanished. It still exists, as
aether. As the matter transitions to aether it expands in three
dimensions. The effect this transition has on the surrounding aether
and matter is energy.
From: mpc755 on
On Apr 6, 12:50 pm, PD <thedraperfam...(a)gmail.com> wrote:
> On Apr 6, 11:47 am, Tom Roberts <tjroberts...(a)sbcglobal.net> wrote:
>
>
>
> > mpc755 wrote:
> > > On Apr 6, 10:29 am, Tom Roberts <tjroberts...(a)sbcglobal.net> wrote:
> > >> Normally we apply the word "mass" to OBJECTS, not to collections of unbound
> > >> objects. In the initial state the electron and the positron EACH have a mass,
> > >> and the total mass is 1.022 MeV/c^2. In the final state the gammas each have
> > >> zero mass, and the total mass is 0. The total energies of the initial and final
> > >> states are the same. The total kinetic energy of the initial state is 0, but the
> > >> total kinetic energy of the final state is 1.022 MeV. These units have c=1, and
> > >> it is obvious that mass was indeed converted to kinetic energy.
>
> > > Stating the 'total mass is 0' is misleading. The mass still exists.
>
> > No. I am using these words with their standard meanings in modern physics. There
> > is no mass in that final state.
>
> >  > [... attempt to invoke undefined concepts to "explain" this]
>
> > Tom Roberts
>
> MPC says mass is conserved because he says so.
> He also says the mass becomes invisible as mass and appears in some
> other supposed substance. This occurrence is evidence, for him, of the
> existence of the supposed substance.
> MPC is a little tetched in the head, perhaps.

You must have missed this post:

Quote from poster stating science does not understand gravity:

'Therefore, in order to understand gravity, you must not try to
understand current theory as it has gotten us absolutely nowhere in
the past 100 years. That would be like trying to understand a flat
Earth theory. If you don't believe me, then just ask any real
scientist and the answer will still come back "we really don't
understand gravity" if they are honest.'

Your model can not explain how matter causes space to be unflat but
not move. Your model can not explain how matter causes space to be
unflat. Your model can not explain how an unflat space causes gravity
to physically exist.

You are making the point.

Gravity is pressure exerted by aether displaced by matter.

http://en.wikipedia.org/wiki/Louis_de_Broglie

"This research culminated in the de Broglie hypothesis stating that
any moving particle or object had an associated wave."

'Interpretation of quantum mechanics
by the double solution theory
Louis de BROGLIE'
http://www.ensmp.fr/aflb/AFLB-classiques/aflb124p001.pdf

"I called this relation, which determines the particle's motion in the
wave, "the guidance formula". It may easily be generalized to the case
of an external field acting on the particle."

"This result may be interpreted by noticing that, in the present
theory, the particle is defined as a very small region of the wave
where the amplitude is very large, and it therefore seems quite
natural that the internal motion rythm of the particle should always
be the same as that of the wave at the point where the particle is
located."

de Broglie's definition of wave-particle duality is of a physical wave
and a physical particle. The particle occupies a very small region of
the wave.

In AD, the external field is the aether. In a double slit experiment
the particle occupies a very small region of the wave and enters and
exits a single slit. The wave enters and exits the available slits.

For example, in the image on the right here:
http://en.wikipedia.org/wiki/Delayed_choice_quantum_eraser#The_experiment
There are waves propagating both the red and blue paths towards D0.
One of the downgraded photon 'particles' is traveling either the red
or blue path towards D0. The lens causes the waves to create
interference which alters the direction the particle travels. One set
of downgraded photons is creating one of the interference patterns at
D0 and the other set of downgraded photons is creating the other.

It's all very easy to understand once you realize 'delayed-choice',
'quantum eraser', and the future determining the past is simply
misinterpreting what is occurring in nature.

In the image on the right here:
http://en.wikipedia.org/wiki/Delayed_choice_quantum_eraser#The_experiment
When the downgraded photon pair are created, in order for there to be
conservation of momentum, the original photons momentum is maintained.
This means the downgraded photon pair have opposite angular momentums.
We will describe one of the photons as being the 'up' photon and the
other photon as being the 'down' photon. One of the downgraded photons
travels either the red or blue path towards D0 and the other photon
travels either the red or blue path towards the prism.

There are physical waves in the aether propagating both the red and
blue paths. The aether waves propagating towards D0 interact with the
lens and create interference prior to reaching D0. The aether waves
create interference which alters the direction the photon travels
prior to reaching D0. There are actually two interference patterns
being created at D0. One associated with the 'up' photons when they
arrive at D0 and the other interference pattern associated with the
'down' photons when they arrive at D0.

