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An exact simplification challenge - 95 (EllipticF/Pi)
Hello, (-1)^(1/4)*( EllipticF ((-1)^(3/4), I) - 2*EllipticPi((-1)^(3/4),-I,I) ) ? Cheers, Vladimir Bondarenko Co-founder, CEO, Mathematical Director http://www.cybertester.com/ Cyber Tester Ltd. ---------------------------------------------------------------- ... 17 Jul 2010 04:28
Garmin nüvi 265W/265WT - Incredible Deal!
Garmin nüvi 265W/265WT 4.3-Inch Widescreen Bluetooth Portable GPS Navigator with Traffic http://astore.amazon.com/agsdirect-20/detail/B001ELJ9QK ... 16 Jul 2010 22:03
What is the difference between a value judgment and a fact (descriptionvs prescription)
Daniel T. wrote: Immortalista <extropy1(a)hotmail.com> wrote: I see many people try and disguise a value judgment as some sort of fact or just a value free description. How can one tell when someone is explaining some facts or just trying you to get interested in what he or she likes? You know, how... 17 Jul 2010 10:53
Question about discrete logarithm problem.
I am interested in solutions to the congruency (2^m)p = +-1 (mod q) where p and q are known and m is unknown. I'm not so much interested in finding the value of m as I am in knowing whether such an m exists. Is there a fast way of doing this, or is it as hard as the general discrete logarithm problem? Thanks in advance... 21 Jul 2010 12:28
portrait of infinity in Old Math #687 Correcting Math
Archimedes Plutonium wrote: Archimedes Plutonium wrote: Alright, so I have a method, now all I need are conjectures waited to be conquered after I sharpen my sword. So let me recap how the method works. I use Indirect Euclid Infinitude of Primes which retrieves two new primes not on... 16 Jul 2010 17:41
Galois Algebra Principle used to prove Goldbach Conjecture #686: Correcting Math
As far as I know, it has no name, so I am going to give it a name of the Galois Algebra Principle. Galois Algebra was discovered to fight the quintic problem in the 1800s. Now, I am using it to conquer the Goldbach Conjecture and also to show that Fermat's Last Theorem FLT is false unless a boundary between finit... 16 Jul 2010 16:35
Mathematica 7 does not know that Sin[2z] = 2 Sin[z] Cos[z]
It calculates Integrate[1/(Sin[2 z]/2)^193, z] but returns Integrate[1/(Sin[z] Cos[z])^193, z] unevaluated. Cheers, Vladimir Bondarenko Co-founder, CEO, Mathematical Director http://www.cybertester.com/ Cyber Tester Ltd. ---------------------------------------------- "We must unders... 16 Jul 2010 15:28
Mathematica 7 vs Rubi: Tan[z]/Sqrt[1+Tan[z]^4]
Any comments? f = Tan[z]/Sqrt[1+Tan[z]^4]; Timing[ByteCount[Integrate[f, z]]] {30.078, 1071488} Timing[ByteCount[Int[f, z]]] {0.125, 1952} ~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~ Int[Tan[z]/Sqrt[1 + Tan[z]^4], z] -> -(ArcSinh[(-2 + 4*Sin[z]^2)/2]*Sqrt[1 - 2*Sin[z]^2 + 2*Sin[z]^4])/ (2*Sqrt[2]... 19 Jul 2010 16:53
A really stupid question (calculus)
This question is really stupid. We have got an integral (where xa,xb,c etc. are constants; I use a pseudo-Mathematica notation for the clarity) I = Integrate[Exp[-c x] f[x], {x, xa, xb}] we want to obtain the form I = g * Integrate[Exp[-t] F[t], {t, ta, tb}] Obviously, t == c x dt == c dx ta =... 18 Jul 2010 10:32
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