Both 'up' and 'down' photons are reflected by BSa and arrive at D3.
Since there is a single path towards D3 there is nothing for the wave
in the aether to interfere with and there is no interference pattern
and since it is not determined if it is an 'up' or 'down' photon being
detected at D3 there is no way to distinguish between the photons
arriving at D0 which interference pattern each photon belongs to. The
same for photons reflected by BSb and arrive at D4.

Photons which pass through BSa and are reflected by BSc and arrive at
D1 are either 'up' or 'down' photons but not both. If 'up' photons
arrive at D1 then 'down' photons arrive at D2. The opposite occurs for
photons which pass through BSb. Photons which pass through BSa and
pass through BSb and arrive at D1 are all either 'up' or 'down'
photons. If all 'up' photons arrive at D1 then all 'down' photons
arrive at D2. Since the physical waves in the aether traveling both
the red and blue paths are combined prior to D1 and D2 the aether
waves create interference which alters the direction the photon
travels. Since all 'up' photons arrive at one of the detectors and all
'down' photons arrive at the other an interference pattern is created
which reflects back to the interference both sets of photons are
creating at D0.

Figures 3 and 4 here:
http://arxiv.org/PS_cache/quant-ph/pdf/9903/9903047v1.pdf
Show the interference pattern of the 'up' and 'down' photons. If you
were to combine the two images and add the peaks together and add the
valleys together you would have the interference pattern of the
original photon. This is evidence the downgraded photon pair maintain
the original photons momentum and have opposite angular momentums.

Nothing is erased. There is no delayed choice. Physical waves in the
aether are traveling both the red and blue paths and when the paths
are combined the waves create interference which alters the direction
the photon 'particle' travels.

Experiments which will provide evidence of Aether Displacement:

Experiment #1:

Instead of having a single beam splitter BSc have two beam splitters
BSca and BScb. Have the photons reflected by mirror Ma interact with
BSca and have the photons reflected by mirror Mb interact with BScb.
Do not combine the red and blue paths. Have additional detectors D1a,
D2a, D1b, and D2b. Have the photons reflected by and propagate through
BSca be detected at D1a and D2a. Have the photons reflected by and
propagate through BScb be detected at D1b and D2b. If you compare the
photons detected at D1a and D1b with the photons detected at D0, the
corresponding photons detected at D0 will form an interference
pattern. If you compare the photons detected at D2a and D2b with the
photons detected at D0, the corresponding photons detected at D0 will
form an interference pattern. What is occurring is all 'up' photons
are being detected at one pair of detectors, for example D1a and D1b,
and all 'down' photons are being detected at the other pair of
detectors, for example D2a and D2b. Interference patterns do not even
need to be created in order to 'go back' and determine the
interference patterns created at D0.

Experiment #2:

Alter the experiment. When the downgraded photon pair are created,
have each photon interact with its own double slit apparatus. Have
detectors at one of the exits for each double slit apparatus. When a
photon is detected at one of the exits, in AD, the photon's aether
wave still exists and is propagating along the path exiting the other
slit. When a photon is not detected at one of the exits, the photon
'particle' along with its associated aether wave exits the other slit.
Combine the path the aether wave the detected photon is propagating
along with the path of the other photon and its associated aether
wave. An interference pattern will still be created. This shows the
aether wave of a detected photon still exists and is able to create
interference with the aether wave of another photon, altering the
direction the photon 'particle' travels.

Your inability to physically explain the following is evidence you
feign hypothesis:

- The future determining the past
- Virtual particles which exist out of nothing
- Conservation of momentum does not apply to a downgraded photon pair
- A C-60 molecule can enter, travel through, and exit multiple slits
simultaneously without requiring energy, releasing energy, or having
a change in momentum.
- Matter causes physical space to be 'unflat' but not move

The following are the most correct physical explanations to date:

- A C-60 molecule enters and exits a single slit while the associate
aether displacement wave enters and exits available slits
- The aether displaced by the matter which are the plates extends
past the other plate. The pressure exerted by the aether displaced
by the plates forces the plates together
- Conservation of momentum does apply to a downgraded photon pair.
When a photon is detected its wave collapses which determines its
spin. In order for the original photons momentum to be conserved,
the downgraded photon pair have opposite angular momentums.
- A C-60 molecule enters and exits a single slit while the associate
aether displacement wave enters and exits available slits
- Physical space is displaced by matter. Aether is displaced by
matter.